问题
I am using Spring and Hibernate.
NamedQuery:
@NamedQueries({ @NamedQuery(name = "Contact.findByUserId", query = "select cntct.mobileNo,cntct.homeTown,cntct.city,cntct.state,cntct.country,mbr.firstName,mbr.lastName,usr.userName from Contact cntct,Member mbr,User usr where cntct.user = :user")})
@Entity
@Table(name = "Contact")
public class Contact {
@Id
@Column(name="CONTACT_ID")
@GeneratedValue(strategy=GenerationType.AUTO)
private long contactId;
@Column(name="MOBILE_NUMBER", length=30)
private long mobileNo;
@Column(name="HOME_TOWN", length=30)
private String homeTown;
@Column(name="CITY_NAME", length=30)
private String city;
@Column(name="STATE_NAME", length=30)
private String state;
@Column(name="COUNTRY_NAME", length=30)
private String country;
The following code for firing the query and fetching the data.
public ContactView getContact(long userId) {
Session session=sessionFactory.openSession();
Query query=session.getNamedQuery("Contact.findByUserId");
query.setLong("user", userId);
List<?> list=query.list();
session.close();
return null;
}
The problem that I am facing is, how to map the list's data to any custom Bean?
Or is there any other viable means?
Thanks!!
回答1:
query.list();
Returns the query results as a List. If the query contains multiple results per row, the results are returned in an instance of Object[].
source: http://docs.jboss.org/hibernate/orm/3.2/api/org/hibernate/Query.html#list()
So, we need to modify our code in following way to get the intended result:
List<Object[]> list=query.list();
for(i=0;i<list.size();i++){
Object obj[]=list.get(i);
for(Object obj1:obj){
//set your beans by using appropriate setters
}
}
Other alternative:
Please use ResultTransformer in hibernate to map the resultset(of a complex select query) to a single entity class.
ProdEntity prod = (ProdEntity)session.createQuery("select e.productId as pId,e.price as pPrice from Product e where e.productId = :productId").setParameter("productId", 103).setResultTransformer(Transformers.aliasToBean(ProdEntity.class)).uniqueResult();
回答2:
Use generic DAO instead see for example http://yanuar7199.wordpress.com/2013/03/30/hibernate-generic-dao-for-generic-purpose/
Define mapping for One-To-Many e.g. List of contacts in UserEntity.
http://www.dzone.com/tutorials/java/hibernate/hibernate-example/hibernate-mapping-one-to-many-using-annotations-1.html
来源:https://stackoverflow.com/questions/21374550/fetching-data-from-multiple-tables-in-hibernate-and-storing-the-result-in-a-bean