counting

问题 I have a data set that has 3 columns , (ID , D , AE). sample=data.frame( ID=c(1,1,1,2,2,2), D=c('a','b','c','a','c','c'), AE=c('m','x','w','y','m','f') ) I want to count the number of IDs where all possible combinations that consist of any combination between any two drugs within a certain ID and the AEs corresponding to that ID. please see the image to understand exactly what i mean enter image description here. Someone could help me with a code that worked perfectly on the small dataset

问题 I can't figure out how to take a matrix and count the amount of the alphanumerical values for each row. I will only be taking in matrices with the values I'm counting. For example, if I got: ABA455 7L9O36G DZLFPEI I would get something like A:2 B:1 4:1 5:2 for the first row and each row would be counted independently. I would most like to understand the operators used if you could please explain them too. Thank you. 回答1: The following should work in any mainstream APL implementation. Let's

问题 I can't figure out how to take a matrix and count the amount of the alphanumerical values for each row. I will only be taking in matrices with the values I'm counting. For example, if I got: ABA455 7L9O36G DZLFPEI I would get something like A:2 B:1 4:1 5:2 for the first row and each row would be counted independently. I would most like to understand the operators used if you could please explain them too. Thank you. 回答1: The following should work in any mainstream APL implementation. Let's

问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

问题 I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this? int length() { pointer = root; // Reset pointer int i; // Looping through data in node int len = 0; // Counting characters int sizedata = sizeof(pointer->data); // Sets size limit for data in

问题 Okay, so I have a Google Sheet that I need to reduce a number down to a specific set of 4 numbers. Then count how many times those numbers occur. For example: The numbers it breaks down to: 1, 2, 3, 4 Disregard their individual values other than for the purpose of being broken down. Now take the number 17 . Count+Add 1, 2, 3, 4, 1, 2, 3 = 7 r1 Take number 12 Count+Add 1, 2, 3, 4, 1 = r1 The remainder is rounded DOWN So, basically, it breaks down Cell A1 into a count of how many sequences it

问题 Okay, so I have a Google Sheet that I need to reduce a number down to a specific set of 4 numbers. Then count how many times those numbers occur. For example: The numbers it breaks down to: 1, 2, 3, 4 Disregard their individual values other than for the purpose of being broken down. Now take the number 17 . Count+Add 1, 2, 3, 4, 1, 2, 3 = 7 r1 Take number 12 Count+Add 1, 2, 3, 4, 1 = r1 The remainder is rounded DOWN So, basically, it breaks down Cell A1 into a count of how many sequences it

问题 I have the following data.frame: x <- data.frame(A = c("Y", "Y", "Z", NA), B = c(NA, TRUE, FALSE, TRUE), C = c(TRUE, TRUE, NA, FALSE)) And I need to compute the following table with xtabs : A B C Y 1 2 Z 0 0 <NA> 1 0 I was told to use na.action = NULL, which indeed returns the table I need: xtabs(formula = cbind(B, C) ~ A, data = x, addNA = TRUE, na.action = NULL) A B C Y 1 2 Z 0 0 <NA> 1 0 However, na.action = na.pass returns a different table: xtabs(formula = cbind(B, C) ~ A, data = x,