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I found many answers about my question, but I still don't understand why my application does not throw any exceptions. I created a new java form application in NetBeans 8. My form is created and displayed in main method like this: public static void main(String args[]) { /* Set the Nimbus look and feel */ //<editor-fold defaultstate="collapsed" desc=" Look and feel setting code (optional) "> /* If Nimbus (introduced in Java SE 6) is not available, stay with the default look and feel. * For details see http://download.oracle.com/javase/tutorial/uiswing/lookandfeel/plaf.html */ try { for (javax

I had already looked through this post: Python: building new list from existing by dropping every n-th element , but for some reason it does not work for me: I tried this way: def drop(mylist, n): del mylist[0::n] print(mylist) This function takes a list and n . Then it removes every n-th element by using n-step from list and prints result. Here is my function call: drop([1,2,3,4],2) Wrong output: [2, 4] instead of [1, 3] Then I tried a variant from the link above: def drop(mylist, n): new_list = [item for index, item in enumerate(mylist) if index % n != 0] print(new_list) Again, function call

This question already has an answer here: Ruby: How to find and return a duplicate value in array? 18 answers I have an array like [1,1,1,2,4,6,3,3] and I would like to get the list of repeated elements, in this case [1,3]. I wrote this: my_array.select{|obj|my_array.count(obj)>1}.uniq But it is tragically inefficient (o(n²)). Do you have a better idea? If possible concise. Thanks Inspired by Ilya Haykinson's answer: def repeated(array) counts = Hash.new(0) array.each{|val|counts[val]+=1} counts.reject{|val,count|count==1}.keys end Using Ruby's Set library: require 'set' ary = [1,1,1,2,4,6,3,3

该vector只能容纳标准库中string类， 直接上代码了，StrVec.h文件内容为: 1 #ifndef STRVEC_H 2 #define STRVEC_H 3 4 #include<iostream> 5 #include<string> 6 #include<memory> 7 using namespace std; 8 class StrVec{ 9 public: 10 // 默认构造函数 11 StrVec():elements(nullptr),first_free(nullptr),cap(nullptr) 12 { 13 14 } 15 //拷贝构造函数 16 StrVec(const StrVec& ); 17 //拷贝赋值运算符 18 StrVec& operator=(const StrVec&); 19 ~StrVec(); 20 void push_back(const string&); 21 size_t size() const { return first_free - elements ; } 22 size_t capacity() const { return cap - elements ;} 23 string* begin() const { return elements ;} 24 string* end() const

This question already has an answer here: Interleaving Lists in Python [duplicate] 4 answers for example: a=[1,2,3,4,5,6] b=[7,8,9,10,11,12] then result: c=[1,7,2,8,3,9,4,10,5,11,6,12] How do you concatenate two lists,so that the elements are in alternative positions?? i have tried to link them in to a new list and rearrange but its not coming. it would be nice if you could tell me the long way(without using built in functions too much).I m new to python and not much is taught in my school. Thank you. Just append them with a for loop, assuming they're the same length: c = [] for i in range(len

I'm working on automated builds and need to be able to list elements that were worked on under particular activities. I'm new to ClearCase so I apologise for naiivety ... My downstream build process works fine and I now need to populate a 'pre-build' area by identifying the (checked-in) files associated with one or more activities, labels etc (in fact any combination the change/release manager wants) by listing the candidate files for a build and then copying them from the M: drive (Windows). We are using CC 7.1 with a back end on AIX and Win XP Pro desktops. We'll use ccperl to drive the find

How would I go about finding the three most common elements in an array? I am working with an array of length 10,000 with elements = random integer from 0-100. I was thinking of using two arrays, one of length 100 and just incrementing by using an if statement. However, I was wondering if there is a way that only one for/if loop(statement) could be used to find these values. If you are going to do this in a constant number of passes over the list, you need a second data structure. If you have lower and upper bounds for the values in that set and the values are relatively dense, then an array

I have a problem using Linq To Xml. A simple code. I have this XML: <?xml version="1.0" encoding="utf-8" ?> <data xmlns="http://www.example.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.com/directory file.xsd"> <contact> <name>aaa</name> <email>email@email.ext</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description>Description for this contact</description> </contact> <contact> <name>sss</name> <email>email@email.ext</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description