elements

polymer not working or displaying no elements

由 为君一笑 提交于 2019-12-04 22:24:30
Trying to display hello world using elements but nothing happens any help? index.html <!DOCTYPE html> <html> <head> <meta name="viewport" content="width=device-width, minimum-scale=1.0, initial-scale=1.0, user-scalable=yes"> <script src="bower_components/webcomponentsjs/webcomponents.js"></script> <link rel="import" href="elements/hello-world.html"> </head> <body unresolved> <hello-world></hello-world> </body> </html> hello-world.html <link rel="import" href="../bower_components/polymer/polymer.html"> <polymer-element name="hello-world" nonscript> <template> <h2>Hello World</h2> </template> <

Looping over Protocol Buffers attributes in Python

由 戏子无情 提交于 2019-12-04 18:07:18
问题 I would like help with recursively looping over all attributes/sub objects contained in a protocol buffers message, assuming that we do not know the names of them, or how many there are. As an example, take the following .proto file from the tutorial on the google website: message Person { required string name = 1; required int32 id = 2; optional string email = 3; enum PhoneType { MOBILE = 0; HOME = 1; WORK = 2; } message PhoneNumber { required string number = 1; optional PhoneType type = 2

comparing elements of the same array in java

由 非 Y 不嫁゛ 提交于 2019-12-04 13:31:42
问题 I am trying to compare elements of the same array. That means that i want to compare the 0 element with every other element, the 1 element with every other element and so on. The problem is that it is not working as intended. . What i do is I have two for loops that go from 0 to array.length-1.. Then i have an if statement that goes as follows: if(a[i]!=a[j+1]) for (int i = 0; i < a.length - 1; i++) { for (int k = 0; k < a.length - 1; k++) { if (a[i] != a[k + 1]) { System.out.println(a[i] + "

Selenium - How to capture all web page elements and associated locators on a page?

由 三世轮回 提交于 2019-12-04 12:57:59
What Java/Selenium commands can I use to capture/get/output for all elements and associated element locators for a single webpage? The Selenium IDE allows you to inspect one element at a time. That is a problem if you have thousands of elements to automate. Is there a tool or Java/selenium command that I can use to get all of the objects/elements on my web page at once and then maybe customize the output to suite my needs? If you have any experience with SilkTest, I'd like something analogous to generating Window Declarations in SilkTest. SilkTest's Record Window Declaration tool captures tag

Trying to replace html tags using regex

由 ⅰ亾dé卋堺 提交于 2019-12-04 10:29:56
For the example, I'm trying to replace <script type='text/javascript'>some stuff</script> with: <div type='text/javascript'>some stuff</div> I'm currently testing with: alert( o.replace( /(?:<\s*\/?\s*)(script)(?:\s*([^>]*)?\s*>)/gi ,'div') ); But what I'm getting is: divsomestuffdiv How can I get this to only replace the "script" portion and preserve the other markup and attribute characters? You have keep the opening and closing tag brackets. So try this: o.replace(/(<\s*\/?\s*)script(\s*([^>]*)?\s*>)/gi ,'$1div$2') A naive but readable way would be to do it in two passes i suppose and first

Is it possible to obtain a list of events bound to an element in jQuery?

由 五迷三道 提交于 2019-12-04 05:48:25
As the question said, i need the list of events bound to a specific element. I mean events like click, mouseover etc bound to that element at the loading of the dom. (Stupid) example: $("#element").click(function() { //stuff }); $("#element").mouseover(function() { //stuff }); $("#element").focus(function() { //stuff }); Result: click, mouseover, focus Every event is added to an array. This array can be accessed using the jQuery data method: $("#element").data('events') To log all events of one object to fireBug just type: console.log ( $("#element").data('events') ) And you will get a list of

How to concatenate two lists so that elements are in alternative position? [duplicate]

由 ￣綄美尐妖づ 提交于 2019-12-04 02:06:12
问题 This question already has answers here : Interleaving Lists in Python [duplicate] (4 answers) Closed 4 years ago . for example: a=[1,2,3,4,5,6] b=[7,8,9,10,11,12] then result: c=[1,7,2,8,3,9,4,10,5,11,6,12] How do you concatenate two lists,so that the elements are in alternative positions?? i have tried to link them in to a new list and rearrange but its not coming. it would be nice if you could tell me the long way(without using built in functions too much).I m new to python and not much is

Moving a DIV element to bottom of parent (as last child)

由 泪湿孤枕 提交于 2019-12-04 01:47:38
I'm trying to create a continually rotating banner for the top of the homepage of a site I'm developing. The best way that I can figure to keep it constantly in rotation is to take the first DIV (firstChild) and move it to the end of the stack once it's slid out of view. This: <div id='foo0'></div> <div id='foo1'></div> <div id='foo2'></div> <div id='foo3'></div> Should become this: <div id='foo1'></div> <div id='foo2'></div> <div id='foo3'></div> <div id='foo0'></div> I use the Prototype framework... and I've tried to do this by cloning the element using my own method and inserting it into

java数据结构之数组

由 為{幸葍}努か 提交于 2019-12-03 11:10:11
package demo01;import java.util.Arrays;public class MyArray { private int[] elements; public MyArray() { elements = new int[0]; } //获取长度 public int size() { return elements.length; } //添加元素 public void add(int element){ int[] newArr = new int[elements.length+1]; for(int i = 0;i < elements.length;i++) { newArr[i] = elements[i]; } newArr[elements.length] = element; elements = newArr;//新数组替换旧数组 } //打印元素 public void printArray() { System.out.println(Arrays.toString(elements)); } //删除元素 public void delete(int index) { if(index < 0 || index > elements.length-1) { throw new RuntimeException("下标越界");

comparing elements of the same array in java

由 怎甘沉沦 提交于 2019-12-03 08:49:01
I am trying to compare elements of the same array. That means that i want to compare the 0 element with every other element, the 1 element with every other element and so on. The problem is that it is not working as intended. . What i do is I have two for loops that go from 0 to array.length-1.. Then i have an if statement that goes as follows: if(a[i]!=a[j+1]) for (int i = 0; i < a.length - 1; i++) { for (int k = 0; k < a.length - 1; k++) { if (a[i] != a[k + 1]) { System.out.println(a[i] + " not the same with " + a[k + 1] + "\n"); } } } First things first, you need to loop to < a.length
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