gawk

Looking to convert human readable timestamps to epoch/Unix time within a CSV file using GAWK in preparation for loading into a MySQL DB. Data Example: {null};2013-11-26;Text & Device;Location;/file/path/to/;Tuesday, November 26 12:17 PM;1;1385845647 Looking to take column 6, Tuesday, November 26 12:17 PM, and convert to epoch time for storage. All times shown will be in EST format. I realize AWK is the tool for this, but can't quite seem to structure the command. Currently have: cat FILE_IN.CSV | awk 'BEGIN {FS=OFS=";"}{$6=strftime("%s")} {print}' However this returns: {null};2013-11-26;Text &

I am trying to do pattern replacement using SED script but its not working properly sample_content.txt 288Y2RZDBPX1000000001dhana JP2F64EI1000000002d EU9V3IXI1000000003dfg1000000001dfdfds XATSSSSFOO4dhanaUXIBB7TF71000000004adf 10Q1W4ZEAV18LXNPSPGRTTIDHBN1000000005egw patterns.txt 1000000001 9000000003 1000000002 2000000001 1000000003 3000000001 1000000004 4000000001 1000000005 5000000001 Expected output 288Y2RZDBPX9000000003dhana JP2F64EI2000000001d EU9V3IXI3000000001dfg9000000003dfdfds XATSSSSFOO4dhanaUXIBB7TF74000000001adf 10Q1W4ZEAV18LXNPSPGRTTIDHBN5000000001egw I am able to do with single

This seems like it should be dirt simple, but the awk gensub/gsub/sub behavior has always been unclear to me, and now I just can't get it to do what the documentation says it should do (and what experience with a zillion other similar tools suggests should work). Specifically, I want to access "captured groups" from a regex in the replacement string. Here's what I think the awk syntax should be: awk '{ gsub(/a(b*)c/, "Here are bees: \1"); print; }' That should turn "abbbc" into "Here are bees: bbb". It does not, at least not for me in Ubunutu 9.04. Instead, the "\1" is rendered as a ^A; that

Is there a way to print all records separated by the OFS without typing out each column number. #Desired style of syntax, undesired result [kbrandt@glade: ~] echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-( "}; {print $0}' 1 2 3 4 #Desired result, undesired syntax [kbrandt@glade: ~] echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-) "}; {print $1,$2,$3,$4}' 1 :-) 2 :-) 3 :-) 4 This is a variation on the first style: echo "1 2 3 4" | gawk 'BEGIN { OFS=" :-( "}; {$1=$1; print $0}' Results: 1 :-( 2 :-( 3 :-( 4 Explanation: the $1=$1 is to rebuild the record, using the current OFS (you can also see http://www.gnu

I would like to have help or direction on a problem I have in awk. I have a tab-delimited file with more than 5 fields. I want to output the fields excluding the first 5 fields. Could you please tell how to write an awk script to accomplish this task? Best, jianfeng.mao Do Note the following kind comment: There are many fields in my files. Different lines have a different number of fields. The number of fields per line is not standard. I agree with matchew's suggestion to use cut : it's the right tool for this job. But if this is just going to become a part of a larger awk script, here's how

Suppose I have a log file mylog like this: [01/Oct/2015:16:12:56 +0200] error number 1 [01/Oct/2015:17:12:56 +0200] error number 2 [01/Oct/2015:18:07:56 +0200] error number 3 [01/Oct/2015:18:12:56 +0200] error number 4 [02/Oct/2015:16:12:56 +0200] error number 5 [10/Oct/2015:16:12:58 +0200] error number 6 [10/Oct/2015:16:13:00 +0200] error number 7 [01/Nov/2015:00:10:00 +0200] error number 8 [01/Nov/2015:01:02:00 +0200] error number 9 [01/Jan/2016:01:02:00 +0200] error number 10 And I want to find those lines that occur between 1 Oct at 18.00 and 1 Nov at 1.00. That is, the expected output