hibernate-mapping

问题 Im trying to configure my entities but hibernate throws the following exception: org.hibernate.MappingException: Could not determine type for: com.sd.entity.SDUserProductAcess, at table: SDUser, for columns: [org.hibernate.mapping.Column(productAccess)] [PersistEngine] Failed to initialize persistence engine!java.lang.NullPointerException These are my Entities: @Entity @Inheritance(strategy = InheritanceType.JOINED) public class SDObject { @Id @GeneratedValue private long sdId; private String

问题 In Java, new BigDecimal("1.0") != new BigDecimal("1.00") i.e., scale matters. This is apparently not true for Hibernate/SQL Server, however. If I set the scale on a BigDecimal to a particular value, save the BigDecimal to the database via Hibernate and then re-inflate my object, I get back a BigDecimal with a different scale. For instance, a value of 1.00 is coming back as 1.000000, I assume because we're mapping BigDecimals to a column defined as NUMERIC(19,6) . I can't just define the

问题 i have a table Permission : id name desc what i am doing right now is to make a query that returns a permission object then put the values in the map programmatically 1- But i was wondering if it's possible to make an HQL (or native sql if not possible) to select the permission_id , permission_name and return them in a map. 2- is it possible to return map in one to many relationship instead of following list or set @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY) @JoinTable(name

问题 I wonder why this exception happens although it's assured by Hibernate get/query methods to retrieve objects that are already available inside the Hibernate session in case those objects are required repeatedly: org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: [x.y.z.MyObject#130062] at org.hibernate.engine.StatefulPersistenceContext.checkUniqueness(StatefulPersistenceContext.java:638) at org.hibernate.event.def

问题 Fellow developers, I'm finding it hard to get the sequence generation configured. I inherited a persistent class with the following id field definition: @Id @GeneratedValue(strategy= GenerationType.AUTO) private Long id; All of my classes inherit from this class. The main thing I want: I need to override the strategy of id generation to use HiLo. It has to be in the cfg.xml since it's the only place that I have control over. This thing looked promising: <property name="hibernate.id.new

问题 I am using hibernate 4.1.10.Final to insert data into database, but it throws the following exception, I have three tables, development and address . Development has an object of address in itself. INFO: HCANN000001: Hibernate Commons Annotations {4.0.1.Final} INFO: HHH000412: Hibernate Core {4.1.10.Final} INFO: HHH000206: hibernate.properties not found INFO: HHH000021: Bytecode provider name : javassist INFO: HHH000043: Configuring from resource: /hibernate.cfg.xml INFO: HHH000040:

问题 I need to have a friendship relationship. I have a friendship class with two primary keys that each is a Member class. I am receiving following exception: org.hibernate.MappingException: Foreign key (FK_8ynretl1yt1xe3gcvfytrvpq:Friendship [])) must have same number of columns as the referenced primary key (Member [username]) Friendship @Entity public class Friendship implements Serializable { /** * */ private static final long serialVersionUID = -1234656876554786549L; @Id @ManyToOne Member

问题 in postgres we can use the following construct to create a temporary table of type array of integers. For example the singleTestColumn below. Usually this is used during CTE. String sql_query = "SELECT ARRAY[]::INTEGER[] AS singleTestColumn"; How to properly map this column in hibernate native sql query. taking into account the custom integer array mapping described here https://vladmihalcea.com/how-to-map-java-and-sql-arrays-with-jpa-and-hibernate/#comment-26149 i.e. by that i mean the

问题 I am using Spring and Hibernate. NamedQuery: @NamedQueries({ @NamedQuery(name = "Contact.findByUserId", query = "select cntct.mobileNo,cntct.homeTown,cntct.city,cntct.state,cntct.country,mbr.firstName,mbr.lastName,usr.userName from Contact cntct,Member mbr,User usr where cntct.user = :user")}) @Entity @Table(name = "Contact") public class Contact { @Id @Column(name="CONTACT_ID") @GeneratedValue(strategy=GenerationType.AUTO) private long contactId; @Column(name="MOBILE_NUMBER", length=30)

问题 I am getting the below error. But i am unable to find what the error is. Caused by: java.lang.NullPointerException at org.hibernate.cfg.Configuration.processFkSecondPassInOrder(Configuration.java:1481) at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1419) at org.hibernate.cfg.Configuration.buildMappings(Configuration.java:1375) at org.springframework.orm.hibernate3.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:717) at org.springframework.orm