cufft

Asynchronous executions of CUDA memory copies and cuFFT

由 邮差的信 提交于 2019-12-12 16:04:14
问题 I have a CUDA program for calculating FFTs of, let's say, size 50000 . Currently, I copy the whole array to the GPU and execute the cuFFT. Now, I am trying to optimize the programm and the NVIDIA Visual Profiler tells me to hide the memcopy by concurrency with parallel computations. My question is: Is it possible, for example, to copy the first 5000 Elements, then start calculating, then copying the next bunch of data in parallel to calculations etc? Since a DFT is basically a sum over the

cuFFT in Alea GPU

由 旧街凉风 提交于 2019-12-12 10:22:47
问题 I am using Alea GPU to program on GPU using C# language. I installed Alea 3.0.4 on Visual Studio 2017 project, but I can't find some cuFFT library. On NVidia's website stands cuFFT is part of CUDA Toolkit, so I don't need to download additional CUDA libraries. Do I need to downlaod some additional binding or it is possible to use cuFFT with Alea GPU? 回答1: The bindings you're searching are here: https://www.nuget.org/packages/Alea.CudaToolkit/ In order for these to work you need to have CUDA

Is it possible to overlap batched FFTs with CUDA's cuFFT library and cufftPlanMany?

由 泄露秘密 提交于 2019-12-12 06:04:57
问题 I am trying to parallelize the FFT transforms of an acoustic fingerprinting library known as Chromaprint. It works by "splitting the original audio into many overlapping frames and applying the Fourier transform on them." Chromaprint uses a frame size of 4096, with a 2/3 overlap. For instance, the first frame consists of elements [0...4095], then the second frame is something like [1366.. 5462]. With cufftPlanMany, I know that you can specify batches of size 4096, that will perform batches of

On plans reuse in cuFFT

由 こ雲淡風輕ζ 提交于 2019-12-11 11:03:49
问题 This may seem like a simple question but cufft usage is not very clear to me. My question is: which one of the following implementations is correct ? 1) // called in a loop cufftPlan3d (plan1, x, y, z) ; cufftexec (plan1, data1) ; cufftexec (plan1, data2) ; cufftexec (plan1, data3) ; destroyplan(plan1) 2) init() //called only one time in application { cufftPlan3d (plan1, x, y, z) ; } exec () //called many times with data changing size remains same { cufftexec (plan1, data1) ; cufftexec (plan1

CUFFT: How to calculate fft of pitched pointer?

由 吃可爱长大的小学妹 提交于 2019-12-10 18:33:22
问题 I'm trying to calculate the fft of an image using CUFFT. It seems like CUFFT only offers fft of plain device pointers allocated with cudaMalloc . My input images are allocated using cudaMallocPitch but there is no option for handling pitch of the image pointer. Currently, I have to remove the alignment of rows, then execute the fft, and copy back the results to the pitched pointer. My current code is as follows: void fft_device(float* src, cufftComplex* dst, int width, int height, int

CUFFT is 1000x slower in VS2013/Cuda7.0 compared to VS2010/Cuda4.2

由 僤鯓⒐⒋嵵緔 提交于 2019-12-08 05:34:09
问题 This simple CUFFT code was run on two IDEs - VS 2013 with Cuda 7.0 VS 2010 with Cuda 4.2 I found that VS 2013 with Cuda 7.0 was a 1000 times slower approximately. The code executed in 0.6 ms in VS 2010, and took 520 ms on VS 2013, both on an average. #include "stdafx.h" #include "cuda.h" #include "cuda_runtime_api.h" #include "cufft.h" typedef cuComplex Complex; #include <iostream> using namespace std; int _tmain(int argc, _TCHAR* argv[]) { cudaEvent_t start, stop; cudaEventCreate(&start);

running FFTW on GPU vs using CUFFT

由 心已入冬 提交于 2019-12-08 02:51:35
问题 I have a basic C++ FFTW implementation that looks like this: for (int i = 0; i < N; i++){ // declare pointers and plan fftw_complex *in, *out; fftw_plan p; // allocate in = (fftw_complex*) fftw_malloc(sizeof(fftw_complex) * N); out = (fftw_complex*) fftw_malloc(sizeof(fftw_complex) * N); // initialize "in" ... // create plan p = fftw_plan_dft_1d(N, in, out, FFTW_FORWARD, FFTW_ESTIMATE); // execute plan fftw_execute(p); // clean up fftw_destroy_plan(p); fftw_free(in); fftw_free(out); } I'm

CUFFT | cannot figure out a simple example

由 独自空忆成欢 提交于 2019-12-06 14:08:11
问题 I've been struggling the whole day, trying to make a basic CUFFT example work properly. However i run into a little problem which I cannot identify. Basically I have a linear 2D array vx with x and y coordinates. Then I just calculate a forward then backward CUFFT (in-place), that simple. Then I copy back the array vx, normalize it by NX*NY , then display. #define NX 32 #define NY 32 #define LX (2*M_PI) #define LY (2*M_PI) float *x = new float[NX*NY]; float *y = new float[NX*NY]; float *vx =

Batched FFTs using cufftPlanMany

由 梦想与她 提交于 2019-12-05 06:30:01
问题 I want to perform 441 2D, 32-by-32 FFTs using the batched method provided by the cuFFT library. The parameters of the transform are the following: int n[2] = {32,32}; int inembed[] = {32,32}; int onembed[] = {32,32/2+1}; cufftPlanMany(&plan,2,n,inembed,1,32*32,onembed,1,32*(32/2+1),CUFFT_D2Z,441); cufftPlanMany(&inverse_plan,2,n,onembed,1,32*32,inembed,1,32*32,CUFFT_Z2D,441); After I did the forward and inverse FFTs using the above plans, I could not get the original data back. Can anyone

CUFFT | cannot figure out a simple example

由 时光总嘲笑我的痴心妄想 提交于 2019-12-04 19:43:30
I've been struggling the whole day, trying to make a basic CUFFT example work properly. However i run into a little problem which I cannot identify. Basically I have a linear 2D array vx with x and y coordinates. Then I just calculate a forward then backward CUFFT (in-place), that simple. Then I copy back the array vx, normalize it by NX*NY , then display. #define NX 32 #define NY 32 #define LX (2*M_PI) #define LY (2*M_PI) float *x = new float[NX*NY]; float *y = new float[NX*NY]; float *vx = new float[NX*NY]; for(int j = 0; j < NY; j++){ for(int i = 0; i < NX; i++){ x[j*NX + i] = i * LX/NX; y
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