dom

How to set overflow-x with jQuery? Or: How to set css-properties with a '-' (dash)?

若如初见. 提交于 2021-01-18 05:01:25
问题 I would like to set the overflow-x css property with jQuery, but it doesn't work: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflow-x: 'scroll' }); How would I set properties that have a '-' (dash) in them? 回答1: You could use either camel-case: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflowX: 'scroll' }); Or quoted keys: $('.mySelector').css({ color: 'Red', overflow: 'auto', 'overflow-x': 'scroll' }); I would recommend quoted keys, I find it easier to tell 'at a

How to set overflow-x with jQuery? Or: How to set css-properties with a '-' (dash)?

▼魔方 西西 提交于 2021-01-18 05:01:23
问题 I would like to set the overflow-x css property with jQuery, but it doesn't work: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflow-x: 'scroll' }); How would I set properties that have a '-' (dash) in them? 回答1: You could use either camel-case: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflowX: 'scroll' }); Or quoted keys: $('.mySelector').css({ color: 'Red', overflow: 'auto', 'overflow-x': 'scroll' }); I would recommend quoted keys, I find it easier to tell 'at a

How to set overflow-x with jQuery? Or: How to set css-properties with a '-' (dash)?

独自空忆成欢 提交于 2021-01-18 05:01:05
问题 I would like to set the overflow-x css property with jQuery, but it doesn't work: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflow-x: 'scroll' }); How would I set properties that have a '-' (dash) in them? 回答1: You could use either camel-case: $('.mySelector').css({ color: 'Red', overflow: 'auto', overflowX: 'scroll' }); Or quoted keys: $('.mySelector').css({ color: 'Red', overflow: 'auto', 'overflow-x': 'scroll' }); I would recommend quoted keys, I find it easier to tell 'at a

How can I connect two parent node into one child node and how to make a tooltip for each node in the tree pragmatically? in D3 js (SVG)

谁说我不能喝 提交于 2021-01-14 09:12:09
问题 I have made a tree graph structure and it's working absolutely fine. But now I want to make a small change but unable to make that change. I want to connect the two-parent node into one child node...also I am trying to add a tooltip into each node pragmatically. For example - if you run the code, you will see it more clearly. I wanna make a child node of Hanna and mark which will be connected to a child node named "Eric". any idea how to achieve this? var svg = d3 .select("body") .append("svg

How can I connect two parent node into one child node and how to make a tooltip for each node in the tree pragmatically? in D3 js (SVG)

前提是你 提交于 2021-01-14 09:08:43
问题 I have made a tree graph structure and it's working absolutely fine. But now I want to make a small change but unable to make that change. I want to connect the two-parent node into one child node...also I am trying to add a tooltip into each node pragmatically. For example - if you run the code, you will see it more clearly. I wanna make a child node of Hanna and mark which will be connected to a child node named "Eric". any idea how to achieve this? var svg = d3 .select("body") .append("svg

How can I connect two parent node into one child node and how to make a tooltip for each node in the tree pragmatically? in D3 js (SVG)

不羁的心 提交于 2021-01-14 09:07:48
问题 I have made a tree graph structure and it's working absolutely fine. But now I want to make a small change but unable to make that change. I want to connect the two-parent node into one child node...also I am trying to add a tooltip into each node pragmatically. For example - if you run the code, you will see it more clearly. I wanna make a child node of Hanna and mark which will be connected to a child node named "Eric". any idea how to achieve this? var svg = d3 .select("body") .append("svg

Chrome Extension/Javascript - Iterate through an array of URLs and Fetch DOM for each

点点圈 提交于 2021-01-07 01:25:10
问题 I was wondering if anyone might be able to help me out? I am trying to write a Google Chrome Extension that loops through an array of URL's and grabs the DOM for each and outputs it somewhere (here just the console). Ideally I'd like this all to be done in the background rather than having to update the active tab... but not sure if this is possible - maybe for another question perhaps... For now though, my problem is that it will only fetch the DOM of the last URL in the array and ignores

What's the point of the second argument in element.classList.toggle?

筅森魡賤 提交于 2021-01-02 20:49:40
问题 From MDN: The toggle method has an optional second argument that will force the class name to be added or removed based on the truthiness of the second argument. For example, to remove a class (if it exists or not) you can call element.classList.toggle('classToBeRemoved', false); and to add a class (if it exists or not) you can call element.classList.toggle('classToBeAdded', true); To my understanding, the classList is a token list, and lists, unlike arrays, can't have duplicate items. So

What's the point of the second argument in element.classList.toggle?

蓝咒 提交于 2021-01-02 20:49:13
问题 From MDN: The toggle method has an optional second argument that will force the class name to be added or removed based on the truthiness of the second argument. For example, to remove a class (if it exists or not) you can call element.classList.toggle('classToBeRemoved', false); and to add a class (if it exists or not) you can call element.classList.toggle('classToBeAdded', true); To my understanding, the classList is a token list, and lists, unlike arrays, can't have duplicate items. So

JavaScript - addEventListener “click” doesn't work

╄→尐↘猪︶ㄣ 提交于 2021-01-01 08:07:46
问题 I want take a value from input after click on button but all the time function var buttonToBinary = document.querySelector("#toBinary"); buttonToBinary.addEventListener('click', console.log(getInput())); function getInput() { return document.querySelector("#inputSector").value; } <input type="text" name="userInput" id="inputSector" value="aa" /> <button id="toBinary" type="submit">to binary</button> getInput() was started on load page. Please, help me. 回答1: When you do: buttonToBinary