eof

问题 From The C Programming Language : int c; while ((c = getchar()) != EOF) putchar(c); "... The solution is that getchar returns a distinctive value when there is no more input, a value that cannot be confused with any real character. This value is called EOF , for "end of file." We must declare c to be a type big enough to hold any value that getchar returns. We can't use char since c must be big enough to hold EOF in addition to any possible char ." I checked in stdio.h and printed the value

问题 I've tried some ways to detect EOF in my code, but it still not working. I've tried using BufferedReader, Scanner, and using char u001a to flag the EOF, but still not make any sense to my code. Here is my last code : Scanner n=new Scanner(System.in); String input; int counter=0; while(n.hasNextLine()) { input=n.nextLine(); char[] charInput=input.toCharArray(); for (int i = 0; i < input.length(); i++) { if(charInput[i]=='"') { if(counter%2==0) { System.out.print("``"); } else { System.out

问题 I want to do something like: for line in sys.stdin: do_something() if is **END OF StdIn**: do_something_special() After a few tries, for now I am doing this: while True: try: line = sys.stdin.next() print line, except StopIteration: print 'EOF!' break Or with this: while True: line = sys.stdin.readline() if not line: print 'EOF!' break print line, I think both above ways are very similar. I want to know is there a more elegant (pythonic) way to do this? Early failed tries: I first tried to

问题 I want to do something like: for line in sys.stdin: do_something() if is **END OF StdIn**: do_something_special() After a few tries, for now I am doing this: while True: try: line = sys.stdin.next() print line, except StopIteration: print 'EOF!' break Or with this: while True: line = sys.stdin.readline() if not line: print 'EOF!' break print line, I think both above ways are very similar. I want to know is there a more elegant (pythonic) way to do this? Early failed tries: I first tried to

问题 #include<stdio.h> int main(void) { FILE *fp; int ch; fp = fopen("input.txt", "w"); printf("Enter data"); while ((ch = getchar()) != EOF) { putc(ch, fp); } fclose(fp); fp = fopen("input.txt", "w"); while ((ch = getc(fp)) != EOF) { printf("%c", ch); } fclose(fp); } How does the first while loop stop inputting from user? Since there is EOF present as a condition. Or else do I need to use for loop? 回答1: EOF is a value, not a function. It is essentially defined as a macro. For reference, from C11

问题 Executing the command: ./program < input.txt with the following code checking: string input; while(cin) { getline(cin, input); } The above code seems to generate an extra getline() call where input is empty. This happens regardless of whether or not there's a \n on the last line of input.txt. 回答1: @Jacob had the correct solution but deleted his answer for some reason. Here's what's going on in your loop: cin is checked for any of the failure bits (BADBIT, FAILBIT) cin reports no problem

问题 I'm need to know if the next char in ifstream is the end of file. I'm trying to do this with .peek() : if (file.peek() == -1) and if (file.peek() == file.eof()) But neither works. There's a way to do this? Edit: What I'm trying to do is to add a letter to the end of each word in a file. In order to do so I ask if the next char is a punctuation mark, but in this way the last word is left without an extra letter. I'm working just with char , not string . 回答1: istream::peek() returns the

问题 I am in an intro to programming class and we're making a calculator to figure out how many times a human heart has beaten given the number of years someone has been alive, and I keep getting unexpected EOF while parsing on the last line of code, can someone help me figure out why? input("What is your name? ") age= float(input("How old are you? ")) print("The average human heart beats 70 times a minute.") beats_per_hour = 70 * 60 beats_per_day = beats_per_hour * 24 beats_per_year = beats_per

问题 in my program i need to read numbers in this format - number, number, number etc., and it ends when user press ctrl+d. I switch scanf("%d",&i) and scanf("%c",&c) . My problem is, that the program ends, when i press ctrl+d 3 times, the first and second time it ignores it for some reason. I also noticed, that if i debug and write : " 5, 6ctrl+d " it reads " 5, " and then it waits for next input. Why, when there is 6 and ctlr+d already ? Thanks My code : for (;;) { if (cislo==1) { res=scanf("%d"

问题 in my program i need to read numbers in this format - number, number, number etc., and it ends when user press ctrl+d. I switch scanf("%d",&i) and scanf("%c",&c) . My problem is, that the program ends, when i press ctrl+d 3 times, the first and second time it ignores it for some reason. I also noticed, that if i debug and write : " 5, 6ctrl+d " it reads " 5, " and then it waits for next input. Why, when there is 6 and ctlr+d already ? Thanks My code : for (;;) { if (cislo==1) { res=scanf("%d"