dimension

View of the application javafx

点点圈 提交于 2019-11-29 16:47:48
i was searching in google for hours and i still cant find the right answer, so i have a last chance to come here and ask. i'm making school year JAVA FX project. I'm using NetBeans. I have a point that i can see on the application i have. The problem is: I would like to have a big map (background) and I need to be able to move with my view. For example move by 50 to the right (x). I have Application where I use Stage, Scene, StackPane. I heard something about Dimensions in Java, but i can't use it in javafx application. Is there something similar, what can I use in my Application? Thank you

Multiply 2D Matrix with vector to span third dimension - MATLAB

China☆狼群 提交于 2019-11-29 15:33:18
As I am trying to multiply a m x n Matrix with a p-dimensional vector, I am stumbling across some difficulties. Trying to avoid for loops, here is what I am looking to achieve enter code here M = [1 2 3; p = [1;2;3] 4 5 6; 7 8 9] I want to obtain a 3x3x3 matrix, where the slices in third dimension are simply the entries of M multiplied by the respective entry in p . Help is much appreciated You can use bsxfun with permute for a vectorized (no-loop) approach like so - out = bsxfun(@times,M,permute(p(:),[3 2 1])) You would end up with - out(:,:,1) = 1 2 3 4 5 6 7 8 9 out(:,:,2) = 2 4 6 8 10 12

Fortran array inside array [closed]

本秂侑毒 提交于 2019-11-29 15:27:31
I am trying to create an array in Fortran similar to a cell in MATLAB. Basically (for example) I am trying to create an array X(10) where the element X(1) is an array with dimension (20,2), X(2) is an array with dimension (25,2), etc. How can I do this? The equivalent for your specific case is achieved using a derived type, that contains a single component. The cell array corresponds to an array of that derived type, the arrays that sit inside each element of the cell array are then the array components of each array element. Something like: TYPE Cell ! Allocatable component (F2003) allows

Android get layout height and width in a fragment

倖福魔咒の 提交于 2019-11-29 06:13:52
问题 I am working on a fragment and I want to get the dimension of a layout contained in the xml fragment layout . When I try the code RelativeLayout myLayout = view.findViewById(R.id.myLayout); myLayout.getHeight(); it returns 0. I need these dimensions to put inside myLayout other objects. I try to use: myLayout.getViewTreeObserver().addOnGlobalLayoutListener( new ViewTreeObserver.OnGlobalLayoutListener(){ @Override public void onGlobalLayout() { mHeight = myLayout.getHeight(); mWidth= myLayout

My JFrame always becomes a few pixels too big.

自闭症网瘾萝莉.ら 提交于 2019-11-28 14:05:36
I am working on this game in Java, and I just rewrote all my window related code from being based on java.awt to javax.swing. Soon after, I realized that things were a bit more complicated now, and so i did some research and and found out how to draw things, how to set the size of a JFrame, etc. But for some reason, the size of my JFrame always goes 10 pixels beyond the size I've specified it to become. In this case, I wanted it to be 640 by 640 pixels. Here's my code: package chrononaut; import java.awt.*; import java.io.IOException; import javax.imageio.ImageIO; import javax.swing.*;

How to get screen's physical size (i.e. in inches)?

两盒软妹~` 提交于 2019-11-28 09:52:56
I'm trying to figure out how to get the physical dimensions of a device's screen via Javascript. So far, my conclusion is that it's currently impossible, but I hope someone can prove me wrong :). So far I have tried to get this information by finding the device's DPI, but it seems there is no way to get the correct value here, as all devices I have tested (some HDPI & XHDPI Android devices, an iPhone4S, an iPad 2 and an iPad 3) report 96DPI. The first method of obtaining the DPI I tried is one you can find everywhere on the internet: create a div with a CSS width of 1in , get its clientWidth

Value equals to match_parent or fill_parent in dimens.xml?

倾然丶 夕夏残阳落幕 提交于 2019-11-28 04:50:58
Based on here on XML Attributes section I specify following in my dimens.xml : <dimen name="match_parent">-1dp</dimen> <dimen name="main_left_menu_user_account_width">@dimen/match_parent</dimen> <dimen name="main_left_menu_user_account_height">@dimen/match_parent</dimen> Then I use the both dimensions in my layout: <ImageView android:id="@+id/userAccountImage" android:background="@drawable/user_account" android:layout_width="@dimen/main_left_menu_user_account_width" android:layout_height="@dimen/main_left_menu_user_account_height" /> Then, when I preview to Graphical Layout , it complains: You

Measuring text width/height without rendering

冷暖自知 提交于 2019-11-27 21:15:10
Is there any way to get an estimate for text width without rendering the actual elements? Something like canvas TextMetrics? Case: I need to estimate element heights for ReactList. To do that I'd need to know roughly how much space the text elements will need (or how many lines will they span). eg. render(){ return <div><SomeComponentWithKnownDims/><p>{this.props.someText}</p></div>; } If I knew how wide someText would be rendered into one line and how long the line would be, I could easily come up with a decent estimate for the components height. EDIT: Note that this is quite performance

How do I set the size of the visible area of a form, minus heading and borders?

做~自己de王妃 提交于 2019-11-27 14:38:25
I would like to set my form to be exactly 300*300 excluding heading and borders. If I use Size property, it does include these values. Is there any way how to do it? Yetti You have two options, as follows: To remove heading and borders from a Form, disable the Form's FormBorderStyle property. Set the interior of the form with the ClientSize property, as follows: this.ClientSize = new Size(300, 300); Why not just factor in the size of the border and the title bar? int BorderWidth = (this.Width – this.ClientSize.Width) /2; int TitlebarHeight = this.Height – this.ClientSize.Height – 2 *

Difference between android dimension: pt and dp

蹲街弑〆低调 提交于 2019-11-27 06:07:38
The documentation says that 160 dp (density-independent) equals 1 inch. And 72 pt is also 1 inch. So I don't see why android define a dp measurement while it seems to work the same as points. Can anybody explain that? Why should I use dp if I can use pt? John Leehey The Android documentation used to incorrectly state that 160 dp always equals 1 inch regardless of screen density. This was reported as a bug which was accepted and the documentation updated. From the updated documentation: 160 dp will NOT always equal 1 inch, it will vary with different screen sizes and densities. On a screen with