dendrogram

Tree cut and Rectangles around clusters for a horizontal dendrogram in R

 ̄綄美尐妖づ 提交于 2019-11-29 03:07:56
问题 I am trying to plot the results of a hierarchical clustering in R as a dendrogram, with rectangles identifying clusters. The following code does the trick for a vertical dendrogram, but for a horizontal dendrogram, ( horiz=TRUE ), the rectangles are not drawn. Is there any way to do the same for horizontal dendrograms too. library("cluster") dst <- daisy(iris, metric = c("gower"), stand = FALSE) hca <- hclust(dst, method = "average") plot(as.dendrogram(hca), horiz = FALSE) rect.hclust(hca, k

Custom cluster colors of SciPy dendrogram in Python (link_color_func?)

橙三吉。 提交于 2019-11-29 03:02:34
问题 I want to color my clusters with a color map that I made in the form of a dictionary (i.e. {leaf: color} ). I've tried following https://joernhees.de/blog/2015/08/26/scipy-hierarchical-clustering-and-dendrogram-tutorial/ but the colors get messed up for some reason. The default plot looks good, I just want to assign those colors differently. I saw that there was a link_color_func but when I tried using my color map ( D_leaf_color dictionary) I got an error b/c it wasn't a function. I've

sklearn agglomerative clustering linkage matrix

此生再无相见时 提交于 2019-11-29 01:43:32
问题 I'm trying to draw a complete-link scipy.cluster.hierarchy.dendrogram, and I found that scipy.cluster.hierarchy.linkage is slower than sklearn.AgglomerativeClustering. However, sklearn.AgglomerativeClustering doesn't return the distance between clusters and the number of original observations, which scipy.cluster.hierarchy.dendrogram needs. Is there a way to take them? 回答1: I made a scipt to do it without modifying sklearn and without recursive functions. Before using note that: Merge

Change Dendrogram leaves

与世无争的帅哥 提交于 2019-11-29 00:13:56
I want to modify the properties of the leaves in a dendrogram produced from plot of an hclust object. Minimally, I want to change the colors, but any help you can provide will be appreciated. I did try to google the answer, but but every solution that I saw seemed alot harder than what I would have guessed. A while ago, Joris Meys kindly provided me with this snippet of code that changes the color of leaves. Modify it to reflect your attributes. clusDendro <- as.dendrogram(Clustering) labelColors <- c("red", "blue", "darkgreen", "darkgrey", "purple") ## function to get colorlabels colLab <-

How do you compare the “similarity” between two dendrograms (in R)?

天涯浪子 提交于 2019-11-28 21:12:40
问题 I have two dendrograms which I wish to compare to each other in order to find out how "similar" they are. But I don't know of any method to do so (let alone a code to implement it, say, in R). Any leads ? UPDATE (2014-09-13): Since asking this question, I have written an R package called dendextend, for the visualization, manipulation and comparison of dendrogram. This package is on CRAN and comes with a detailed vignette. It includes functions such as cor_cophenetic , cor_bakers_gamma and Bk

how to convert a data.frame to tree structure object such as dendrogram

穿精又带淫゛_ 提交于 2019-11-28 20:34:12
问题 I have a data.frame object. For a simple example: > data.frame(x=c('A','A','B','B','B'), y=c('Ab','Ac','Ba', 'Ba','Bd'), z=c('Abb','Acc','Bad', 'Bae','Bdd')) x y z 1 A Ab Abb 2 A Ac Acc 3 B Ba Bad 4 B Ba Bae 5 B Bd Bdd there are a lot more rows and columns in the actual data. how could I create a nested tree structure object of dendrogram like this: |---Ab---Abb A---| | |---Ac---Acc --| /--Bad | |---Ba-------| B---| \--Bae |---Bb---Bdd 回答1: data.frame to Newick I did my PhD in computational

How to colour the labels of a dendrogram by an additional factor variable in R

混江龙づ霸主 提交于 2019-11-28 11:23:51
I have produced a dendrogram after running hierarchical clustering analysis in R using the below code. I am now trying to colour the labels according to another factor variable, which is saved as a vector. The closest that I have come to achieving this is to colour code the branches using the ColourDendrogram function in the sparcl package. If possible, I would prefer to colour-code the labels. I have found answers to a similar questions at the following links Color branches of dendrogram using an existing column & Colouring branches in a dendrogram in R , but I have not been able to work out

Associated Labels in a dendrogram plot - MATLAB

喜你入骨 提交于 2019-11-28 08:44:40
问题 I have the following set of data stored in file stations.dat : Station A 305.2 321.1 420.9 383.5 311.7 197.1 160.2 113.9 60.5 60.5 64.8 154.3 Station B 281.1 304.0 353.1 231.9 84.6 20.9 11.7 11.9 31.1 75.8 133.0 235.3 Station C 312.3 342.2 366.2 335.2 200.1 74.4 45.9 27.5 24.0 53.6 87.7 177.0 Station D 402.2 524.5 554.9 529.5 347.5 176.8 120.2 35.0 12.6 13.3 14.0 61.6 Station E 261.3 262.7 282.3 232.6 103.8 33.2 16.7 33.2 111.0 149.0 184.8 227.0 By using the following commands, Z = linkage

How do I create a radial cluster like the following code-example in Python?

僤鯓⒐⒋嵵緔 提交于 2019-11-28 05:07:42
I've found several examples on how to create these exact hierarchies (at least I believe they are) like the following here stackoverflow.com/questions/2982929/ which work great, and almost perform what I'm looking for. [EDIT]Here's a simplified version of Paul 's code, which now should be easier for someone to help get this into a radial cluster instead of this current cluster shape import scipy import pylab import scipy.cluster.hierarchy as sch def fix_verts(ax, orient=1): for coll in ax.collections: for pth in coll.get_paths(): vert = pth.vertices vert[1:3,orient] = scipy.average(vert[1:3

how to plot and annotate hierarchical clustering dendrograms in scipy/matplotlib

这一生的挚爱 提交于 2019-11-28 02:57:29
I'm using dendrogram from scipy to plot hierarchical clustering using matplotlib as follows: mat = array([[1, 0.5, 0.9], [0.5, 1, -0.5], [0.9, -0.5, 1]]) plt.subplot(1,2,1) plt.title("mat") dist_mat = mat linkage_matrix = linkage(dist_mat, "single") print "linkage2:" print linkage(1-dist_mat, "single") dendrogram(linkage_matrix, color_threshold=1, labels=["a", "b", "c"], show_leaf_counts=True) plt.subplot(1,2,2) plt.title("1 - mat") dist_mat = 1 - mat linkage_matrix = linkage(dist_mat, "single") dendrogram(linkage_matrix, color_threshold=1, labels=["a", "b", "c"], show_leaf_counts=True) My