divide-and-conquer | 易学教程

Tromino program using Graphics

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问题 I have my tromino program. However, now that it needs to be converted to graphics (which I left for last). I am pretty confused on how to do this, I know some basics about graphics but looking at my program it seems I might have to do a lot of modification to make it work. Is there a simple way to do this? Basically I need to convert the trominos which I have as numbers right now onto a chessboard (which the size is specified by the user). And the deficient square being any color that

How to add all vector elements using divide and conquer and iterators?

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问题 I needed to write a function that sums up all elements of a vector. Specifications are that it has to be done by recursion and the only parameters input would be iterators. The function should:Divide the vector in half, recurse on the left hand side, recurse on the right hand side, return the sum of both sides. I wrote the code below but I am getting an incorrect answer. int sumVectorRecurse(vector<int>::iterator left, vector<int>::iterator right) { if (left != right){ int midPosition =

Problem with Divide and Conquer Maximum Consecutive Subarray (MCS)

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问题 I want to find a nonempty, contiguous subarray for a given input array of integers, that can have duplicate values. I tried the divide and conquer method to find the maximum consecutive subarray of an array, which returns a different result as expected. Please find the code below. private static int maxSumRec(int[] a, int low, int high) { int leftSum = 0, rightSum = 0; int sum = 0; if (low == high) { // Base case return a[low]; } int mid = (low + high) >> 1; // (low + high) / 2 int maxLeftSum

Divide and conquer - why does it work?

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问题 I know that algorithms like mergesort and quicksort use the divide-and-conquer paradigm, but I'm wondering why does it work in lowering the time complexity... why does usually a "divide and conquer" algorithm work better than a non-divide-and-conquer one? 回答1: Divide and conquer works, because the mathematics supports it! Consider a few divide and conquer algorithms: 1) Binary search: This algorithm reduces your input space to half each time. It is intuitively clear that this is better than a

Grouping Symbols Maximum Length Balanced Subsequence

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问题 Consider B to be a sequence of grouping symbols (, ), [, ], {, and }. B is called a Balanced sequence if it is of length 0 or B is of one of the following forms: { X } Y or [ X ] Y or { X } Y where X and Y are Balanced themselves. Example for Balanced : ( ) - { [ ] ( ) } [ ] - ... Now the question is to find an efficient algorithm to find maximum length balanced subsequence (not necessarily contiguous) of a given input which is an string of these grouping symbols. For example if input is ( )

Matrix Multiplication using divide and conquer approach [closed]

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问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . I am a beginner in programming and just learned new concepts and started writing code for matrix multiplication but I got confused in pointers and others so I am uploading my code here in seek of guidelines. #include <stdio.h> #include <stdlib.h> int **matrixMultiply(int A[][8], int B[][8], int row); int main()

Simple Divide and Conquer Example

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问题 Here is my test divide and conquer program, but it gives me an error. I am heading in the right direction? public class getSum { static int sum = 0; public static void main(String[] args) { int[] numbers = {2,2,2,2,2,2,2,2}; int amount = 0; amount = sumArray(0,numbers.length,numbers); System.out.print(amount); } public static int sumArray(int first, int last, int[] A){ int index = last - first; if(index == 1){ return sum; }else if(index <= 4 && index > 1){ for(int i = first; first < last; i++

How to solve “fixed size maximum subarray” using divide and conquer approach?

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问题 Disclaimer: I know this problem can be solved with single pass of array very efficiently, but I am interested in doing this with divide and conquer because it is bit different than typical problems we tackle with divide and conquer. Suppose you are given a floating point array X[1:n] of size n and interval length l. The problem is to design a divide and conquer algorithm to find the sub-array of length l from the array that has the maximum sum. Here is what I came up with.For array of length

Is Quick Sort a Divide & Conquer approach? [closed]

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问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 2 years ago . I consider Merge sort as divide and conquer because, Divide - Array is literally divided into sub arrays without any processing (compare/swap), and the problem sized is halved/Quartered/.... Conquer - merge() those sub arrays by processing (compare/swap) Code gives an

Divide and Conquer Algo to find maximum difference between two ordered elements

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Given an array arr[] of integers, find out the difference between any two elements such that larger element appears after the smaller number in arr[]. Max Difference = Max { arr[x] - arr[y] | x > y } Examples: If array is [2, 3, 10, 6, 4, 8, 1, 7] then returned value should be 8 (Diff between 10 and 2). If array is [ 7, 9, 5, 6, 3, 2 ] then returned value should be 2 (Diff between 7 and 9) My Algorithm: I thought of using D&C algorithm. Explanation 2, 3, 10, 6, 4, 8, 1, 7 then 2,3,10,6 and 4,8,1,7 then 2,3 and 10,6 and 4,8 and 1,7 then 2 and 3 10 and 6 4 and 8 1 and 7 Here as these elements