dictionary

Convert tuple of tuples to a dictionary with key value pair

由 眉间皱痕 提交于 2021-02-16 08:39:11
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

Convert tuple of tuples to a dictionary with key value pair

由 本小妞迷上赌 提交于 2021-02-16 08:37:55
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

Searching the Web UVA

由 筅森魡賤 提交于 2021-02-15 17:12:08
  The word “search engine” may not be strange to you. Generally speaking, a search engine searches the web pages available in the Internet, extracts and organizes the information and responds to users’ queries with the most relevant pages. World famous search engines, like GOOGLE, have become very important tools for us to use when we visit the web. Such conversations are now common in our daily life: “What does the word like ∗ ∗ ∗ ∗ ∗∗ mean?” “Um. . . I am not sure, just google it.”   In this problem, you are required to construct a small search engine. Sounds impossible, does it? Don’t worry

How to use dict.get() with multidimensional dict?

由 我怕爱的太早我们不能终老 提交于 2021-02-15 10:47:07
问题 I have a multidimensional dict, and I'd like to be able to retrieve a value by a key:key pair, and return 'NA' if the first key doesn't exist. All of the sub-dicts have the same keys. d = { 'a': {'j':1,'k':2}, 'b': {'j':2,'k':3}, 'd': {'j':1,'k':3} } I know I can use d.get('c','NA') to get the sub-dict if it exists and return 'NA' otherwise, but I really only need one value from the sub-dict. I'd like to do something like d.get('c['j']','NA') if that existed. Right now I'm just checking to

Unity AssetBundle 教程

由 自古美人都是妖i 提交于 2021-02-14 21:55:05
Unity AssetBundle 教程 AssetBundle是Unity用来处理资源热更新的，下面简单介绍AssetBundle的所有操作。本教程使用的Unity版本：Unity 2018.2.12f1 (64-bit) AssetBundle打包 设置AssetBundle名字 手动设置 打包之前按照上图所示的方法，设置一下AssetBundle的名字。 自动设置 将需要进行AssetBundle打包的图片按照“UI_”的前缀命名，然后根据图片的父目录来设置AssetBundle的名字。如下所示 然后新建一个ImageImporter.cs文件放入Editor目录下 using UnityEngine; using UnityEditor; /// <summary> /// 根据名字前缀自动化设置图片的格式以及TAG等设置 /// </summary> public class ImageImporter : AssetPostprocessor { /// <summary> /// 图片导入之前调用，可设置图片的格式、spritePackingTag、assetBundleName等信息 /// </summary> void OnPreprocessTexture() { TextureImporter importer = (TextureImporter

Ogg

由 断了今生、忘了曾经 提交于 2021-02-13 19:04:46
说明：这篇文章将介绍如何配置oracle到mysql的ogg同步 源端：ip-192.168.56.11 数据库类型-oracle 11.2.0.4 目标端：ip-192.168.56.71 数据库类型-mysql 5.7.25 1. 解压并准备目录 （源端） su - oracle mkdir -p /home/oracle/ogg1/ tar -xvf fbo_ggs_Linux_x64_ora11g_64bit.tar -C /home/oracle/ogg1 （目标端） su - mysql mkdir -p /home/mysql/ogg2/ tar -xvf ggs_Linux_x64_MySQL_64bit.tar -C /home/mysql/ogg2 创建socket软链接，mysql ogg默认使用/tmp/mysql.sock 查看mysql socket的位置 (root@localhost)[(none)]> show variables like 'socket'; +---------------+-----------------------------+ | Variable_name | Value | +---------------+-----------------------------+ | socket | /opt/mydata

Using a dict to translate numbers to letters in python

由 独自空忆成欢 提交于 2021-02-13 17:40:22
问题 I have a string 'alphabet' with all the letters in the alphabet and a list of ints corresponding to those those letters (0-25). Ex: num_list = [5,3,1] would translate into letter_list = ['f','d','b'] I currently can translate with: letter_list = [alphabet[a] for a in num_list] However, I would like to use a dict for the same thing, retrieve 'letter' keys from dict with 'number' values. alpha_dict = {'a':0,'b':1,'c':2}... etc How do I change my statement to do this? 回答1: Simply iterate through

Using a dict to translate numbers to letters in python

由 三世轮回 提交于 2021-02-13 17:38:18
问题 I have a string 'alphabet' with all the letters in the alphabet and a list of ints corresponding to those those letters (0-25). Ex: num_list = [5,3,1] would translate into letter_list = ['f','d','b'] I currently can translate with: letter_list = [alphabet[a] for a in num_list] However, I would like to use a dict for the same thing, retrieve 'letter' keys from dict with 'number' values. alpha_dict = {'a':0,'b':1,'c':2}... etc How do I change my statement to do this? 回答1: Simply iterate through

Using a dict to translate numbers to letters in python

由 自古美人都是妖i 提交于 2021-02-13 17:37:34
问题 I have a string 'alphabet' with all the letters in the alphabet and a list of ints corresponding to those those letters (0-25). Ex: num_list = [5,3,1] would translate into letter_list = ['f','d','b'] I currently can translate with: letter_list = [alphabet[a] for a in num_list] However, I would like to use a dict for the same thing, retrieve 'letter' keys from dict with 'number' values. alpha_dict = {'a':0,'b':1,'c':2}... etc How do I change my statement to do this? 回答1: Simply iterate through

IndexError: string index out of range:

由 此生再无相见时 提交于 2021-02-13 17:32:27
问题 I'm trying take a .txt file populated by 88 rows, each of which has two characters separated by a space, copy the first character in each row into a list #1, copy the second character of each list into a list #2 and then populate a dictionary with those two lists. Something, however, is going wrong when I try to copy down the data from the file into my lists. Could you tell me what I'm not doing correctly? I keep getting this error: "IndexError: string index out of range" at the line where I
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