gawk

Can I use a field separator consisting of multiple characters? Like I want to separate words which contain quotes and commas between them viz. "School","College","City" So here I want to set my FS to be ",". But I am getting funny results when I define my FS like that. Here's a snippet of my code. awk -F\",\" ' { for(i=1;i<=NF;i++) { if($i~"[a-z0-9],[a-z0-9]") print $i } }' OFS=\",\" $* yes, FS could be multi-characters. see the below test with your example: kent$ echo '"School","College","City"'|awk -F'","|^"|"$' '{for(i=1;i<=NF;i++){if($i)print $i}}' School College City What's being talked

Here's my array (gawk script) : myArray["peter"] = 32 myArray["bob"] = 5 myArray["john"] = 463 myArray["jack"] = 11 After sort, I need the following result : bob 5 jack 11 peter 32 john 463 When i use "asort", indices are lost. How to sort by array value without losing indices ? (I need ordered indices based on their values) (I need to obtain this result with awk/gawk only, not shell script, perl, etc) If my post isn't clear enough, here is an other post explaining the same issue : http://www.experts-exchange.com/Programming/Languages/Scripting/Shell/Q_26626841.html ) Thanks in advance Update

This file has 3 fields. I wanted e.g. the first 2 fields in green, and the third in white (NB : black background), so I tried : awk '{print "\033[0;32m"$1"\033[0m", "\033[0;32m"$2"\033[0m", "\033[0;37m"$3"\033[0m"} }' chrono.txt and everything was green… How must I proceed (if it is possible) ? To get color output from awk, you can use this approach. function red(s) { printf "\033[1;31m" s "\033[0m " } function green(s) { printf "\033[1;32m" s "\033[0m " } function blue(s) { printf "\033[1;34m" s "\033[0m " } { print red($1), green($2), blue($3) } An alternative to using awk functions is

I have a very huge file in which I need to obtain every nth line and print it into a row. My data: 1 937 4.320194 2 667 4.913314 3 934 1.783326 4 940 -0.299312 5 939 2.309559 6 936 3.229496 7 611 -1.41808 8 608 -1.154019 9 606 2.159683 10 549 0.767828 I want my data to look like this: 1 937 4.320194 3 934 1.783326 5 939 2.309559 7 611 -1.41808 9 606 2.159683 This is of course an example, I want every 10th line for my huge data file. I tried this so far: NF == 6 { if(NR%10) {print;} } To print every second line, starting with the first: awk 'NR%2==1' file.txt To print every tenth line, starting

The awk manual indicates that both -v FS and -F are equivalent ways to set the field separator. The GNU Awk User’s Guide -> 4.5.4 Setting FS from the Command Line : FS can be set on the command line. You use the `-F' argument to do so. (...) The value used for the argument to `-F' is processed in exactly the same way as assignments to the built-in variable FS. However, I noticed that there is a difference if we set it to an empty string, it is not the same. Tested on my GNU Awk 4.1.1 . This works: $ awk -F, '{print $2}' <<< "a,b,c" b $ awk -v FS=, '{print $2}' <<< "a,b,c" b But this does not:

I want gawk to parse number using comma , as the decimal point character. So I set LC_NUMERIC to fr_FR.utf-8 but it does not work: echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk '{printf ("%.2f\n", $1 + 0) }' 123.00 The solution is to specify option --posix or export POSIXLY_CORRECT=1 but in this case the GNU awk extensions are not available, for example delete or the gensub function: echo 123,2 | LC_NUMERIC=fr_FR.utf-8 gawk --posix '{printf ("%.2f\n", $1 + 0) }' 123,20 Is it possible to have gawk parsing number with , as decimal point without specifying POSIX option? The option your are looking for