dateadd

Need to add constraint: date plus 10 days

由 做~自己de王妃 提交于 2020-01-04 03:24:08
问题 I'm trying to add a constraint to a table so that it displays one of the columns as the current date plus 10 days. Here's what I've tried so far (I'm very new to SQL): ALTER TABLE orders ADD CONSTRAINT default_date DEFAULT DATEADD (DAY,10,required_date) FOR required_date Halp! Edit: I've also tried this now: ALTER TABLE orders ALTER COLUMN required_date ADD CONSTRAINT required_date_plus_ten DEFAULT DATEADD (DAY,10,required_date) Edit: Thanks to ypercube & my classmate. The final code is:

Using Parameters in DATEADD function of a Query

由 纵饮孤独 提交于 2019-12-30 09:49:53
问题 I am trying to us the DateAdd function of SQL in my Query. The problem is when I use a parameter to set the second arguement, the number argument I get an error which will say something like this: Failed to convert parameter value from a Decimal to a DateTime While if I enter it parameterless, i.e hardcode an Int, it works fine. This works: SELECT FieldOne, DateField FROM Table WHERE (DateField> DATEADD(day, -10, GETDATE())) while this does not: SELECT FieldOne, DateField FROM Table WHERE

SQL server DATEADD specific week days

由 三世轮回 提交于 2019-12-25 16:38:04
问题 So I need to add some days to a date, let's say 30, but the 30 days can't be calendar days, they are parameters that depend on some logic behind, so, I need to find a way to add to a date 30 days between mondays and wednesday for example: If I add 30 (mon to wed) days to february 15th, I should get April 26 If I add 30 (sun to fri) days to february 15th, I should get March 17 If the situation is not clear enough just let me know ant I'll try to give a better explanation. Thanks. 回答1: First I

SSIS, How to calculate next wednesday based on any given date using ssis derived column expression

由 北城余情 提交于 2019-12-25 01:37:32
问题 I am creating a package which will store a report's generation date. on basis of that date need to derive the next wednesday date. Ex: report date is 11/11/2019 so wed date should be 13/11/2019. urgenty needed 回答1: This Derived Column Expression should provide the next Wednesday's date. DATEADD("DAY",((1 + DATEDIFF("DAY",(DT_DATE)"1/1/1970",GETDATE())) / 7) * 7 + 6,(DT_DATE)"1/1/1970") Parts (inside out). Days since 1/1/1970 + 1. (Divide by 7) (Implicit Cast to Int) (Multiple by 7) will round

last occurence of date

由 旧街凉风 提交于 2019-12-25 00:51:50
问题 I need to find the last occurence of a date (in my case a static date 1st of may) I made this which works but i know this can be done in a much smarter way declare @lastmay date set @lastmay = DATEADD(YY,YEAR(GETDATE())-2000,'20000501') IF @lastmay <= GETDATE() BEGIN SET @lastmay = DATEADD(YY,-1,@lastmay) END 回答1: When you are working with dates in SQL it can be a real help to have a Dates utility table on your database that you can then compare against. This article discusses it well: http:/

When I enter a dateadd or datediff code i get this error all the time “ORA-00904 ”DATEADD“ INVALID IDENTIFIER.”

由 落花浮王杯 提交于 2019-12-24 03:24:15
问题 I have a university project and I have a patient table with admission and discharge date attributes. I need to delete records that are older than 7 years, I used the following code : delete from patient where dis_date >= datedadd(yy,-7,getdate()); I get the error "ORA-00904: "DATEADD" invalid identifier" . It's the same with the DATEDIFF function. Any alternatives please? 回答1: The typical way of doing this in Oracle would be: DELETE FROM patient WHERE dis_date < TRUNC(ADD_MONTHS(SYSDATE, -7

How to add minutes to the time part of datetime

由 梦想的初衷 提交于 2019-12-22 03:48:16
问题 How to add minutes(INT) to the time part of datetime ? For example : If i have datetime variable like this : @shift_start_time = 2015-11-01 08:00:00.000 @increase = 30 How to get the result : 2015-11-01 08:30:00.000 回答1: Use DATEADD : SELECT DATEADD(mi, @increase, @shift_start_time); db<>fiddle demo 回答2: Using dateadd: DATEADD(minute,@increase,@shift_start_time) the first argument can be chosen among: year quarter month dayofyear day week weekday hour minute second millisecond microsecond

Subtract minute from DateTime in SQL Server 2005

由 若如初见. 提交于 2019-12-21 06:45:26
问题 Suppose I have a datetime field whose value is 2000-01-01 08:30:00 and a duration field whose value is say 00:15 (meaning 15 minutes) If I subtract these two, I should get 2000-01-01 08:15:00 Also if I want to subtract 1:15 (means 1 hour 15 minutes), the output should be 2000-01-01 07:15:00 I am trying SELECT DATEDIFF(minute, '00:15','2000-01-01 08:30:00'); But the output is 52595055. How can i get the desired result? N.B.~ If I do SELECT dateadd(minute, -15,'2000-01-01 08:30:00'); , I will

sqlserver 取月初月末的时间

由 只愿长相守 提交于 2019-12-20 18:48:25
1.取月初的时间 --getdate() :2012/05/08 19：29：00 select convert(varchar,dateadd(day,-day(getdate())+1,getdate()),111) --结果：2012/05/08 2.取月末时间 select convert(varchar,dateadd(day,-day(getdate()),dateadd(month,1,getdate())),111) --结果集：2012/05/31 3.取某一个月的天数 select datediff(day,dateadd(day,-day (getdate() ), getdate() ),dateadd(day,-day( getdate () ),dateadd(month,1, getdate() ))) ---31 可将getdate()设为参数，想求几月的天数，则将本月的随便一个日期替换，如想查2月份的，则 select datediff(day,dateadd(day,-day(' 20120201 '),' 20120201 '),dateadd(day,-day(' 20120201 '),dateadd(month,1,' 20120201 '))) --29 来源： https://www.cnblogs.com/hlfei/p

Select records from start of month to current date

由 ↘锁芯ラ 提交于 2019-12-20 04:36:44
问题 I'm trying to select records that were added to the database between the start of the current month and the current day - I more or less know how to get records from the current day, and within a specific time period - but how do I get it so it starts from the beginning of the current calendar month? 回答1: DECLARE @sm DATETIME; SET @sm = DATEADD(DAY, 1-DAY(GETDATE()), DATEDIFF(DAY, 0, GETDATE())); SELECT columns FROM dbo.foo WHERE datetime_column >= @sm; 回答2: WHERE YEAR([Date])=YEAR(GETDATE())
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