interpolation

interpolation with matrices in R

徘徊边缘 提交于 2021-02-10 18:53:58
问题 I want to use linear interpolation to create a large matrix from 2 smaller matrices. I can do this using a function like this: mat1 <- matrix(rep(20, 4), ncol = 2) mat2 <- matrix(seq(21, 24, 1), ncol = 2) mat3 <- matrix(c(18, 27, 25, 12), ncol = 2) num.days <- c(31, 29) interpolate <- function(initial, final, n){ data.list <- list() for (i in 1:(n - 1)){ step1 <- (final - initial) / n step2 <- step1 * i data.list[[1]] <- initial data.list[[i+1]] <- round(step2 + initial, 2) } newmat = do.call

interpolation with matrices in R

三世轮回 提交于 2021-02-10 18:53:44
问题 I want to use linear interpolation to create a large matrix from 2 smaller matrices. I can do this using a function like this: mat1 <- matrix(rep(20, 4), ncol = 2) mat2 <- matrix(seq(21, 24, 1), ncol = 2) mat3 <- matrix(c(18, 27, 25, 12), ncol = 2) num.days <- c(31, 29) interpolate <- function(initial, final, n){ data.list <- list() for (i in 1:(n - 1)){ step1 <- (final - initial) / n step2 <- step1 * i data.list[[1]] <- initial data.list[[i+1]] <- round(step2 + initial, 2) } newmat = do.call

interpolation with matrices in R

别来无恙 提交于 2021-02-10 18:53:36
问题 I want to use linear interpolation to create a large matrix from 2 smaller matrices. I can do this using a function like this: mat1 <- matrix(rep(20, 4), ncol = 2) mat2 <- matrix(seq(21, 24, 1), ncol = 2) mat3 <- matrix(c(18, 27, 25, 12), ncol = 2) num.days <- c(31, 29) interpolate <- function(initial, final, n){ data.list <- list() for (i in 1:(n - 1)){ step1 <- (final - initial) / n step2 <- step1 * i data.list[[1]] <- initial data.list[[i+1]] <- round(step2 + initial, 2) } newmat = do.call

Downsampling signal from 100.21 Hz to 8 Hz (non-integer decimation factor)

痴心易碎 提交于 2021-02-09 09:36:32
问题 I have found the following method to downsample a signal in python. I would like to use this method with a sample_rate of 100.21 but I think currently it only works for integer powers of two. Is there a possibility to downsample my signal with frequency 100.21 Hz to 8 Hz? def interpolateDataTo8Hz(data,sample_rate,startTime): # Downsample idx_range = range(0,len(data)) data = data.iloc[idx_range[0::int(sample_rate)/8]] # Set the index to be 8Hz data.index = pd.DatetimeIndex(start=startTime

perl6 How to use junction inside regex interpolation?

血红的双手。 提交于 2021-02-08 13:14:41
问题 Sometimes I have a long list and I would like to check whether a string matches anything in the list. I am trying to interpolate a junction inside a regex. They are all errors. say "12345" ~~ m/ <{ (2,3,4).any }> / Cannot resolve caller MAKE_REGEX(Int, Bool, Bool, Int, PseudoStash); none of these signatures match: say "12345" ~~ m/ $( (2,3,4).any ) / This type cannot unbox to a native string: P6opaque, Junction Does this error message mean that junctions cannot be used inside regex

perl6 How to use junction inside regex interpolation?

南笙酒味 提交于 2021-02-08 13:14:28
问题 Sometimes I have a long list and I would like to check whether a string matches anything in the list. I am trying to interpolate a junction inside a regex. They are all errors. say "12345" ~~ m/ <{ (2,3,4).any }> / Cannot resolve caller MAKE_REGEX(Int, Bool, Bool, Int, PseudoStash); none of these signatures match: say "12345" ~~ m/ $( (2,3,4).any ) / This type cannot unbox to a native string: P6opaque, Junction Does this error message mean that junctions cannot be used inside regex

perl6 How to use junction inside regex interpolation?

拟墨画扇 提交于 2021-02-08 13:14:17
问题 Sometimes I have a long list and I would like to check whether a string matches anything in the list. I am trying to interpolate a junction inside a regex. They are all errors. say "12345" ~~ m/ <{ (2,3,4).any }> / Cannot resolve caller MAKE_REGEX(Int, Bool, Bool, Int, PseudoStash); none of these signatures match: say "12345" ~~ m/ $( (2,3,4).any ) / This type cannot unbox to a native string: P6opaque, Junction Does this error message mean that junctions cannot be used inside regex

One end clamped and other end free cubic spline using scipy.interpolate.splprep and splev

旧时模样 提交于 2021-02-08 07:25:44
问题 I have the following data: x_old = [ 0.00000000e+00, -5.96880765e-24, -8.04361605e-23, -2.11167774e-22, -2.30386081e-22, -7.86854147e-23, 1.17548440e-22, 1.93009272e-22, 1.49906866e-22, 9.66877465e-23, 1.48495705e-23] y_old = [ 0. , 0.03711505, 0.03780602, 0.02524459, 0.01349815, 0.00964215, 0.00972842, 0.0168793 , 0.02577024, 0.02761626, 0.02141961] z_old = [ 0. , 0.29834302, 0.59805918, 0.89773519, 1.19755092, 1.49749325, 1.79750314, 2.09741402, 2.39727031, 2.69726787, 2.99719479] I want to

One end clamped and other end free cubic spline using scipy.interpolate.splprep and splev

会有一股神秘感。 提交于 2021-02-08 07:25:30
问题 I have the following data: x_old = [ 0.00000000e+00, -5.96880765e-24, -8.04361605e-23, -2.11167774e-22, -2.30386081e-22, -7.86854147e-23, 1.17548440e-22, 1.93009272e-22, 1.49906866e-22, 9.66877465e-23, 1.48495705e-23] y_old = [ 0. , 0.03711505, 0.03780602, 0.02524459, 0.01349815, 0.00964215, 0.00972842, 0.0168793 , 0.02577024, 0.02761626, 0.02141961] z_old = [ 0. , 0.29834302, 0.59805918, 0.89773519, 1.19755092, 1.49749325, 1.79750314, 2.09741402, 2.39727031, 2.69726787, 2.99719479] I want to

How to interpolate N points that do not describe a function

隐身守侯 提交于 2021-02-08 02:01:59
问题 Suppose i have n points, also suppose that this points have an order, and not necessary this points make a function. I'm wondering how to interpolate them if the points do not describe a function? For example this will be the original points: And i hope this result: Note that only using splines do not works because the points do not make a function, and also using Bezier curves do not works because them do not interpolate the points (only pass near of them). How can i do for get this? Is