function-parameter

String in function parameter

若如初见. 提交于 2019-11-27 15:04:40
问题 int main() { char *x = "HelloWorld"; char y[] = "HelloWorld"; x[0] = 'Z'; //y[0] = 'M'; return 0; } In the above program, HelloWorld will be in read-only section(i.e string table). x will be pointing to that read-only section, so trying to modify that values will be undefined behavior. But y will be allocated in stack and HelloWorld will be copied to that memory. so modifying y will works fine. String literals: pointer vs. char array Here is my Question: In the following program, both char

Maximum number of parameters in function declaration

谁都会走 提交于 2019-11-27 11:48:44
I know that minimum number of parameters in function definition is zero, but what is the maximum number of parameters in function definition? I am asking the question just for the sake of knowledge and out of curiosity, not that I am going to write a real function. Yes, there are limits imposed by the implementation. Your answer is given in the bold text in the following excerpt from the C++ Standard. 1. C++ Language Annex B - Implementation quantities Because computers are finite, C + + implementations are inevitably limited in the size of the programs they can successfully process. Every

Determining the Parameter Types of an Undefined Function

心不动则不痛 提交于 2019-11-27 07:45:26
问题 I've recently learned that I cannot: Take the address of an undefined function Take the address of a templatized function with a type it would fail to compile for But I've also recently learned that I can call decltype to get the return type of said function So an undefined function: int foo(char, short); I'd like to know if there's a way that I can match the parameter types to the types in a tuple . This is obviously a meta programming question. What I'm really shooting for is something like

How to deal with name/value pairs of function arguments in MATLAB

喜欢而已 提交于 2019-11-26 23:31:40
I have a function that takes optional arguments as name/value pairs. function example(varargin) % Lots of set up stuff vargs = varargin; nargs = length(vargs); names = vargs(1:2:nargs); values = vargs(2:2:nargs); validnames = {'foo', 'bar', 'baz'}; for name = names validatestring(name{:}, validnames); end % Do something ... foo = strmatch('foo', names); disp(values(foo)) end example('foo', 1:10, 'bar', 'qwerty') It seems that there is a lot of effort involved in extracting the appropriate values (and it still isn't particularly robust again badly specified inputs). Is there a better way of

Why use an asterisk “[*]” instead of an integer for a VLA array parameter of a function?

梦想的初衷 提交于 2019-11-26 22:13:17
When using variable-Length Array as parameter in function int sum(int n, int a[n]); it is easy to understand first parameter( n ) specifies the length of the second parameter( a ). But encountered with another prototype used for VLAs as parameter int sum(int n, int a[*]); is really difficult to understand why * is used instead of n inside [] ? The [*] syntax is intended to be used when declaring function prototypes . The key detail here is that in function prototypes you are not required to name your parameters, you just have to specify the type of each parameter. In your example, if you leave

PHP: variable-length argument list by reference?

╄→гoц情女王★ 提交于 2019-11-26 21:08:48
问题 Is it possible to create a PHP function that takes a variable number of parameters all of them by reference? It doesn't help me a function that receives by reference an array of values nor a function that takes its arguments wrapped in an object because I'm working on function composition and argument binding. Don't think about call-time pass-by-reference either. That thing shouldn't even exist. 回答1: PHP 5.6 introduced new variadic syntax which supports pass-by-reference. (thanks @outis for

Maximum number of parameters in function declaration

做~自己de王妃 提交于 2019-11-26 18:03:57
问题 I know that minimum number of parameters in function definition is zero, but what is the maximum number of parameters in function definition? I am asking the question just for the sake of knowledge and out of curiosity, not that I am going to write a real function. 回答1: Yes, there are limits imposed by the implementation. Your answer is given in the bold text in the following excerpt from the C++ Standard. 1. C++ Language Annex B - Implementation quantities Because computers are finite, C + +

Python - use list as function parameters

回眸只為那壹抹淺笑 提交于 2019-11-26 11:43:49
How can I use a Python list (e.g. params = ['a',3.4,None] ) as parameters to a function, e.g.: def some_func(a_char,a_float,a_something): # do stuff You can do this using the splat operator: some_func(*params) This causes the function to receive each list item as a separate parameter. There's a description here: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists This has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example. def some_func(a_char, a_float, a_something):

Why use an asterisk “[*]” instead of an integer for a VLA array parameter of a function?

a 夏天 提交于 2019-11-26 08:16:00
问题 When using variable-Length Array as parameter in function int sum(int n, int a[n]); it is easy to understand first parameter( n ) specifies the length of the second parameter( a ). But encountered with another prototype used for VLAs as parameter int sum(int n, int a[*]); is really difficult to understand why * is used instead of n inside [] ? 回答1: The [*] syntax is intended to be used when declaring function prototypes . The key detail here is that in function prototypes you are not required

Skipping optional function parameters in JavaScript

天涯浪子 提交于 2019-11-26 05:58:51
问题 Could you please point me to the nice way of skipping optional parameters in JavaScript. For example, I want to throw away all opt_ parameters here: goog.net.XhrIo.send(url, opt_callback, opt_method, opt_content, {\'Cache-Control\': \'no-cache\'}, opt_timeoutInterval) 回答1: Solution: goog.net.XhrIo.send(url, undefined, undefined, undefined, {'Cache-Control': 'no-cache'}) You should use undefined instead of optional parameter you want to skip, because this 100% simulates the default value for