How do I get the first n characters of a string without checking the size or going out of bounds?
问题 How do I get up to the first n characters of a string in Java without doing a size check first (inline is acceptable) or risking an IndexOutOfBoundsException ? 回答1: Here's a neat solution: String upToNCharacters = s.substring(0, Math.min(s.length(), n)); Opinion: while this solution is "neat", I think it is actually less readable than a solution that uses if / else in the obvious way. If the reader hasn't seen this trick, he/she has to think harder to understand the code. IMO, the code's