dimensional

how to find determinant [closed]

由 匆匆过客 提交于 2020-05-17 06:23:40
问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 20 days ago . double Determinant(double *X, int N){ /*Solution*/ } int main(void) { double X[] = {3, 1, 2, 7, 9, 2, 4, 6, 9}; if (Determinant(X,3) == 164) { printf("✓"); } } how to find one dimensional array NxN determinant matrix? Can someone help me? thanks in advance. 回答1: A determinant is commonly computed

how to find determinant [closed]

由 懵懂的女人 提交于 2020-05-17 06:22:27
问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 20 days ago . double Determinant(double *X, int N){ /*Solution*/ } int main(void) { double X[] = {3, 1, 2, 7, 9, 2, 4, 6, 9}; if (Determinant(X,3) == 164) { printf("✓"); } } how to find one dimensional array NxN determinant matrix? Can someone help me? thanks in advance. 回答1: A determinant is commonly computed

VB .NET: How to get reference to a row in a 2D-array

由 馋奶兔 提交于 2020-01-05 02:53:47
问题 I have a function that returns a 1D-array like this: Public Function KeyConvert([args]) As Byte() and a 2 dimension array: Public KeyList(15, 5) As Byte Which can be seen as 15 rows,each row is a 5 element array, as we all already knew. Now I want to call the function and assign the result (which is a 1D array) to a row (say row 4) in the KeyList array. At first I thought the code should be like Keylist(4) = KeyConvert([args]) But that didn't work. I cannot find a way to reference to that

Creating 2 dimensional list matrix

由 廉价感情. 提交于 2019-12-31 04:54:04
问题 How do you create a list-based matrix of 1 's with given row and column counts? For example, like: row=3,column=4 -> [[1,1,1,1],[1,1,1,1],[1,1,1,1]] 回答1: You can do this with replicate : onesMatrix rows cols = replicate rows (replicate cols 1) 回答2: Here's an alternative method using list comprehension. Let's have a look at the basics: Prelude> [ 2*x | x <- [1..4] ] [2,4,6,8] So that gives you one number for each element in the list [1..4] . Why not, instead of doubling x , just have a 1 :

Check and see if an element in a two-dimensional array is of a certain data type

由 ≯℡__Kan透↙ 提交于 2019-12-25 05:49:05
问题 I'm writing a method that checks to see if the text file being passed into the constructor of my instantiable class contains non-numeric data. Specifically, it matters if the data cannot be represented as a double. That is, chars are not okay, and integers are. What I have so far is: private boolean nonNumeric(double[][] grid) throws Exception { boolean isNonNumeric = false; for (int i = 0; i < grid.length; i++) for (int j = 0; j < grid[i].length; j++) { if (grid[i][j] != ) { isNonNumeric =

java two dimensional array sorting

由 痴心易碎 提交于 2019-12-13 04:32:57
问题 Write a program that prompts the user to enter a nxn matrix of double values and displays a new matrix which has the columns of the initial matrix sorted. You may use any sorting algorithm to solve the problem; please specify the name of the used sorting algorithm into your code header. Your program must implement a sorting algorithm; you cannot use the sorting methods provided in the Array class. The sorting should be implemented into a method, in which a new array is returned and the

Java method for recursive matrix multiply?

由 馋奶兔 提交于 2019-12-12 01:06:47
问题 So basically, what I want to do is make a method that takes 2 matrices as arguments, and multiplies them. This is a school task, and Im asked to solve this by using recursive "Divide and Conquer". This is my code so far: public class RecMult { public int[][] calc(int[][] a, int[][] b) { int n = a.length; int[][] c = new int[n][n]; if (n == 1) { c[0][0] = a[0][0] * b[0][0]; } else { int sub = a.length / 2; int[][] smalla11 = new int[sub][sub]; int[][] smalla12 = new int[sub][sub]; int[][]

Convert One Dimensional Arrary to Two Dimensional in C++

由 落花浮王杯 提交于 2019-12-07 05:28:31
问题 I have a 49 space one dimensional array declared as int boardArray [49]; and I also have a two dimensional 7x7 array declared as int boardArrayTwo [7][7]' I am trying to use nested for loops to throw the one dimensional array into the two dimensional array here is the code I am using to test it. for (int i = 0; i > 50; ++i) { boardArray[i] = i; //fills the array with ints 0 - 48 to test } for (int x = 0; x >= 7; ++x) { for (int k = 0; k >= 7; ++k) { for (int n = 0; n >= 49; ++n) {

Convert One Dimensional Arrary to Two Dimensional in C++

由 狂风中的少年 提交于 2019-12-05 10:23:31
I have a 49 space one dimensional array declared as int boardArray [49]; and I also have a two dimensional 7x7 array declared as int boardArrayTwo [7][7]' I am trying to use nested for loops to throw the one dimensional array into the two dimensional array here is the code I am using to test it. for (int i = 0; i > 50; ++i) { boardArray[i] = i; //fills the array with ints 0 - 48 to test } for (int x = 0; x >= 7; ++x) { for (int k = 0; k >= 7; ++k) { for (int n = 0; n >= 49; ++n) { boardArrayTwo[x][k] = boardArray[n]; cout << boardArrayTwo[x][k] << " " << endl; } } } I tried running this but

C: Size of two dimensional array

由 一笑奈何 提交于 2019-12-04 16:30:50
问题 I need some help counting the rows and columns of a two dimensional array. It seems like I can't count columns? #include <stdio.h> int main() { char result[10][7] = { {'1','X','2','X','2','1','1'}, {'X','1','1','2','2','1','1'}, {'X','1','1','2','2','1','1'}, {'1','X','2','X','2','2','2'}, {'1','X','1','X','1','X','2'}, {'1','X','2','X','2','1','1'}, {'1','X','2','2','1','X','1'}, {'1','X','2','X','2','1','X'}, {'1','1','1','X','2','2','1'}, {'1','X','2','X','2','1','1'} }; int row = sizeof
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