enums

pip install enum not working showing the error of 'intflag' doesnt have

孤人 提交于 2021-02-10 06:27:07
问题 pip install Enum is not working is showing the error of AttributeError:module 'enum' has no attribute 'IntFlag' 回答1: enum34 is the stdlib Enum backport, but it only supports features found up to 3.5. If you want features found in 3.6 you'll need to use aenum 1 . 1 Disclosure: I am the author of the Python stdlib Enum, the enum34 backport, and the Advanced Enumeration (aenum) library. 来源: https://stackoverflow.com/questions/44745374/pip-install-enum-not-working-showing-the-error-of-intflag

pip install enum not working showing the error of 'intflag' doesnt have

人盡茶涼 提交于 2021-02-10 06:26:09
问题 pip install Enum is not working is showing the error of AttributeError:module 'enum' has no attribute 'IntFlag' 回答1: enum34 is the stdlib Enum backport, but it only supports features found up to 3.5. If you want features found in 3.6 you'll need to use aenum 1 . 1 Disclosure: I am the author of the Python stdlib Enum, the enum34 backport, and the Advanced Enumeration (aenum) library. 来源: https://stackoverflow.com/questions/44745374/pip-install-enum-not-working-showing-the-error-of-intflag

Is it possible to iterate through several enum classes?

試著忘記壹切 提交于 2021-02-10 06:01:16
问题 I have three enum classes. I want to somehow put these in an array, loop through the array and call the same method in each enum class. Is this possible in Java? It seems to me you can't place enum types in an array structure (unless i've missed how). Thank you. 回答1: Let each enum type implement a common interface that has the common method that you want into invoke. You can now cast each enum, while iterating, to this common interface and call the method. Also look at EnumSet 回答2: Here is an

Is it possible to iterate through several enum classes?

核能气质少年 提交于 2021-02-10 06:01:16
问题 I have three enum classes. I want to somehow put these in an array, loop through the array and call the same method in each enum class. Is this possible in Java? It seems to me you can't place enum types in an array structure (unless i've missed how). Thank you. 回答1: Let each enum type implement a common interface that has the common method that you want into invoke. You can now cast each enum, while iterating, to this common interface and call the method. Also look at EnumSet 回答2: Here is an

Type is not assignable to conditional type

◇◆丶佛笑我妖孽 提交于 2021-02-10 03:26:23
问题 I have a TypeScript code snippet in the playground. Please take a look there at TypeScript playground or here: enum MyTypes { FIRST = "FIRST", SECOND = "SECOND", THIRD = "THIRD" } type TFirst = { type: MyTypes.FIRST foo: string } type TSecond = { type: MyTypes.SECOND foo: string } type TThird = { type: MyTypes.THIRD bar: string } type TConditionalType<T> = T extends MyTypes.FIRST ? TFirst : T extends MyTypes.SECOND ? TSecond : T extends MyTypes.THIRD ? TThird : null const

Type is not assignable to conditional type

有些话、适合烂在心里 提交于 2021-02-10 03:26:06
问题 I have a TypeScript code snippet in the playground. Please take a look there at TypeScript playground or here: enum MyTypes { FIRST = "FIRST", SECOND = "SECOND", THIRD = "THIRD" } type TFirst = { type: MyTypes.FIRST foo: string } type TSecond = { type: MyTypes.SECOND foo: string } type TThird = { type: MyTypes.THIRD bar: string } type TConditionalType<T> = T extends MyTypes.FIRST ? TFirst : T extends MyTypes.SECOND ? TSecond : T extends MyTypes.THIRD ? TThird : null const

Type is not assignable to conditional type

左心房为你撑大大i 提交于 2021-02-10 03:25:09
问题 I have a TypeScript code snippet in the playground. Please take a look there at TypeScript playground or here: enum MyTypes { FIRST = "FIRST", SECOND = "SECOND", THIRD = "THIRD" } type TFirst = { type: MyTypes.FIRST foo: string } type TSecond = { type: MyTypes.SECOND foo: string } type TThird = { type: MyTypes.THIRD bar: string } type TConditionalType<T> = T extends MyTypes.FIRST ? TFirst : T extends MyTypes.SECOND ? TSecond : T extends MyTypes.THIRD ? TThird : null const

Type is not assignable to conditional type

安稳与你 提交于 2021-02-10 03:25:07
问题 I have a TypeScript code snippet in the playground. Please take a look there at TypeScript playground or here: enum MyTypes { FIRST = "FIRST", SECOND = "SECOND", THIRD = "THIRD" } type TFirst = { type: MyTypes.FIRST foo: string } type TSecond = { type: MyTypes.SECOND foo: string } type TThird = { type: MyTypes.THIRD bar: string } type TConditionalType<T> = T extends MyTypes.FIRST ? TFirst : T extends MyTypes.SECOND ? TSecond : T extends MyTypes.THIRD ? TThird : null const

Representing enum variants with optional data in macro_rules

左心房为你撑大大i 提交于 2021-02-10 00:36:23
问题 I'm trying to create a macro to help with some boilerplate enum code that I've been repetitively writing. I managed to implement a simple enum (i.e. no arguments) relatively easily using a basic macro_rule . e.g. An excerpt: macro_rules! enum_helper { ($type:ident, { $( $name:ident ), * }) => { enum $type { $( $name, )+ } impl FromSql for $type { fn from_sql<R: Read>(_: &Type, raw: &mut R, _: &SessionInfo) -> Result<&type> { // ... the implementation } // ... plus some other internal traits

Representing enum variants with optional data in macro_rules

一笑奈何 提交于 2021-02-10 00:33:48
问题 I'm trying to create a macro to help with some boilerplate enum code that I've been repetitively writing. I managed to implement a simple enum (i.e. no arguments) relatively easily using a basic macro_rule . e.g. An excerpt: macro_rules! enum_helper { ($type:ident, { $( $name:ident ), * }) => { enum $type { $( $name, )+ } impl FromSql for $type { fn from_sql<R: Read>(_: &Type, raw: &mut R, _: &SessionInfo) -> Result<&type> { // ... the implementation } // ... plus some other internal traits