django-guardian

ViewFlow and django-guardian

蓝咒 提交于 2021-02-08 08:11:41
问题 I want to make use of django-guardian 's object permissions and grant specific rights for specific users to one or more Django users. I have tried to add some permissions to my Process class like this: class TestProcess(Process): title = models.CharField(max_length=64) something = models.ForeignKey(ForInheritage, null=True, on_delete=models.CASCADE) no_approval = models.BooleanField(default=False) approved = models.BooleanField(default=False) def something_is_approved(self): try: return self

ViewFlow and django-guardian

醉酒当歌 提交于 2021-02-08 08:10:50
问题 I want to make use of django-guardian 's object permissions and grant specific rights for specific users to one or more Django users. I have tried to add some permissions to my Process class like this: class TestProcess(Process): title = models.CharField(max_length=64) something = models.ForeignKey(ForInheritage, null=True, on_delete=models.CASCADE) no_approval = models.BooleanField(default=False) approved = models.BooleanField(default=False) def something_is_approved(self): try: return self

ViewFlow and django-guardian

℡╲_俬逩灬. 提交于 2021-02-08 08:10:23
问题 I want to make use of django-guardian 's object permissions and grant specific rights for specific users to one or more Django users. I have tried to add some permissions to my Process class like this: class TestProcess(Process): title = models.CharField(max_length=64) something = models.ForeignKey(ForInheritage, null=True, on_delete=models.CASCADE) no_approval = models.BooleanField(default=False) approved = models.BooleanField(default=False) def something_is_approved(self): try: return self

ViewFlow and django-guardian

本小妞迷上赌 提交于 2021-02-08 08:10:19
问题 I want to make use of django-guardian 's object permissions and grant specific rights for specific users to one or more Django users. I have tried to add some permissions to my Process class like this: class TestProcess(Process): title = models.CharField(max_length=64) something = models.ForeignKey(ForInheritage, null=True, on_delete=models.CASCADE) no_approval = models.BooleanField(default=False) approved = models.BooleanField(default=False) def something_is_approved(self): try: return self

django.db.utils.OperationalError: no such table: auth_user

拥有回忆 提交于 2020-01-04 06:15:15
问题 After I install Django-userena,there is an error my django version :1.9.5 I just install django-userena step by step ,but when i migrate it ,an error happend and I don't how to solve it. Traceback (most recent call last): File "manage.py", line 12, in <module> execute_from_command_line(sys.argv) File "C:\Python27\lib\site-packages\django\core\management\__init__.py", line 353, in execute_from_command_line utility.execute() File "C:\Python27\lib\site-packages\django\core\management\__init__.py

Can django-guardian and django-rules be used together?

醉酒当歌 提交于 2020-01-01 05:39:08
问题 I'd like to be able to create per-object permissions using django-guardian. But I'd like to add a layer of logic surrounding these permissions. For example if someone has edit_book permission on a Book , then their permission to edit Pages in that book should be implicit. The rules package seems ideal. 回答1: The following appears to work: import rules import guardian @rules.predicate def is_page_book_editor(user, page): return user.has_perm('books.edit_book', page.book) @rules.predicate def is

How to handle per object permission in Django nowadays?

穿精又带淫゛_ 提交于 2019-12-20 09:46:03
问题 I was about to use django-guardian until I came across the following in the official documentation: https://docs.djangoproject.com/en/1.8/topics/auth/customizing/#handling-authorization-in-custom-backends Permissions can be set not only per type of object, but also per specific object instance. By using the has_add_permission(), has_change_permission() and has_delete_permission() methods provided by the ModelAdmin class, it is possible to customize permissions for different object instances

Django, South, and Guardian: Migrate

删除回忆录丶 提交于 2019-12-12 05:18:23
问题 I have two users, mh00h1 and mh00h2. I also have modelA that defines the following in my models.py: class Meta: permissions = ( ('read','read'), ('write','write'), ) From a shell, I went to set permissions: >>>> frhde = create modelA instance >>>> assign_perm('read', mh00h2, frhde) DoesNotExist: Permission matching query does not exist. Lookup parameters were {'codename': u'read', 'content_type': <ContentType: modelA>} I realized that South didn't migrate my models after I added class Meta to

Set object-level permission with django-rest-framework

吃可爱长大的小学妹 提交于 2019-12-12 02:45:20
问题 Trying to manage django-guardian object-level permissions with django-rest-framework the most cleanly and canon possible. I want to assign a read permission (module.view_object) of an object to to the user making the request when performing a POST. My class-based view: class ObjectList(ListCreateAPIView): queryset = Object.objects.all() serializer_class = ObjectSerializer filter_backends = (DjangoObjectPermissionsFilter,) # MyObjectPermissions inherit from DjangoObjectPermissions and just #

Django: Can't override admin templates when they are already overridden?

随声附和 提交于 2019-12-10 09:56:12
问题 To add some content to a Django admin view of a model, I want to override the change_form.html template. According to the documentation I would need to create a file change_form.html in a the folder /project-path/templates/admin/appname/modelname/ . Of course I need to make sure, that this path is also available in TEMPLATE_DIRS . Such a file could look like this: {% extends "admin/change_form.html" %} {% load i18n %} {% block after_field_sets %} SOME CONTENT {% endblock %} However, I make