doctrine-orm

Doctrine - how to check if a collection contains an entity

自作多情 提交于 2020-12-05 10:02:11
问题 I have two entities User and Article with many-to-many relation as Article can have many authors. class User { /** @var string */ public $name; /** @var Collection<Article> */ public $articles; } class Article { /** @var string */ public $title; /** @var Collection<User> */ public $authors; } How I can find all Articles with specified (co)author using DQL? 回答1: Use MEMBER OF expression. Your DQL query could like like SELECT art FROM Article art WHERE :user MEMBER OF art.authors or using query

What is the difference between JOIN ON and JOIN WITH in Doctrine2?

一个人想着一个人 提交于 2020-12-02 07:07:57
问题 What is the difference between JOIN ON and JOIN WITH in Doctrine2? I couldn't find any relevant info in the manual. 回答1: ON replaces the original join condition, WITH adds a condition to it. Example : [Album] ---OneToMany---> [Track] Case One DQL FROM Album a LEFT JOIN a.Track t WITH t.status = 1 Will translate in SQL FROM Album a LEFT JOIN Track t ON t.album_id = a.id AND t.status = 1 Case Two DQL FROM Album a LEFT JOIN a.Track t ON t.status = 1 Will translate in SQL FROM Album a LEFT JOIN

What is the difference between JOIN ON and JOIN WITH in Doctrine2?

僤鯓⒐⒋嵵緔 提交于 2020-12-02 07:05:15
问题 What is the difference between JOIN ON and JOIN WITH in Doctrine2? I couldn't find any relevant info in the manual. 回答1: ON replaces the original join condition, WITH adds a condition to it. Example : [Album] ---OneToMany---> [Track] Case One DQL FROM Album a LEFT JOIN a.Track t WITH t.status = 1 Will translate in SQL FROM Album a LEFT JOIN Track t ON t.album_id = a.id AND t.status = 1 Case Two DQL FROM Album a LEFT JOIN a.Track t ON t.status = 1 Will translate in SQL FROM Album a LEFT JOIN

Difference between Symfony / Doctrine commands make:migration and doctrine:migrations:diff

依然范特西╮ 提交于 2020-11-29 05:55:56
问题 What are the differences between Symfony console command make:migration and doctrine:migrations:diff? 回答1: make:migration will create empty file for you so you can write your custom migration doctrine:migrations:diff will compare your current database schema with entities mappings and if there is difference then it will create migration so you can update you database schema to reflect your entities mappings 回答2: There is no difference between these two commands. make:migration is simply a

Difference between Symfony / Doctrine commands make:migration and doctrine:migrations:diff

吃可爱长大的小学妹 提交于 2020-11-29 05:55:14
问题 What are the differences between Symfony console command make:migration and doctrine:migrations:diff? 回答1: make:migration will create empty file for you so you can write your custom migration doctrine:migrations:diff will compare your current database schema with entities mappings and if there is difference then it will create migration so you can update you database schema to reflect your entities mappings 回答2: There is no difference between these two commands. make:migration is simply a

Difference between Symfony / Doctrine commands make:migration and doctrine:migrations:diff

匆匆过客 提交于 2020-11-29 05:54:34
问题 What are the differences between Symfony console command make:migration and doctrine:migrations:diff? 回答1: make:migration will create empty file for you so you can write your custom migration doctrine:migrations:diff will compare your current database schema with entities mappings and if there is difference then it will create migration so you can update you database schema to reflect your entities mappings 回答2: There is no difference between these two commands. make:migration is simply a

Output array in Twig

狂风中的少年 提交于 2020-11-27 04:47:43
问题 I trying to output an array from the database to the screen. In my entity: /** * @ORM\Column(type="array", nullable=true) */ private $category; In my twig template: {% for category in user.profile.category %} {{ category }} {% endfor %} Error: Array to string conversion in ... Where is my mistake? 回答1: TWIG doesn't know how you want to display your table. By the way, you should consider naming your variable $categories instead of $category , as you table contains several categories. Then try