frequency

问题 I have data saved in a long list. This is an example of the first six lines / records: A <- list(c("JAMES","CHARLES","JAMES","RICHARD"), c("JOHN","ROBERT","CHARLES"), c("CHARLES","WILLIAM","CHARLES","MICHAEL","WILLIAM","DAVID","CHARLES","WILLIAM"), c("CHARLES"), c("CHARLES","CHARLES"), c("MATTHEW","CHARLES","JACK")) Now I would like to calculate the relative frequency with which each unique term occurs in each line / record. Based on my example I would like to achieve an output similar to

问题 I am trying to convert a daily frequency dataframe to minute data, and in a previous post it was suggested to use the ffil method below but it does not seem to work with dataframes that consist of only 2 rows (Conversion of Daily pandas dataframe to minute frequency). So the below dataframe is supposed to be converted. import pandas as pd dict = [ {'ticker':'jpm','date': '2016-11-28','returns': 0.2}, { 'ticker':'ge','date': '2016-11-28','returns': 0.2}, {'ticker':'fb', 'date': '2016-11-28',

问题 I am trying to write a function that takes the size of an array and an int array made up of digits as input and prints the frequency of each digit. Sample input and output: Input: [1,2,2,3,3,3] Output: 1 occurs 1 times. 2 occurs 2 times 3 occurs 3 times. Here is my attempt (not the most elegant): void freq(int size, int numArray[]) { int one=0, two=0, thr=0, fou=0, fiv=0, six=0, sev=0, eit=0, nin=0; int i, j; for (i = 0; i < size; i++) { for (j = 1; j < size; j++) { if (numArray[i] ==

问题 The census dataset for last name and first name occurrences provides cumulative frequency and frequency . How do I go about getting a random name with the likelyhood of it being chosen that of the occurrence in the real world? 回答1: Just generate a random real number in the 0-100 range and look for the corresponding entry in the cumulative frequency dataset. Example, say your random number gives x = 19.41 . Look into the table (sorted by cumulative frequencies) and locate the first one that

问题 So, basically, I created an algorithm in java that takes characters from a string and counts its frequencies. Now, I need it to be printed in alphabetical order. For example : A freq: 3 d freq: 1 l freq: 5 Any suggestions? Here's what I have thus far. int[] charCounts(String userSort) { int[] counts = new int[256]; char[] c = userSort.toCharArray(); for (int i=0;i<c.length;++i) { counts[c[i]]++; } return counts; } 回答1: First you want to sort the characters within your supplied String and a

问题 I want to create a program to help me with the statistics, but I'm having problems from the beginning and I'm making a huge mess to calculate the relative frequency of an array with random numbers and only one dimension. For example to generate these numbers: {3, 5, 5, 2, 4, 1, 3, 5, 4} I want that the program tell me that the 3 is repeated 2 times, the 4 3 times and 5 5 times I've created a class to sort these values ​​in order to calculate the median, the first and third quartile, but I

问题 I have a plot that I would like to recreate within R. Here is the plot: From: Boring, E. G. (1941). Statistical frequencies as dynamic equilibria. Psychological Review, 48(4), 279. This is a little above my paygrade (abilities) hence asking here. Boring states: On the first occasion A can occur only 'never' (0) or 'always' (1). On the second occasion the frequencies are 0,1/2, or 1; on the third 0, 1/3, 2/3, or 1 etc, etc. Obviously, you don't have to worry about labels etc. Just a hint to

问题 I was wondering if it is possible at all the manipulate the radio hardware on the device to transmit an FM signal on a specified frequency. As far as I am aware, the phone uses Bluetooth radio, it uses 802.11 radio, so would it not be possible to adjust the power output of the radio device to transmit at frequencies of 87.5–108.0 MHz? If anyone has any documentation/research papers/guides into this area, please let me know. Is there any generic radio support in the SDK? Because my thinking is

问题 What is efficient and elegant data.table syntax for finding the most common category for each id? I keep a boolean vector indicating NA positions (for other purposes) dt = data.table(id=rep(1:2,7), category=c("x","y",NA)) print(dt) In this toy example, ignoring NA, x is common category for id==1 and y for id==2 . 回答1: If you want to ignore NA 's, you have to exclude them first with !is.na(category) , group by id and category ( by = .(id, category) ) and create a frequency variable with .N :

问题 I've been tasked with creating frequency tables with statistical summaries. My goal is to create a data frame that can be exported simply to excel. Most of this could be in sql using stored procedures but I decided to do this in R. I'm learning R so I might be doing it the long way. This is a follow on question from getting-r-frequency-counts-for-all-possible-answers Given Id <- c(1,2,3,4,5,6,7,8,9,10) ClassA <- c(1,NA,3,1,1,2,1,4,5,3) ClassB <- c(2,1,1,3,3,2,1,1,3,3) R <- c(1,2,3,NA,9,2,4,5