gets

Is character array in C dynamic?

a 夏天 提交于 2019-12-31 04:42:06
问题 I have written a simple program in C. A program to input a String and display it along with the length. #include<stdio.h> int main() { char a[4]; printf("Enter the name : "); gets(a); printf("\nThe name enterd is : %s",a); printf("\nLength of string is : %d",strlen(a)); getch(); return 0; } The program do not contain warning or error. At run-time I entered the value " melwinsunny " as input. There was no error and the result displayed was : Enter the name : melwinsunny The name entered is :

Recovering from a broken TCP socket in Ruby when in gets()

╄→尐↘猪︶ㄣ 提交于 2019-12-30 06:26:49
问题 I'm reading lines of input on a TCP socket, similar to this: class Bla def getcmd @sock.gets unless @sock.closed? end def start srv = TCPServer.new(5000) @sock = srv.accept while ! @sock.closed? ans = getcmd end end end If the endpoint terminates the connection while getline() is running then gets() hangs. How can I work around this? Is it necessary to do non-blocking or timed I/O? 回答1: You can use select to see whether you can safely gets from the socket, see following implementation of a

How do the puts and gets functions work?

末鹿安然 提交于 2019-12-28 03:11:13
问题 main() { char name[20]; printf("enter your name\n"); scanf("%s",name); printf("%s",name); gets(name); puts(name); } input: Sampad Saha Output Sampad Saha Here puts only uses the input taken from gets() . as, if I omit this printf() the output would be Saha So here puts does not print anything given through scanf() . main() { char color[20]; printf("enter your name\n"); scanf("%s",color); puts(color); } But here puts() uses the input taken from scanf() also. 回答1: The problem here is, for an

What is going on with 'gets(stdin)' on the site coderbyte?

天涯浪子 提交于 2019-12-27 17:07:41
问题 Coderbyte is an online coding challenge site (I found it just 2 minutes ago). The first C++ challenge you are greeted with has a C++ skeleton you need to modify: #include <iostream> #include <string> using namespace std; int FirstFactorial(int num) { // Code goes here return num; } int main() { // Keep this function call here cout << FirstFactorial(gets(stdin)); return 0; } If you are little familiar with C++ the first thing * that pops in your eyes is: int FirstFactorial(int num); cout <<

rspec issue believed to be with gets.chomp call

浪子不回头ぞ 提交于 2019-12-25 04:13:13
问题 I am having trouble or am confused with an rspec error when running: rspec -fd game_spec (the above is only the beginning of a long eror message) When I run it without the -fd, it works... but it looks goofy... something is wrong. I start getting error messages when I use gets.chomp but I've looked at similar examples that use it. Does 'the_word' have to be set in initialize? Does gets.chomp or can it? I appreciate any help. Below is game file and its rspec so far. I do not want to change

Using “gets” for String input in C

陌路散爱 提交于 2019-12-25 02:22:38
问题 I have been trying to get a string input from a user using fgets but fgets does not wait for input so upon investagation I learned of the gets function which seems to be working fine. My questions are: 1. Why does gets work when I input more than 10 characters if I declared an array of only ten elements. Here is my code #include<stdio.h> int main(void){ char name[10]; printf("Please enter your name: "); gets(name); printf("\n"); printf("%s", name); return 0; } my input when testing:

C - fgets() - What if the string is longer?

亡梦爱人 提交于 2019-12-25 01:46:40
问题 Let's say i have a file containing a string of length 10 : abcdefghij And read my text file line by line using fgets() with a buffer of size 4. I will have to call fgets() in a loop to make sure the whole line is read. But, at say the first call, it will read the first 3 characters (buffer size -1) right ? Will it also append a null terminating character at the last position of my 4 char buffer even if the real end of my string wasn't reached, or will fill it with 4 characters and no null

gets() taking input without actually giving it any input?

左心房为你撑大大i 提交于 2019-12-24 04:26:28
问题 I'm fairly new to C so sorry if this is a stupid question but when I run the following code: #include <stdio.h> int main () { int i; int test[10]; char string[81]; for(i = 0; i < 10; i++){ scanf("%d", &test[i]); } for(i=0; i < 7; i++){ gets(string); printf("String was entered\n"); } } And enter any 10 digits, the line "string was entered" will be printed even though I didn't enter a string in the command window. Can anyone explain why? Is there any way to stop it happening? Thanks! 回答1: After

TCL gets command with kind of -nohang option?

孤者浪人 提交于 2019-12-24 03:17:02
问题 Here is a code which just implements an interactive TCL session with command prompt MyShell > . puts -nonewline stdout "MyShell > " flush stdout catch { eval [gets stdin] } got if { $got ne "" } { puts stderr $got } This code prompts MyShell > at the terminal and waits for the enter button to be hit; while it is not hit the code does nothing. This is what the gets command does. What I need, is some alternative to the gets command, say coolget . The coolget command should not wait for the

How to use “gets” function in C++ after previous input?

岁酱吖の 提交于 2019-12-22 14:53:11
问题 I tried to input data with gets() function, but whenever program execution get to the the lien with the gets , it ignores it. When I use gets() without previous data input, it runs properly. But when I use it after data input the problem happens. Here's the code where it is used after previous data input (so in execution I can't input data to string): int main() { char str[255]; int a = 0; cin >> a; if(a == 1) { gets(str); cout << "\n" << str << endl; } } How could I fix this? NB: the same