inline-method

If optimizations are enabled will the JIT always inline this method?

由 你说的曾经没有我的故事 提交于 2019-12-21 01:06:43
问题 I am not expecting a definite yes or no. Any knowledge you might have I will consider as an answer. private String CalculateCharge(Nullable<Decimal> bill, Nullable<Decimal> rate) { return ((bill ?? 0.0m) * (rate ?? 0.0m)).ToString("C"); } 回答1: Inlining is an implementation detail of the JIT, not of the C# compiler. From Eric Gunnerson's blog: The JIT uses a number of heuristics to decide whether a method should be in-lined. The following is a list of the more significant of those (note that

Inline member functions in C++

由 a 夏天 提交于 2019-12-18 19:12:32
问题 ISO C++ says that the inline definition of member function in C++ is the same as declaring it with inline. This means that the function will be defined in every compilation unit the member function is used. However, if the function call cannot be inlined for whatever reason, the function is to be instantiated "as usual". (http://msdn.microsoft.com/en-us/library/z8y1yy88%28VS.71%29.aspx) The problem I have with this definition is that it does not tell in which translation unit it would be

Can method inlining optimization cause race conditions?

由 ≡放荡痞女 提交于 2019-12-18 12:17:41
问题 As seen in this question: Raising C# events with an extension method - is it bad? I'm thinking of using this extension method to safely raise an event: public static void SafeRaise(this EventHandler handler, object sender, EventArgs e) { if (handler != null) handler(sender, e); } But Mike Rosenblum raise this concern in Jon Skeet's answer: You guys need to add the [MethodImpl(MethodImplOptions.NoInlining)] attribute to these extension methods or else your attempt to copy the delegate to a

C Inline Functions and Memory Use

由 ￣綄美尐妖づ 提交于 2019-12-06 02:25:11
问题 If I use inline functions, does the memory usage increase? 回答1: There are two kinds of memory usage that inline functions will affect: code size — in general, inlining code will increase how much memory is used to load your program. This is because there will be multiple copies of the generated code scattered around your program. However, this isn't always true -- if your inlined function was only used once, there's little change, and if the inlined function is very small, you could get a net

Inline member functions in C++

由 非 Y 不嫁゛ 提交于 2019-11-30 17:32:02
ISO C++ says that the inline definition of member function in C++ is the same as declaring it with inline. This means that the function will be defined in every compilation unit the member function is used. However, if the function call cannot be inlined for whatever reason, the function is to be instantiated "as usual". ( http://msdn.microsoft.com/en-us/library/z8y1yy88%28VS.71%29.aspx ) The problem I have with this definition is that it does not tell in which translation unit it would be instantiated. The problem I encountered is that when facing two object files in a single static library,

C++ template and inline

由 只愿长相守 提交于 2019-11-27 13:26:57
When I'm writing a simple (non-template) class, if the function implementation is provided "right in place", it's automatically treated as inline . class A { void InlinedFunction() { int a = 0; } // ^^^^ the same as 'inline void InlinedFunction' } What about this rule when talking about template-based classes? template <typename T> class B { void DontKnowFunction() { T a = 0; } // Will this function be treated as inline when the compiler // instantiates the template? }; Also, how is the inline rule applied to non-nested template functions, like template <typename T> void B::DontKnowFunction()

Why can't c# use inline anonymous lambdas or delegates? [duplicate]

由 隐身守侯 提交于 2019-11-27 06:59:09
This question already has an answer here: Why must a lambda expression be cast when supplied as a plain Delegate parameter 7 answers I hope I worded the title of my question appropriately. In c# I can use lambdas (as delegates), or the older delegate syntax to do this: Func<string> fnHello = () => "hello"; Console.WriteLine(fnHello()); Func<string> fnHello2 = delegate() { return "hello 2"; }; Console.WriteLine(fnHello2()); So why can't I "inline" the lambda or the delegate body, and avoid capturing it in a named variable (making it anonymous)? // Inline anonymous lambda not allowed Console

C++ template and inline

由 眉间皱痕 提交于 2019-11-26 18:17:06
问题 When I'm writing a simple (non-template) class, if the function implementation is provided "right in place", it's automatically treated as inline . class A { void InlinedFunction() { int a = 0; } // ^^^^ the same as 'inline void InlinedFunction' } What about this rule when talking about template-based classes? template <typename T> class B { void DontKnowFunction() { T a = 0; } // Will this function be treated as inline when the compiler // instantiates the template? }; Also, how is the

Inlining in Java

由 不羁的心 提交于 2019-11-26 15:26:45
In C++ I can declare a method "inline" and the compiler is likely to inline it. As far as I understand there is no such keyword in Java. Inlining is done if the JVM decides to do so? Can I influence this decision somehow? A couple of the other answers have suggested that only final methods can be inlined - this is not true, as HotSpot is smart enough to be able to inline non-final methods so long as they haven't been overridden yet . When a class is loaded which overrides the method, it can undo its optimisation. Obviously making the method final mean that's never required... Basically let the

Why can&#39;t c# use inline anonymous lambdas or delegates? [duplicate]

由 ▼魔方 西西 提交于 2019-11-26 12:59:21
问题 This question already has answers here : Why must a lambda expression be cast when supplied as a plain Delegate parameter (8 answers) Closed 6 years ago . I hope I worded the title of my question appropriately. In c# I can use lambdas (as delegates), or the older delegate syntax to do this: Func<string> fnHello = () => \"hello\"; Console.WriteLine(fnHello()); Func<string> fnHello2 = delegate() { return \"hello 2\"; }; Console.WriteLine(fnHello2()); So why can\'t I \"inline\" the lambda or the
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