equals

String is being shown as equal to a number

狂风中的少年 提交于 2020-01-05 07:11:10
问题 I'm having a strange problem in some of my php. What seems to be happening is that 0 is being shown as equal to the string "done". Here's what's happening: if(!isset($pointer)){ $pointer = 0; } error_log($pointer); //in this instance, I haven't set a pointer, returns 0 if($pointer == "done"){ die(); } For some reason, the second if statement is triggering and killing the script. I can't figure out why, when $pointer is equal to 0, it is apparently also equal to "done". Is this something super

String is being shown as equal to a number

泄露秘密 提交于 2020-01-05 07:09:15
问题 I'm having a strange problem in some of my php. What seems to be happening is that 0 is being shown as equal to the string "done". Here's what's happening: if(!isset($pointer)){ $pointer = 0; } error_log($pointer); //in this instance, I haven't set a pointer, returns 0 if($pointer == "done"){ die(); } For some reason, the second if statement is triggering and killing the script. I can't figure out why, when $pointer is equal to 0, it is apparently also equal to "done". Is this something super

Constant states do not match in developer preview android L

妖精的绣舞 提交于 2020-01-05 05:26:14
问题 I am trying to do something in an if-statement, this works in every version of android (16 or higher because of the getDrawable) except Android L (tested on latest). The code is the following: if (item.getIcon().getConstantState().equals(getResources().getDrawable(R.drawable.add_to_fav_normal).getConstantState()) Any help/hints or explanation would be appreciated! 回答1: Use item.getContext().getDrawable(int) or the equivalent ContextCompat method. Starting in API 21, all framework widgets that

Can I use .getClass() == .class or .getClass() == .class.getClass()?

喜欢而已 提交于 2020-01-05 04:10:50
问题 I'm testing if an Object is equals than a specific class type. For example: @Override public void itemStateChanged(ItemEvent e) { if (e.getStateChange() == ItemEvent.SELECTED) { Object sourceObject = e.getSource(); if (sourceObject.getClass() == JComboBox.class.getClass()) { @SuppressWarnings("unchecked") JComboBox<String> jComboBox = (JComboBox<String>) sourceObject; So, what comparison method should I use? sourceObject.getClass() == JComboBox.class.getClass() or sourceObject.getClass() ==

Override Equals and GetHashCode in class with one field

点点圈 提交于 2020-01-05 02:55:08
问题 I have a class: public abstract class AbstractDictionaryObject { public virtual int LangId { get; set; } public override bool Equals(object obj) { if (obj == null || obj.GetType() != GetType()) { return false; } AbstractDictionaryObject other = (AbstractDictionaryObject)obj; if (other.LangId != LangId) { return false; } return true; } public override int GetHashCode() { int hashCode = 0; hashCode = 19 * hashCode + LangId.GetHashCode(); return hashCode; } And I have derived classes: public

HashSet.contains returns false when it shouldn't

家住魔仙堡 提交于 2020-01-04 05:22:28
问题 I have this code: public class Tray { private Set<Block> blocks; private int numColumns; private int numRows; //constructor public Tray (int numRows, int numColumns){ this.numColumns = numColumns; this.numRows = numRows; blocks = new HashSet<>(); } public boolean satisfiesGoal(Tray other){ Block thisBlock = this.blocks.iterator().next(); Block otherBlock = other.blocks.iterator().next(); boolean hashesEqual = thisBlock.hashCode() == otherBlock.hashCode(); // this is true boolean areEqual =

Confusion about comparison by .Equals() vs. == operator and primitives vs. objects

≯℡__Kan透↙ 提交于 2020-01-04 04:56:43
问题 Consider this code: int a = 0; short b = 0; int c = 0; object a1 = a; object b1 = b; object c1 = c; Console.WriteLine(1); //comparing primitives - int vs. short Console.WriteLine(a == b); Console.WriteLine(b == a); Console.WriteLine(a.Equals(b)); Console.WriteLine(b.Equals(a)); Console.WriteLine(2); //comparing objects - int vs. int Console.WriteLine(c1 == a1); Console.WriteLine(a1 == c1); Console.WriteLine(c1.Equals(a1)); Console.WriteLine(a1.Equals(c1)); Console.WriteLine(3); //comparing

When subsetting rows with a factor with equal (==), NA's are also included. It doesn't happen with %in%. Is it normal?

笑着哭i 提交于 2020-01-03 11:49:52
问题 Suppose I have a factor A with 3 levels A1, A2, A3 and with NA's. Each appears in 10 cases, so there is a total of 40 cases. If I do subset1 <- df[df$A=="A1",] dim(subset1) # 20, i.e., 10 for A1 and 10 for NA's summary(subset1$A) # both A1 and NA have non-zero counts subset2 <- df[df$A %in% c("A1"),] dim(subset2) # 10, as expected summary(subset2$A) # only A1 has non-zero count And it is the same whether the class of the variable used for subsetting is factor or integer. Is it just how equal

When subsetting rows with a factor with equal (==), NA's are also included. It doesn't happen with %in%. Is it normal?

◇◆丶佛笑我妖孽 提交于 2020-01-03 11:49:04
问题 Suppose I have a factor A with 3 levels A1, A2, A3 and with NA's. Each appears in 10 cases, so there is a total of 40 cases. If I do subset1 <- df[df$A=="A1",] dim(subset1) # 20, i.e., 10 for A1 and 10 for NA's summary(subset1$A) # both A1 and NA have non-zero counts subset2 <- df[df$A %in% c("A1"),] dim(subset2) # 10, as expected summary(subset2$A) # only A1 has non-zero count And it is the same whether the class of the variable used for subsetting is factor or integer. Is it just how equal

Apache Commons Lang3 Hashcode, Equals and ToString including Enums

淺唱寂寞╮ 提交于 2020-01-03 09:09:12
问题 We have few datatypes defined for our service response and request objects in a model. Recently we found a need of implementing ToString, HashCode and Equals on all such types to make use of these over comparison and assertions. Confirming from few source like What issues should be considered when overriding equals and hashCode in Java?, Right way to implement equals contract etc we followed implementing toString, equals and hashcode using org.apache.commons.lang3.builder.EqualsBuilder ,