datetime

问题 Show day for ex:- today, tommorow, 28 Dec 2020 etc after comparing date from sqlite db in a list tile with present date. And also delete a particular item from list on app start if the day was yesterday. In present it is showing like 21-11-2020 and if the date has expired also it still continues to show. This is my Code List<Note2> items2 = new List(); DatabaseHelper2 db2 = new DatabaseHelper2(); db2.getAllNotes2().then((notes2) { setState(() { notes2.forEach((note2) { items2.add(Note2

问题 Show day for ex:- today, tommorow, 28 Dec 2020 etc after comparing date from sqlite db in a list tile with present date. And also delete a particular item from list on app start if the day was yesterday. In present it is showing like 21-11-2020 and if the date has expired also it still continues to show. This is my Code List<Note2> items2 = new List(); DatabaseHelper2 db2 = new DatabaseHelper2(); db2.getAllNotes2().then((notes2) { setState(() { notes2.forEach((note2) { items2.add(Note2

问题 Look at the following code, def expdate(date): _exp_date = datetime.strptime(date, "%m%y") >>> expdate('1268') 2068-12-01 00:00:00 >>> expdate('1269') 1969-12-01 00:00:00 Optionally how to actually overcome this and get 2070 ? I'll be checking only using 2 digits years. 回答1: Python depends on the platform’s C library, which generally doesn’t have year 2000 issues, since all dates and times are represented internally as seconds since the epoch. Functions accepting a struct_time generally

问题 Input 8:30 PM with the local date of May 12th 2020 while UTC date already May 13th 2020 Desired Output 2020-05-12 20:30:00 Actual Output 2020-05-13 20:30:00 Tried 3 things: result = moment('8:30 PM', 'h:mm A').format('YYYY-MM-DD HH:mm:ss'); result = moment.tz('8:30 PM', 'h:mm A', 'America/New_York').format('YYYY-MM-DD HH:mm:ss'); moment.tz.setDefault('America/New_York'); result = moment.tz('8:30 PM', 'h:mm A', 'America/New_York').format('YYYY-MM-DD HH:mm:ss'); 回答1: As user120242 says it seems

问题 Input 8:30 PM with the local date of May 12th 2020 while UTC date already May 13th 2020 Desired Output 2020-05-12 20:30:00 Actual Output 2020-05-13 20:30:00 Tried 3 things: result = moment('8:30 PM', 'h:mm A').format('YYYY-MM-DD HH:mm:ss'); result = moment.tz('8:30 PM', 'h:mm A', 'America/New_York').format('YYYY-MM-DD HH:mm:ss'); moment.tz.setDefault('America/New_York'); result = moment.tz('8:30 PM', 'h:mm A', 'America/New_York').format('YYYY-MM-DD HH:mm:ss'); 回答1: As user120242 says it seems

问题 I have a MySQL database in which I write data every 10 minutes. i.e.: +---------------------+ | datetime | +---------------------+ | 2018-09-03 13:01:49 | | 2018-09-03 12:51:49 | | 2018-09-03 12:41:49 | +---------------------+ In my Python code I want to get just rows which are "exactly" n-hour old, i.e.: +---------------------+ | datetime | +---------------------+ | 2018-09-03 13:01:49 | | 2018-09-03 12:01:49 | | 2018-09-03 11:01:49 | | 2018-09-03 10:01:49 | | 2018-09-03 09:01:49 | | 2018-09

问题 **Year_qtr GDP ADJ_GDP** 2 1947q1 243.1 1934.5 3 1947q2 246.3 1932.3 4 1948q3 250.1 1930.3 5 1949q4 260.3 1960.7 Tried parse() from dateutil package but didnt wwork. Result dataframe should have 'Year_qtr' column as date values instead of object. 回答1: pandas already can do this out of the box! you can cast to datetime right away: import pandas as pd df = pd.DataFrame({'Year_qtr': ['1947q1', '1947q2', '1948q3', '1949q4']}) df['datetime'] = pd.to_datetime(df['Year_qtr']) # df # Year_qtr

问题 This question already has answers here : java DateTimeFormatterBuilder fails on testtime (2 answers) How can I convert Date.toString back to Date? (5 answers) Java - Unparseable date (3 answers) Closed 2 years ago . I am facing DateTimeParseException even after giving appropriate format DateTimeFormatter ft = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy"); LocalDateTime.parse("Tue Jan 08 00:00:00 IST 2019", ft); Please help if I am missing anything? 回答1: This is probably due to the

问题 I have a dataframe like below :- id creTimestamp CPULoad instnceId 0 2021-01-22 18:00:00 22.0 instanceA 1 2021-01-22 19:00:00 22.5 instanceA 2 2021-01-22 20:00:00 23.5 instanceA 3 2021-01-22 18:00:00 24.0 instanceB 4 2021-01-22 19:00:00 24.5 instanceB 5 2021-01-22 20:00:00 22.5 instanceB 6 2021-01-24 18:00:00 23.0 instanceA 7 2021-01-24 19:00:00 23.5 instanceA 8 2021-01-24 20:00:00 24.0 instanceA 9 2021-01-24 18:00:00 25.5 instanceB 10 2021-01-24 19:00:00 28.5 instanceB 11 2021-01-24 20:00:00

问题 I need to find the start and end date of the previous month from the current date. If the current date is 03-Feb-2021 The start date should be 01-Jan-2021 and the end date should be 31-Jan-2021 . how to achieve this as each month have a different number of days? Do we have any function in datetime to achieve this? 回答1: >>> from datetime import date, timedelta >>> this_first = date.today().replace(day=1) >>> prev_last = this_first - timedelta(days=1) >>> prev_first = prev_last.replace(day=1) >