comparison-operators

问题 I have a web page that displays 10 images at a time from a directory. In the directory I have now 55,000 images. Once zz below hits 32,767 it stops. How do I make ZZ into a subtype LONG to get it to be 2,147,483,647 (the code below is not accurate, just quickly done to show you the loop I am achieving) pp = Request("pp") ' pp could be at 40000 filecount = 0 dim zz For Each file in filecoll zz = zz + 1 If ZZ > PP then response.write 'show image here end if Next 回答1: The actual problem got

问题 Consider the following code: >>> class A(object): ... def __init__(self, a): ... self.a = a ... def __eq__(self, other): ... return self.a==other.a ... >>> a=A(1) >>> b=A(1) >>> c=A(2) >>> a==b True # because __eq__ says so >>> a==c False # because __eq__ says so >>> a is b False # because they're different objects >>> l = [b,c] >>> a in l True # seems to use __eq__ under the hood So, in seems to use __eq__ to determine whether or not something is in a container. Where can one find

问题 I'm trying to compare 2 images to see if they're the same. I've done quite a bit of research on this and can't come to a working conclusion. Here is an example of what I have now: var image1 = document.getElementById('imgId1'); var image2 = document.getElementById('imgId2'); if(image1.src.match(image2.src)) { <---This seems to only work w/ a string //do whatever here } I've also tried other things such as: if(image2.src.indexOf(image1.src)!= -1) { //do whatever here } and if(image2.src ==

问题 In Python3, the functools.total_ordering decorator allows one to only overload __lt__ and __eq__ to get all 6 comparison operators. I don't get why one has to write two operators when one would be enough, namely __le__ or __ge__ , and all others would be defined accordingly : a < b <=> not (b <= a) a > b <=> not (a <= b) a == b <=> (a <= b) and (b <= a) a != b <=> (a <= b) xor (b <= a) Is that just because xor operator does not exists natively? 回答1: The documentation states you must define

问题 This question is based on code that I found that monitors possible memory leaks, so it contains some code that you probably don't want to see in regular programs like ordering pointers. However, I saw that a pointer was set to nullptr and then the pointer was compared to a maximum address. Is it guaranteed by the C++ standard that nullptr is always smaller than other pointers for operator< ? 回答1: Can you compare nullptr to other pointers for order? Yes . But whether the result is useful is

来源： https://stackoverflow.com/questions/40432805/how-is-true-2-implemented

来源： https://stackoverflow.com/questions/40432805/how-is-true-2-implemented

来源： https://stackoverflow.com/questions/40432805/how-is-true-2-implemented

来源： https://stackoverflow.com/questions/40432805/how-is-true-2-implemented

来源： https://stackoverflow.com/questions/40432805/how-is-true-2-implemented