elements

what are the fast algorithms to find duplicate elements in a collection and group them?

点点圈 提交于 2019-11-27 13:07:24
问题 Say you have a collection of elements, how can you pick out those with duplicates and put them into each group with least amount of comparison? preferably in C++, but algorithm is more important than the language. For Example given {E1,E2,E3,E4,E4,E2,E6,E4,E3}, I wish to extract out {E2,E2}, {E3,E3}, {E4,E4,E4}. what data structure and algorithm you will choose? Please also include the cost of setting up the data structure, say, if it's a pre-sorted one like std::multimap Updates To make

Number of elements in a javascript object

橙三吉。 提交于 2019-11-27 09:31:27
问题 Is there a way to get (from somewhere) the number of elements in a javascript object?? (i.e. constant-time complexity). I cant find a property or method that retrieve that information. So far I can only think of doing an iteration through the whole collection, but that's linear time. It's strange there is no direct access to the size of the object, dont you think. EDIT: I'm talking about the Object object (not objects in general): var obj = new Object ; 回答1: Although JS implementations might

How to remove the selected element during a clone() operation

有些话、适合烂在心里 提交于 2019-11-27 08:20:40
问题 I have a select box that gets cloned. I want to remove the user's previous selection from each cloned select box. Here is the method that does the clone() : function addselect(s){ $('#product_categories > .category_block:last').after( $('#product_categories > .category_block:last').clone() ); set_add_delete_links(); return false; } function set_add_delete_links(){ $('.remove_cat').show(); $('.add_cat').hide(); $('.add_cat:last').show(); $("#product_categories > .category_block:only-child >

Skipping every other element after the first

无人久伴 提交于 2019-11-27 07:45:46
I have the general idea of how to do this in Java, but I am learning Python and not sure how to do it. I need to implement a function that returns a list containing every other element of the list, starting with the first element. Thus far, I have and not sure how to do from here since I am just learning how for-loops in Python are different: def altElement(a): b = [] for i in a: b.append(a) print b def altElement(a): return a[::2] Darius Bacon Slice notation a[start_index:end_index:step] return a[::2] where start_index defaults to 0 and end_index defaults to the len(a) . Alternatively, you

Deleting list elements based on condition

我的梦境 提交于 2019-11-27 01:48:52
I have a list of lists: [word, good freq, bad freq, change_status] list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]] I would like to delete from the list all elements which don't satisfy a condition. So if change_status > 0.3 and bad_freq < 5 then I would like to delete that the elements corresponding to it. So the list_1 would be modified as, list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0]] How do I selective do that? list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]] list_1 = [item for item in list_1 if item[2] >= 5 or item[3] >= 0.3] You can

Get multiple elements by Id

风格不统一 提交于 2019-11-26 21:51:22
I have a page with anchor tags throughout the body like this: <a id="test" name="Name 1"></a> <a id="test" name="Name 2"></a> <a id="test" name="Name 3"></a> The ID is always the same but the name changes. I need to populate a list of the names of these anchor tags, for example; Name 1, Name 2, Name 3. This is where I've got to so far: document.write(document.getElementById("readme").name); This writes out the name of the first anchor tag. I'm in need of a way to get multiple elements by Id. Any help is greatly appreciated. If you can change the markup, you might want to use class instead. <!-

Deleting list elements based on condition

你。 提交于 2019-11-26 17:28:37
问题 I have a list of lists: [word, good freq, bad freq, change_status] list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]] I would like to delete from the list all elements which don't satisfy a condition. So if change_status > 0.3 and bad_freq < 5 then I would like to delete that the elements corresponding to it. So the list_1 would be modified as, list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0]] How do I selective do that? 回答1: list_1 = [['good',100, 20, 0.2],['bad', 10

Selecting a div by classname

半腔热情 提交于 2019-11-26 17:25:07
问题 I got this div... <div tabindex="0" class="button-base inline-block button aw-btn button-base-active"> <input type="text" tabindex="-1" style="opacity: 0; height: 1px; width: 1px; z-index: -1; overflow-x: hidden; overflow-y: hidden; position: absolute; "> </div> in the middle of my page, it has no id and I am unable to edit the pages HTML, I am also no able to use jQuery. Also trying to do it with IE7 and IE8. Nightmare here :) The solution would be document.getElementsByClassName but that is

Is it possible to clone html element objects in JavaScript / JQuery?

耗尽温柔 提交于 2019-11-26 16:14:10
I am looking for some tips on how to solve my problem. I have a html element (like select box input field) in a table. Now I want to copy the object and generate a new one out of the copy, and that with JavaScript or jQuery. I think this should work somehow but I'm a little bit clueless at the moment. Something like this (pseudo code): oldDdl = $("#ddl_1").get(); newDdl = oldDdl; oldDdl.attr('id', newId); oldDdl.html(); Boris Guéry Using your code you can do something like this in plain JavaScript using the cloneNode() method: // Create a clone of element with id ddl_1: let clone = document

Skipping every other element after the first

。_饼干妹妹 提交于 2019-11-26 13:48:36
问题 I have the general idea of how to do this in Java, but I am learning Python and not sure how to do it. I need to implement a function that returns a list containing every other element of the list, starting with the first element. Thus far, I have and not sure how to do from here since I am just learning how for-loops in Python are different: def altElement(a): b = [] for i in a: b.append(a) print b 回答1: def altElement(a): return a[::2] 回答2: Slice notation a[start_index:end_index:step] return