continuous

How does the C4.5 Algorithm handle continuous data?

五迷三道 提交于 2019-12-21 05:25:11
问题 I am implementing the C4.5 algorithm in .net , however I don't have clear idea of how it deals "continuous (numeric) data". Could someone give me a more detailed explanation? 回答1: For continuous data C4.5 uses a threshold value where everything less than the threshold is in the left node, and everything greater than the threshold goes in the right node. The question is how to create that threshold value from the data you're given. The trick there is to sort your data by the continuous

Video recording to a circular buffer on Android

跟風遠走 提交于 2019-12-20 22:05:44
问题 I'm looking for the best way (if any...) to capture continuous video to a circular buffer on the SD card, allowing the user to capture events after they have happened. The standard video recording API allows you to just write directly to a file, and when you reach the limit (set by the user, or the capacity of the SD card) you have to stop and restart the recording. This creates up to a 2 second long window where the recording is not running. This is what some existing apps like DailyRoads

Create binned variable from results of class interval determination

廉价感情. 提交于 2019-12-19 08:04:32
问题 I want to create a binned variable out of a continuous variable. I want 10 bins, with break points set from whatever results from a jenks classification. How do I assign each value to one of these 10 bins? # dataframe w/ values (AllwdAmt) df <- structure(list(X = c(2078L, 2079L, 2080L, 2084L, 2085L, 2086L, 2087L, 2092L, 2093L, 2094L, 2095L, 4084L, 4085L, 4086L, 4087L, 4088L, 4089L, 4091L, 4092L, 4093L, 4094L, 4095L, 4096L, 4097L, 4098L, 4099L, 4727L, 4728L, 4733L, 4734L, 4739L, 4740L, 4741L,

Create binned variable from results of class interval determination

假如想象 提交于 2019-12-19 08:04:21
问题 I want to create a binned variable out of a continuous variable. I want 10 bins, with break points set from whatever results from a jenks classification. How do I assign each value to one of these 10 bins? # dataframe w/ values (AllwdAmt) df <- structure(list(X = c(2078L, 2079L, 2080L, 2084L, 2085L, 2086L, 2087L, 2092L, 2093L, 2094L, 2095L, 4084L, 4085L, 4086L, 4087L, 4088L, 4089L, 4091L, 4092L, 4093L, 4094L, 4095L, 4096L, 4097L, 4098L, 4099L, 4727L, 4728L, 4733L, 4734L, 4739L, 4740L, 4741L,

How to draw a continuous curved line from 3 given points at a time

 ̄綄美尐妖づ 提交于 2019-12-18 13:23:13
问题 I am trying to draw a continuous curved line in flash. There are many methods but none of the ones I have found so far quite fit my requirements. First of all, I want to use the flash graphic api's curveTo() method. I DO NOT want to simulate a curve with hundreds of calls to lineTo() per curved line segment. It is my experience and understanding that line segments are processor heavy. Flash's quadratic bezier curve should take less CPU power. Please challenge this assumption if you think I am

JS counter continuously updating

五迷三道 提交于 2019-12-18 06:56:26
问题 How to implement a live and persistent number counter on a site So I was looking at this question (^) and I want to do the exact same thing except a little different. I need one of these that counts up 15.8 cents per second from the numb $138,276,343 Preferably I would like to have the commas like a normal dollar amount. Any way I could get this working? I'm stumped. Like the poster of the above question, I don't have much JS knowledge. 回答1: This took me quite a long time to answer since I

python return lists of continuous integers from list

半世苍凉 提交于 2019-12-17 19:00:01
问题 I have a list of integers, and I want to generate a list containing a list of all the continuous integers. #I have: full_list = [0,1,2,3,10,11,12,59] #I want: continuous_integers = [[0,1,2,3], [10,11,12], [59]] I have the following which works, but seems like a poor way to do it: sub_list = [] continuous_list = [] for x in full_list: if sub_list == []: sub_list.append(x) elif x-1 in sub_list: sub_list.append(x) else: continuous_list.append(sub_list) sub_list = [x] continuous_list.append(sub

ggplot: arranging boxplots of multiple y-variables for each group of a continuous x

时光毁灭记忆、已成空白 提交于 2019-12-17 17:38:44
问题 I would like to create boxplots of multiple variables for groups of a continuous x-variable. The boxplots should be arranged next to each other for each group of x. The data looks like this: require (ggplot2) require (plyr) library(reshape2) set.seed(1234) x <- rnorm(100) y.1 <- rnorm(100) y.2 <- rnorm(100) y.3 <- rnorm(100) y.4 <- rnorm(100) df <- as.data.frame(cbind(x,y.1,y.2,y.3,y.4)) which I then melted dfmelt <- melt(df, measure.vars=2:5) The facet_wrap as shown in this solution (

Continuous input to switch case until i press exit c#

泪湿孤枕 提交于 2019-12-13 20:13:32
问题 I am trying to create a program where the application should never exit until I press option '6'. Below is my sample program: Right now, if I press any option, it executes the corresponding method and console window closes (exits the application) after it is done executing. I want the console to wait for the next option to be entered. Console.WriteLine(@"Select one of the following option: 1-Write Apps 2-Write Drivers 3-Write OS 4-Write Packages 5-All the above 6-Exit"); string strReadKey =

Changing Continuous Ranges to Categorical in R

六眼飞鱼酱① 提交于 2019-12-13 04:25:34
问题 I was trying to convert some continuous integers to categorical ranges, but something I did not understand happened. Although I fixed to get what I want, I still don't understand why it happened. The variable is some integers from 0 to 12, the following code left 10 , 11 , 12 out from the 5+ category. py2$Daily.Whole.Grain[py2$Daily.Whole.Grain==0]<-"0" py2$Daily.Whole.Grain[py2$Daily.Whole.Grain==1]<-"1" py2$Daily.Whole.Grain[py2$Daily.Whole.Grain==2]<-"2" py2$Daily.Whole.Grain[py2$Daily