findall

I am trying to use BeautifulSoup to find all div containers with the class attribute beginning by "foo bar". I had hoped the following would work: from bs4 import BeautifulSoup import re soup.findAll('div',class_=re.compile('^foo bar')) However, it seems that the class definition is separated into a list, like ['foo','bar'] , such that regular expressions are not able to accomplish my task. Is there a way I can accomplish this task? (I have reviewed a number of other posts, but have not found a working solution) You can use a syntax with a function that needs to return True or False , a lambda

I have written my first bit of python code to scrape a website. import csv import urllib2 from BeautifulSoup import BeautifulSoup c = csv.writer(open("data.csv", "wb")) soup = BeautifulSoup(urllib2.urlopen('http://www.kitco.com/kitco-gold-index.html').read()) table = soup.find('table', id="datatable_main") rows = table.findAll('tr')[1:] for tr in rows: cols = tr.findAll('td') text = [] for td in cols: text.append(td.find(text=True)) c.writerow(text) When I test it locally in my ide called pyCharm it works good but when I try it out on my server which runs CentOS, I get the following error:

I have a list of objects that I want to filter by an integer parameter List<testObject> objectList = new List<testObject>(); // populate objectList with testObjects objectList.FindAll(GroupLevel0); private static bool GroupLevel0(testObject item) { return item._groupLevel == 0; } private class testObject { public string _FieldSQL = null; public int _groupLevel; } What I'm looking to do is to make GroupLevel0 take in an integer as a parameter instead of hardcoding to 0. I'm working in .NET 2.0 so lambda expressions are a no-go. Is it even possible to pass a parameter into a predicate? Thank you

Say I have a string s containing letters and two delimiters 1 and 2 . I want to split the string in the following way: if a substring t falls between 1 and 2 , return t otherwise, return each character So if s = 'ab1cd2efg1hij2k' , the expected output is ['a', 'b', 'cd', 'e', 'f', 'g', 'hij', 'k'] . I tried to use regular expressions: import re s = 'ab1cd2efg1hij2k' re.findall( r'(1([a-z]+)2|[a-z])', s ) [('a', ''), ('b', ''), ('1cd2', 'cd'), ('e', ''), ('f', ''), ('g', ''), ('1hij2', 'hij'), ('k', '')] From there i can do [ x[x[-1]!=''] for x in re.findall( r'(1([a-z]+)2|[a-z])', s ) ] to get

I'm new to grails and receive the following error: No signature of method: Something.findAll() is applicable for argument types: (java.lang.String, java.util.ArrayList) values: [from Something AS s WHERE s.some_number LIKE ?, [%asdf%]]" The error occurs when I run test-app . It occurs in the following place: SomethingVO[] findBySomeNumber(String searchString) { searchString = "%"+searchString+"%" return Something.findAll("from Something AS s WHERE s.some_number LIKE ?",[searchString]).collect { new SomethingVO(it); } } The class Something is a domain object: package some.project.domain class

I trying to build dynamic filters using findAll on a list. I have a variable that needs to be included in the filter only if not null. @Test void testSample(){ def list = [ new Employee(age:22, isManager:false), new Employee(age:23, isManager:true), new Employee(age:22, isManager:true) ] as Set def var = 22; String query1 = "it.age == var && it.isManager == true " String query2 = "it.isManager == true" println list println list.findAll { var ? query1 : query2 } // Should give 1 record age = 22 and manager var = null; println list.findAll { var ? query1 : query2 } // should give 2 records-only