coordinates

问题 I have the following Layout: <ScrollView> <RelativeLayout> <RelativeLayout> <View android:id="@+id/vline" android:layout_width="match_parent" android:layout_height="1dp" android:background="@color/md_white_1000"/> <ImageButton>...</ImageButton> </RelativeLayout> </RelativeLayout> </ScrollView> The different Layouts have there own content and height on different screens of course. Now I want, by pressing the ImageButton, to smoothly scroll my ScrollView up so that the Views upper left corner

问题 I have the following Layout: <ScrollView> <RelativeLayout> <RelativeLayout> <View android:id="@+id/vline" android:layout_width="match_parent" android:layout_height="1dp" android:background="@color/md_white_1000"/> <ImageButton>...</ImageButton> </RelativeLayout> </RelativeLayout> </ScrollView> The different Layouts have there own content and height on different screens of course. Now I want, by pressing the ImageButton, to smoothly scroll my ScrollView up so that the Views upper left corner

问题 How do I flip the y value of an NSPoint to a flipped coordinate space. I have two sources of points, both in global screen space, but one is flipped: one from a screen coordinate space with 0,0 = top left. one from a screen coordinate space with 0,0 = bottom left. I need to flip the second one (bottom left) to be in the same space as the first one, top left. How can I do that on an NSPoint or CGPoint? 回答1: For Mac OSX Cocoa, you can flip the y Coordinate for a view, just override isFlipped to

问题 So....in my coordinator--which conforms to the mapbox delegate protocol, I can just do: mapView.setCenter(mapView.userLocation!.coordinate, zoomLevel: 13, animated: true) and this function works fine in the coordinator or when it is called in the mapView class. The only problem is I don't know how to pass this mapView instance around (specifically back into ContentView where I want to have a button that does the same thing). I also have a LocationManager struct but I don't know how much use

问题 I am trying to find the equivalent point from one triangle to another. Ideally I want to be able to give the 3 points of triangle A and the 3 points of triangle B which will then calculate the transform matrix which I can apply to the point afterwards to find the equivalent point. I have found a few JavaScript libraries/methods for this, but they all use quadrilaterals rather than triangles and I am not sure what to do to apply to a triangle instead. 回答1: Three point pairs can define affine

问题 I'd like to share with community an useful function that returns segment-distances and segment-weights from a coordinate (PointX, PointY). I create diagrams from tool (such as draw.io) and when making edge (segment style) with multiple waypoints, the freeware provides waypoints by its coordinates. Unfortunately latest version of cytoscape.js (at the time I wrote this post) dont include this capability (apologies if it does) and only segment-distances and segment-weights are used. Therefore I

问题 I have millions of xyz-coordinates from multiple point cloud files which I am storing inside a 2-dimensional numpy array: [[x1, y1, z1], [x2, y2, z2],..., [xn, yn, zn]] . I want to filter all the points which are inside a specific bounding box described by 4 coordinates [[x1, y1], [x2, y2]] i.e. the lower left and upper right coordinates of a rectangle. I have already found the following piece of code to filter coordinates with numpy and it's almost what I want. The only difference is (if I'm

问题 I have millions of xyz-coordinates from multiple point cloud files which I am storing inside a 2-dimensional numpy array: [[x1, y1, z1], [x2, y2, z2],..., [xn, yn, zn]] . I want to filter all the points which are inside a specific bounding box described by 4 coordinates [[x1, y1], [x2, y2]] i.e. the lower left and upper right coordinates of a rectangle. I have already found the following piece of code to filter coordinates with numpy and it's almost what I want. The only difference is (if I'm

问题 I have millions of xyz-coordinates from multiple point cloud files which I am storing inside a 2-dimensional numpy array: [[x1, y1, z1], [x2, y2, z2],..., [xn, yn, zn]] . I want to filter all the points which are inside a specific bounding box described by 4 coordinates [[x1, y1], [x2, y2]] i.e. the lower left and upper right coordinates of a rectangle. I have already found the following piece of code to filter coordinates with numpy and it's almost what I want. The only difference is (if I'm

问题 I get the following error from the gps: Fatal Exception: java.lang.NumberFormatException Invalid double: "-٣٣٫٩٣٨٧٤" Now this is from a error that I got from a user via Fabric. It looks like arabic so I'm guessing it only happens if you have the language set to that, or your sim card? Is it possible to force the gps to send characters in the 0-9 range? Or can I somehow fix this? 回答1: Try this: String number = arabicToDecimal("۴۲"); // number = 42; private static final String arabic = "\u06f0