face-recognition

I am a beginner in openCV. I have been trying out face detection and recognition in Windows platform. I have integrated different pieces of codes. I am also using PCA method to recognize the faces.I am getting an error like below, Error 1 error LNK1120: 2 unresolved externals Error 2 error LNK2019: unresolved external symbol _cvCalcEigenObjects referenced in function "void __cdecl doPCA(void)" (?doPCA@@YAXXZ) Error 3 error LNK2019: unresolved external symbol _cvEigenDecomposite referenced in function "void __cdecl learn(char *)" (?learn@@YAXPAD@Z) can someone please resolve.,.. Abhishek kumar

I want to follow the tutorials of the face recognition with opencv. But in the tutorial source code example getMat() method is used, which shows an error : class cv::face::FaceRecognizer has no member "getMat". After some searching I found out that opencv3.00 has deprecated that method. What can I use instead of getMat() now in opencv3.0? This is the tutorial I am trying to follow. See the new API here . Replace model->getMat("eigenvalues") with model->getEigenValues() , model->getMat("mean") with model->getMean() , etc... 来源： https://stackoverflow.com/questions/33262738/what-is-the

confidence = 1.0f - sqrt( distSq / (float)(nTrainFaces * nEigens) ) / 255.0f Why it is divided by (nTrainFaces*nEigens)? Why it is divided by (nTrainFaces*nEigens)? Well, if you're just trying to find the confidence value for the 'test face eigenvectors (or values?)' with just 1 and only trained face, then you'd do something like confidence = 1.0f - (sqrt( least_squared_distance / no_of_eigens ) / 255.0) However, since you're finding nearest neighbour within trained face database, you want the confidence to reflect that your nearest neighbour gives a high confidence value for one of the faces

I am trying to make face recognition by Principal Component Analysis (PCA) using python. Now I am able to get the minimum euclidean distance between the training images images and the input image input_image . Here is my code: import os from PIL import Image import numpy as np import glob import numpy.linalg as linalg #Step1: put database images into a 2D array filenames = glob.glob('C:\\Users\\me\\Downloads\\/*.pgm') filenames.sort() img = [Image.open(fn).convert('L').resize((90, 90)) for fn in filenames] images = np.asarray([np.array(im).flatten() for im in img]) #Step 2: find the mean image

Now i know that the coordinate system is messed up. I have tried reversing the view and imageView, nothing. I then tried to reverse the coordinates on the features and i still get the same problem. I know it detects the faces, eyes and mouth, but when i try to place the overlaying boxes from the samples codes, they are out of position (to be exact, they are on the right off-screen). Im stumped as to why this is happening. Ill post some code because i know some of you guys like the specificity: -(void)faceDetector { // Load the picture for face detection // UIImageView* image = [[UIImageView

I am trying to use the Face Recognition in video sample provided with OpenCV. The only modification I've done is: Instead of using command line arguments to provide CSV and Cascade classifier paths, I have given them directly in the code. This is the code: #include "stdafx.h" #include "opencv2/core/core.hpp" #include "opencv2/contrib/contrib.hpp" #include "opencv2/highgui/highgui.hpp" #include "opencv2/imgproc/imgproc.hpp" #include "opencv2/objdetect/objdetect.hpp" #include <iostream> #include <fstream> #include <sstream> using namespace cv; using namespace std; static void read_csv(const

Does anyone know the location of the face unlock code in the android source tree? I'm looking to include some face recognition in my app and would love to use the code that google has already created. I've already looked at the alternatives such as opencv and some other third party APIs, but I'd really just like to see the way that google did it. Thanks! Unfortunately: Face unlock is closed-source google proprietary code, so we have no opportunity to modify it. Source: http://forum.xda-developers.com/showthread.php?t=1367610 来源： https://stackoverflow.com/questions/8632541/face-unlock-code-in