fully-qualified-naming

Is fully qualified naming vs the using directive simply a matter of opinion?

ぃ、小莉子 提交于 2020-01-03 12:30:52
问题 I find now that I work in a mostly solo environment that I actually type fully qualified methods calls more and more, instead of make use of the using directive. Previously, I just stayed consistent with the most prominent coding practice on the team. Personally, I find it easier to read verbose code at a glance, I type fast especially with autocompletion and I find myself using Google more often as my source of documentation, which a fully qualified name returns a much narrower results set.

Is fully qualified naming vs the using directive simply a matter of opinion?

元气小坏坏 提交于 2020-01-03 12:30:42
问题 I find now that I work in a mostly solo environment that I actually type fully qualified methods calls more and more, instead of make use of the using directive. Previously, I just stayed consistent with the most prominent coding practice on the team. Personally, I find it easier to read verbose code at a glance, I type fast especially with autocompletion and I find myself using Google more often as my source of documentation, which a fully qualified name returns a much narrower results set.

Fully-qualified urls in HTTP Location header. Why it is important?

心不动则不痛 提交于 2019-12-24 01:23:46
问题 So I've got some warnings from Fiddler that I have bad urls in HTTP Location header and they are should be fully-qualified. Why it's so important and what issues that can lead to? 回答1: The old standard for HTTP/1.1 (RFC 2616 § 14.30) required that Location be an absolute URI. Implementation experience showed that this was not important, and many implementations allowed relative URIs in Location , so the current standard (RFC 7231 § 7.1.2) allows relative URIs. 来源: https://stackoverflow.com

How does the automatic full qualification of class names work, in Python? [relevant to object pickling]

守給你的承諾、 提交于 2019-12-21 18:56:43
问题 (It is possible to directly jump to the question, further down, and to skip the introduction.) There is a common difficulty with pickling Python objects from user-defined classes: # This is program dumper.py import pickle class C(object): pass with open('obj.pickle', 'wb') as f: pickle.dump(C(), f) In fact, trying to get the object back from another program loader.py with # This is program loader.py with open('obj.pickle', 'rb') as f: obj = pickle.load(f) results in AttributeError: 'module'

How to access Rabbitmq Management UI by using fully qualified server name address?

泄露秘密 提交于 2019-12-11 10:57:56
问题 How to access Rabbitmq Management UI by using fully qualified server name address? It is working with localhost, but not with server fully qualified name. 来源: https://stackoverflow.com/questions/53443528/how-to-access-rabbitmq-management-ui-by-using-fully-qualified-server-name-addres

how to find out Fully qualified name IntelliJ project

一笑奈何 提交于 2019-12-11 04:44:22
问题 I have an IntelliJ project with 2 scala objects, as below: cloudera@quickstart tlf]$ ll total 8 -rwxrw-r-- 1 cloudera cloudera 1601 May 2 15:45 AnalyzeGraphTlf.scala -rwxrw-r-- 1 cloudera cloudera 1868 May 2 13:35 FormatDataTlf.scala [cloudera@quickstart tlf]$ ls AnalyzeGraphTlf.scala FormatDataTlf.scala [cloudera@quickstart tlf]$ pwd /home/cloudera/ideaProjects/grafoTelefonos/src/main/scala/tlf How can I know the fully qualified name of the package? 回答1: According to convention that IDEA

Should I use (otherwise optimal) class names that conflict with the .NET BCL's names?

白昼怎懂夜的黑 提交于 2019-12-08 16:54:06
问题 This situation probably is not entirely uncommon to some of you: you have some functionality to put in a class but the perfect name (*) for that class is taken by one of the classes in the System namespace or other namespace/class that's not yours but you're using / import ing. (*) By perfect I mean small, concise and clear names. For instance I have an Utils class that has a Diagnostics (mostly debug utils) class and a Drawing class. I could: have a DrawingUtils class and a DiagnosticsUtils

Impossible to fully qualify class-name in out-of-class declarator of function definition

做~自己de王妃 提交于 2019-12-08 16:22:33
问题 This program results in an undesired parsing greediness dead-end: struct float4x4 {}; class C { float4x4 M(); }; float4x4 ::C::M() { return float4x4{}; } :8:1: error: no member named 'C' in 'float4x4'; did you mean simply 'C'? float4x4 ::C::M() ^~~~~~~~~~~~ Which can be 'fixed' using trailing return type: auto ::C::M() -> float4x4 {} now all good. So I take it we can't fully qualify the class-name when using heading-return-type declarator syntax? 回答1: You can put brackets to disambiguate:

What's the meaning of “apostrophe + number” in the object type of properties with generics (eg. “Collection`1”)?

纵然是瞬间 提交于 2019-12-08 15:43:06
问题 I have an object ( MyObject ) with a property ( MyProperty ). I want to get it's type name (i.e. String or MyClass etc.). I use: PropertyInfo propInfo = typeof(MyObject).GetProperty("MyProperty"); Console.WriteLine(propInfo.PropertyType.Name); Console.WriteLine(propInfo.PropertyType.FullName); No problem with simple types, but when MyProperty is a generic type, I face problems on getting it's name (e.g. Collection<String> ). It prints: Collection`1 System.Collections.ObjectModel.Collection`1[

Using fully qualified function calls in Erlang?

本秂侑毒 提交于 2019-12-07 07:21:04
问题 I have just learnt how to upgrade a module in Erlang and I know that only the function calls that use the fully qualified names (eg. module:function() ) gets "relinked" to the current version loaded into the VM, but the function calls that do not specify the module's name do not get "relinked" to the current version, but keep using the older one. Is there a rule of thumb on when to use a fully qualified function call and when it's OK to call a function just by its name? Is it a bad idea to