integer-overflow

Do you know how to simulate a 32-bit integer overflow in Oracle PL/SQL. For instance, 2147483647 + 1 = -2147483648 or -2147483648 - 1 = 212147483647 I tried PLS_INTEGER, but it throws an overflow exception. Perhaps you could trap the overflow exception, as in the following: DECLARE n PLS_INTEGER; addend PLS_INTEGER; NUMERIC_OVERFLOW EXCEPTION; PRAGMA EXCEPTION_INIT(NUMERIC_OVERFLOW, -1426); BEGIN n := 2147483642; addend := 6; BEGIN n := n + addend; EXCEPTION WHEN NUMERIC_OVERFLOW THEN DBMS_OUTPUT.PUT_LINE('OVERFLOW!'); n := -2147483647 + (-2147483647 + n + addend - 1); WHEN OTHERS THEN DBMS

I am learning computer arithmetic. The book I use(Patterson and Hennessey) lists the below question. Write mips code to conduct double precision integer subtraction for 64-bit data. Assume the first operand to be in registers $t4(hi) and $t5(lo), second in $t6(hi) and $t7(lo). My solution to the answer is sub $t3, $t5, $t7 # Subtract lo parts of operands. t3 = t5 - t7 sltu $t2, $t5, $t7 # If the lo part of the 1st operand is less than the 2nd, # it means a borrow must be made from the hi part add $t6, $t6, $t2 # Simulate the borrow of the msb-of-low from lsb-of-high sub $t2, $t4, $t6 #

This question already has answers here : Closed 6 years ago . Possible Duplicate: Best way to detect integer overflow in C/C++ I was asked this question in an interview : "Convert a string representation of a number into an integer". But if the number exceeds the max value that can be stored in a 32 bit integer, it must throw an error. My question is how can we check if a number overflows a 32-bit unsigned int ? sampson-chen (I looked at the possible duplicate to this question and I'm uncertain how useful that reading will be, since in an interview context, you'd be expected describe the

I wrote a method to convert a given number from days to milliseconds: private long expireTimeInMilliseconds; ... public void setExpireTimeInDays(int expireTimeInDays) { expireTimeInMilliseconds = expireTimeInDays * 24 * 60 * 60 * 1000; } I had a hard time to figure out what I did wrong. Now my question: Is that error so obvious ? The corrected method: private long expireTimeInMilliseconds; ... public void setExpireTimeInDays(int expireTimeInDays) { expireTimeInMilliseconds = ((long) expireTimeInDays) * 24 * 60 * 60 * 1000; } If I don't convert the integer to long before calculating, I get a

I have an 8-character string representing a hexadecimal number and I need to convert it to an int . This conversion has to preserve the bit pattern for strings "80000000" and higher, i.e., those numbers should come out negative. Unfortunately, the naive solution: int hex_str_to_int(const string hexStr) { stringstream strm; strm << hex << hexStr; unsigned int val = 0; strm >> val; return static_cast<int>(val); } doesn't work for my compiler if val > MAX_INT (the returned value is 0). Changing the type of val to int also results in a 0 for the larger numbers. I've tried several different