current-page

How, in Yii, to get the current page's URL. For example: http://www.yoursite.com/your_yii_application/?lg=pl&id=15 but excluding the $GET_['lg'] (without parsing the string manually)? I mean, I'm looking for something similar to the Yii::app()->requestUrl / Chtml::link() methods, for returning URLs minus some of the $_GET variables. Edit : Current solution: unset $_GET['lg']; echo Yii::app()->createUrl( Yii::app()->controller->getId().'/'.Yii::app()->controller->getAction()->getId() , $_GET ); Felipe Almeida Yii 1 Yii::app()->request->url For Yii2: Yii::$app->request->url Yii::app()-

Has anybody experienced routes mysteriously becoming undetectable when using current_page? in Rails 3? Even with a fully generated scaffold complete with routes, a view, and a controller, I am getting a "No route matches" error. Here's the code: if current_page?(:controller => 'users', :action => "show") If I add a "match" command to routes.rb, it works fine, but why would I need to do that if the resources have already been created? What am I missing? You're missing the id parameter from this helper: current_page?(:controller => "users", :action => "show", :id => "1") It expects you to pass a

I'm implementing current_page? in a view to test if the current controller and action is equal to a certain value, however it won't return true when on that controller/action combination. - if current_page?(:controller => 'pages', :action => 'main') # doesn't return true when on that controller/action combination The only way it is working is if I use a bit more verbose method like so: - if controller.controller_name == 'pages' && controller.action_name == 'main' # this works just fine Is my syntax wrong or is there something else happening here? Is there a better way of doing this, such as