instantiation

问题 This question is related to my previous question and Bill's response there. I have a class named StrucData in subfile.py class StrucData: def __init__(self, name): self.name=name def loadData(self, size=1, cost=1): self.size=size self.cost=cost return self In the main file I: call the subfile, create a list of data names loop through the list to instantiate the objects; and load data using 'loadData' method for each object (I'm using the same 'size' and 'cost' to make this example easy.) in

问题 Say I have this program #include <iostream> using namespace std; template<typename T> class A { public: void foo() { cout << "Inside foo" << endl; } void bar() { cout << "Inside bar" << endl; } }; int main() { A<int> a; a.foo(); return 0; } Both g++ and clang++ only generate code for A<int>::foo() , but not for A<int>::bar() . This is annoying when you want to call this function while debugging. (e.g. vector<T>::at() ). Is there some flag or other method by which you can force the generation

问题 Say I have this program #include <iostream> using namespace std; template<typename T> class A { public: void foo() { cout << "Inside foo" << endl; } void bar() { cout << "Inside bar" << endl; } }; int main() { A<int> a; a.foo(); return 0; } Both g++ and clang++ only generate code for A<int>::foo() , but not for A<int>::bar() . This is annoying when you want to call this function while debugging. (e.g. vector<T>::at() ). Is there some flag or other method by which you can force the generation

问题 Say I have this program #include <iostream> using namespace std; template<typename T> class A { public: void foo() { cout << "Inside foo" << endl; } void bar() { cout << "Inside bar" << endl; } }; int main() { A<int> a; a.foo(); return 0; } Both g++ and clang++ only generate code for A<int>::foo() , but not for A<int>::bar() . This is annoying when you want to call this function while debugging. (e.g. vector<T>::at() ). Is there some flag or other method by which you can force the generation

问题 Say I have this program #include <iostream> using namespace std; template<typename T> class A { public: void foo() { cout << "Inside foo" << endl; } void bar() { cout << "Inside bar" << endl; } }; int main() { A<int> a; a.foo(); return 0; } Both g++ and clang++ only generate code for A<int>::foo() , but not for A<int>::bar() . This is annoying when you want to call this function while debugging. (e.g. vector<T>::at() ). Is there some flag or other method by which you can force the generation

问题 [dcl.spec.auto]/14 states [ emphasis mine]: An explicit instantiation declaration does not cause the instantiation of an entity declared using a placeholder type , but it also does not prevent that entity from being instantiated as needed to determine its type. [  Example: template <typename T> auto f(T t) { return t; } extern template auto f(int); // does not instantiate f<int> int (*p)(int) = f; // instantiates f<int> to determine its return type, but an explicit // instantiation definition

问题 [dcl.spec.auto]/14 states [ emphasis mine]: An explicit instantiation declaration does not cause the instantiation of an entity declared using a placeholder type , but it also does not prevent that entity from being instantiated as needed to determine its type. [  Example: template <typename T> auto f(T t) { return t; } extern template auto f(int); // does not instantiate f<int> int (*p)(int) = f; // instantiates f<int> to determine its return type, but an explicit // instantiation definition

问题 [dcl.spec.auto]/14 states [ emphasis mine]: An explicit instantiation declaration does not cause the instantiation of an entity declared using a placeholder type , but it also does not prevent that entity from being instantiated as needed to determine its type. [  Example: template <typename T> auto f(T t) { return t; } extern template auto f(int); // does not instantiate f<int> int (*p)(int) = f; // instantiates f<int> to determine its return type, but an explicit // instantiation definition

来源： https://stackoverflow.com/questions/22628943/how-do-i-force-a-specific-instantiation-of-a-templated-function-without-repeatin

来源： https://stackoverflow.com/questions/22628943/how-do-i-force-a-specific-instantiation-of-a-templated-function-without-repeatin