contains

问题 This question already has answers here : Object comparison in JavaScript [duplicate] (10 answers) How to determine equality for two JavaScript objects? (60 answers) How to determine if Javascript array contains an object with an attribute that equals a given value? (23 answers) indexOf method in an object array? (27 answers) Closed last month . I'm trying to check for the existence of an element of an array using built-in Javascript array function const routes = [ { path: 'users/:id',

问题 I have an ArrayList containing int[] . Assuming Arrays.equals(int[], (a value in the arrayList)) = true why when I do arrayOfInts.contains(int[]) is this false? I assume it is because of the same reason that (int[] == (a value in the arrayList)) = false but should I be getting this error? Can I correct it somehow? TL;DR: Can I use Arraylist.contains() for int[] EDIT: ANSWER (if anyone searches this in the future here's the comparison code I made as a solution): private boolean

问题 How could one count how many times a substring exists within a string? I mean if you have a String " one, two, three, one, one, two" how could you make it count "one" being present 3 times? I thought String.Contains would be able to do the job but that only checks if the substring is present at all. String.forall is for chars and therefofre niether an option. So i am really at a complete halt here. Can some enligten me? 回答1: You can use Regex.Escape to turn the string you're searching for

问题 As the title above. Assume, I have a paragraph: It will be seen that this mere painstaking burrower and grub-worm of a poor devil of a Sub-Sub appears to have gone through the long Vaticans and street-stalls of the earth. . The bold string is a highlight. When I drag my mouse to select string grub-worm of a poor devil of a Sub-Sub Then I want to check if my selected text contains the highlight(or the part of the highlight) or not. How could I do that? The code below is the example to add a

问题 In PowerShell v2, I'm trying to add only unique values to an array. I've tried using an if statement that says, roughly, If (-not $Array -contains 'SomeValue'), then add the value, but this only ever works the first time. I've put a simple code snippet that shows what I'm doing that doesn't work and what I've done as a workaround that does work. Can someone please let me know where my issue is? Clear-Host $Words = @('Hello', 'World', 'Hello') # This will not work $IncorrectArray = @() ForEach

问题 What would be the fastest way to check if a string contains any matches in a string array in C#? I can do it using a loop, but I think that would be too slow. 回答1: You could combine the strings with regex or statements, and then "do it in one pass," but technically the regex would still performing a loop internally. Ultimately, looping is necessary. 回答2: Using LINQ: return array.Any(s => s.Equals(myString)) Granted, you might want to take culture and case into account, but that's the general

问题 Newbie question about java HashSet Set<User> s = new HashSet<User>(); User u = new User(); u.setName("name1"); s.add(u); u.setName("name3"); System.out.println(s.contains(u)); Can someone explain why this code output false ? Moreover this code does not even call equals method of User. But according to the sources of HashSet and HashMap it have to call it. Method equals of User simply calls equals on user's name. Method hashCode return hashCode of user's name 回答1: If the hash code method is

问题 Newbie question about java HashSet Set<User> s = new HashSet<User>(); User u = new User(); u.setName("name1"); s.add(u); u.setName("name3"); System.out.println(s.contains(u)); Can someone explain why this code output false ? Moreover this code does not even call equals method of User. But according to the sources of HashSet and HashMap it have to call it. Method equals of User simply calls equals on user's name. Method hashCode return hashCode of user's name 回答1: If the hash code method is

问题 Newbie question about java HashSet Set<User> s = new HashSet<User>(); User u = new User(); u.setName("name1"); s.add(u); u.setName("name3"); System.out.println(s.contains(u)); Can someone explain why this code output false ? Moreover this code does not even call equals method of User. But according to the sources of HashSet and HashMap it have to call it. Method equals of User simply calls equals on user's name. Method hashCode return hashCode of user's name 回答1: If the hash code method is

问题 I have a dataframe. I can test whether, (C), on each row, the number in column (B) is in the string column (A). df = pd.DataFrame({'A': ["me 1 23", "me", "123", "me 12", "12 me"], 'B': [123, 123, 123, 12, 12 ]}) df = df.dropna() df['C']=df.A.str.contains(r'\b(?:{})\b'.format('|'.join(df.B.astype(str)))).astype(int) print(df) This gives the correct answer: A B C 0 me 1 23 123 0 1 me 123 0 2 123 123 1 3 me 12 12 1 4 12 me 12 1 But when I change the number (B) on row 1 I get the incorrect answer