hql

来源： https://stackoverflow.com/questions/64665737/group-by-count-query-sql-to-hql

来源： https://stackoverflow.com/questions/64665737/group-by-count-query-sql-to-hql

来源： https://stackoverflow.com/questions/56843/looking-for-an-hql-builder-hibernate-query-language

来源： https://stackoverflow.com/questions/33362921/hibernate-formula-query-field-using-another-formula-field

问题 I am reading the book "Java Persistence with Hibernate, 2nd Edition". It takes an example of items sold to bidders like ebay. At the page 400, the author says The query select i from item i left join fetch i.bids b where b.amount > 20 is invalid. You can’t say, “Load the Item instances and initialize their bids collections, but only with Bid instances that have a certain amount.” I am not sure to quite understand. To my opinion it is valid, but it will renders only the items that have a bid

问题 I'm using Hibernate Query Language(HQL) with Oracle database in my Java spring MVC application. I have write an HQL update query in this way: String hql = "update " + MyModel.class.getName() + " e set e.field = " + value + " where ..." //Acquiring session ... Query query = session.createQuery(hql); int result = query.executeUpdate(); The executeUpdate() method returns number of updated rows. But I want to get a list of the ids of updated rows after executing the update query. Is there any way

问题 Caused by: org.hibernate.QueryException: Could not resolve requested type for CAST : INT [ SELECT SUBSTRING(referenceComptable , 8, 14) AS seqNum, SUBSTRING(referenceComptable, 4,7) AS yearCegid, SUBSTRING(referenceComptable, 1,3) AS journal FROM com.dso.model.comptabilite.cegid.EtapeJudiciaireLnkFactureActesHonoraires WHERE dateCegidGenerated BETWEEN :date AND :dateYearIntervalDate ORDER BY CAST(seqNum AS INT), CAST(yearCegid AS INT), CAST(journal AS INT) ASC ] HQL QUery: public

问题 in hql scripts we use "!sh echo ---new line---" for the same . Want to know the alternative for this in impala to print any line in impala scripts? 回答1: You can invoke the shell command line from impala scripts. As an example of how it works. script_impala.sql -- set a variable containing the of the game SET hivevar:game=Monopoly; -- return the list of the game SELECT list_price FROM fun.games WHERE name = '${hivevar:game}'; -- return the prices of the game ate game shops SELECT shop, price

问题 Considering the following "model": USER Long: PK String: firstName String: lastName USER_EXT Long: PK String: moreInfo Date: lastModified I'm trying to find/create the correct Hibernate mapping (using Annotations) such that, with an HQL query as simple as "from User", it would generate the following SQL: select firstName, moreInfo from USER, USER_EXT where user.pk = user_ext.pk I've tried everything, from using @Secondarytable to @OneToOne association, but I can't make it work. The best

问题 Considering the following "model": USER Long: PK String: firstName String: lastName USER_EXT Long: PK String: moreInfo Date: lastModified I'm trying to find/create the correct Hibernate mapping (using Annotations) such that, with an HQL query as simple as "from User", it would generate the following SQL: select firstName, moreInfo from USER, USER_EXT where user.pk = user_ext.pk I've tried everything, from using @Secondarytable to @OneToOne association, but I can't make it work. The best