dynamic-class

Pickling of dynamic class definition

由 微笑、不失礼 提交于 2021-01-27 07:00:05
问题 I am trying to pickle a dynamically generated class as a factory for an alternative class. Something like the following: import sys, pickle class BC(object): pass C = type("NewClassName", (BC,), {}) pickle.dump(C, sys.stdout) This leads to the following error: pickle.PicklingError: Can't pickle <class '__main__.NewClassName'>: it's not found as __main__.NewClassName For pickling an object of a dynamically generated class, you can define an __reduce__ method, but is there a way to achieve this

Pickling of dynamic class definition

由 妖精的绣舞 提交于 2021-01-27 06:59:54
问题 I am trying to pickle a dynamically generated class as a factory for an alternative class. Something like the following: import sys, pickle class BC(object): pass C = type("NewClassName", (BC,), {}) pickle.dump(C, sys.stdout) This leads to the following error: pickle.PicklingError: Can't pickle <class '__main__.NewClassName'>: it's not found as __main__.NewClassName For pickling an object of a dynamically generated class, you can define an __reduce__ method, but is there a way to achieve this

PHP namespace and dynamic classname

由 左心房为你撑大大i 提交于 2020-01-14 13:49:47
问题 I've encountered a "weird" thing while experimenting with spl_autoload, namespaces and dynamic class names. I use PHP 5.3.2, call the autoload like this set_include_path(get_include_path().PATH_SEPARATOR."classes".PATH_SEPARATOR."utils"); spl_autoload_extensions(".class.php"); spl_autoload_register(); Now to the core. Suggest following code: new \User\Student; $name="\User\Student"; new $name(); This works fine, file classes/user/student.class.php gets loaded successfully, both constructions

PHP namespace and dynamic classname

由 ⅰ亾dé卋堺 提交于 2020-01-14 13:49:28
问题 I've encountered a "weird" thing while experimenting with spl_autoload, namespaces and dynamic class names. I use PHP 5.3.2, call the autoload like this set_include_path(get_include_path().PATH_SEPARATOR."classes".PATH_SEPARATOR."utils"); spl_autoload_extensions(".class.php"); spl_autoload_register(); Now to the core. Suggest following code: new \User\Student; $name="\User\Student"; new $name(); This works fine, file classes/user/student.class.php gets loaded successfully, both constructions

Instantiate a class from a string in ActionScript 3

由 此生再无相见时 提交于 2019-12-30 09:51:15
问题 I've got a string which, in run-time, contains the name of a class that I want to instantiate. How would I do that? I read suggestions to use flash.utils.getDefinitionByName() : var myClass:Class = getDefinitionByName("package.className") as Class; var myInstance:* = new myClass(); However, that gives me the following error: [Fault] exception, information=ReferenceError: Error #1065: Variable className is not defined. 回答1: The easiest method I've come up with is to simply write the classnames

Instantiate a class from a string in ActionScript 3

由 放肆的年华 提交于 2019-12-01 06:12:11
I've got a string which, in run-time, contains the name of a class that I want to instantiate. How would I do that? I read suggestions to use flash.utils.getDefinitionByName() : var myClass:Class = getDefinitionByName("package.className") as Class; var myInstance:* = new myClass(); However, that gives me the following error: [Fault] exception, information=ReferenceError: Error #1065: Variable className is not defined. The easiest method I've come up with is to simply write the classnames out, separated by semicolons, anywhere in your project. e.g. I create an Assets.as file with this in it:

Create Class dynamically at runtime

由 孤街醉人 提交于 2019-11-30 10:15:23
I have a method like this: (this is a generic method, and DYNAMIC_CLASS_TYPE will be changed in situation to other situation) Dim res = f.MyMethod(Of DYNAMIC_CLASS_TYPE)("select Id, Name from myTable") I want to create a dynamic class, based on my query's columns and then pass the class instead of DYNAMIC_CLASS_TYPE . How can I do this? Vahid Farahmandian I finally succeeded in doing it. My Code is as: Public Shared Function CreateClass(ByVal className As String, ByVal properties As Dictionary(Of String, Type)) As Type Dim myDomain As AppDomain = AppDomain.CurrentDomain Dim myAsmName As New

Create Class dynamically at runtime

由 拟墨画扇 提交于 2019-11-29 15:17:59
问题 I have a method like this: (this is a generic method, and DYNAMIC_CLASS_TYPE will be changed in situation to other situation) Dim res = f.MyMethod(Of DYNAMIC_CLASS_TYPE)("select Id, Name from myTable") I want to create a dynamic class, based on my query's columns and then pass the class instead of DYNAMIC_CLASS_TYPE . How can I do this? 回答1: I finally succeeded in doing it. My Code is as: Public Shared Function CreateClass(ByVal className As String, ByVal properties As Dictionary(Of String,
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