compare

问题 I am looking to sort a very long list of colors by their HSV/HSB values. I would like to sort them by Hue, then Sat, then Bright. Really all I need is a way to tell if one color comes "before" or "after" based on that order of HSV since I am just going to make a compareTo() in Java and use a TreeSet to do the ordering. In Java, HSV values are all stored as floats. I am terrible at algorithms like these so any help would be appreciated! 回答1: The brute force way: public final class

问题 I have found this (personally) convenient answer that fits my needs: https://stackoverflow.com/a/6713782/2678218 But since I am using TypeScript , I can have something like this with Generics : private equals<T>(x: T, y: T) { if (x === y) { return true; // if both x and y are null or undefined and exactly the same } else if (!(x instanceof Object) || !(y instanceof Object)) { return false; // if they are not strictly equal, they both need to be Objects } else if (x.constructor !== y

问题 For example, I have two arrays: string[] arrayOne = {"One", "Two", "Three", "Three", "Three"}; string[] arrayTwo = {"One", "Two", "Three"}; var result = arrayOne.Except(arrayTwo); foreach (string s in result) Console.WriteLine(s); I want Items from arrayOne which are not there in arrayTwo . So here I need result as: Three Three but I am getting no results as its treating "Three" as common and not checking the other two items("Three", "Three"). I dont want to end up writing a huge method to

问题 For example, I have two arrays: string[] arrayOne = {"One", "Two", "Three", "Three", "Three"}; string[] arrayTwo = {"One", "Two", "Three"}; var result = arrayOne.Except(arrayTwo); foreach (string s in result) Console.WriteLine(s); I want Items from arrayOne which are not there in arrayTwo . So here I need result as: Three Three but I am getting no results as its treating "Three" as common and not checking the other two items("Three", "Three"). I dont want to end up writing a huge method to

问题 For example, I have two arrays: string[] arrayOne = {"One", "Two", "Three", "Three", "Three"}; string[] arrayTwo = {"One", "Two", "Three"}; var result = arrayOne.Except(arrayTwo); foreach (string s in result) Console.WriteLine(s); I want Items from arrayOne which are not there in arrayTwo . So here I need result as: Three Three but I am getting no results as its treating "Three" as common and not checking the other two items("Three", "Three"). I dont want to end up writing a huge method to

问题 I use ReShaper and when I compare two double values with ==, it suggests that I should use the Math. ABS method with a tolerance. See: https://www.jetbrains.com/help/resharper/2016.2/CompareOfFloatsByEqualityOperator.html This example double d = 0.0; double d2 = 0.0; if (d == d2) { /* some code */ } is then converted to double d = 0.0; double d2 = 0.0; if (Math.Abs(d - d2) < TOLERANCE) { /* some code */ } But I think it's really complicated for a developer to think about the right tolerance.

问题 I have tried following this previous question: Comparing 2 Image's sources in Javascript However, there is no solution to this on the page I am trying to generate random images from 2 arrays, the same image can not be compared to each other. Duplicates continue to appear when i run this code from the if statement. However, what i intended to happen if if the same image is generated then a new pair of images would be displayed, and the duplicates would not be displayed. function start2AFC() {

问题 Is there a short way to test for identity over multiple columns? For example, over this input data=data.table(one=c(1,2,3,4), two=c(7,8,9,10), three=c(1,2,3,4), four=c(1,2,3,4) ) Is there something that would return all the columns that are identical to data$one? Something like allcolumnsidentity(data$one, data) # compares all columns with respect to data$one Should return (TRUE, FALSE, TRUE, TRUE) since data$three and data$four are identical to data$one. I saw the identical() and comapre()

问题 Is there a short way to test for identity over multiple columns? For example, over this input data=data.table(one=c(1,2,3,4), two=c(7,8,9,10), three=c(1,2,3,4), four=c(1,2,3,4) ) Is there something that would return all the columns that are identical to data$one? Something like allcolumnsidentity(data$one, data) # compares all columns with respect to data$one Should return (TRUE, FALSE, TRUE, TRUE) since data$three and data$four are identical to data$one. I saw the identical() and comapre()

问题 Is there a short way to test for identity over multiple columns? For example, over this input data=data.table(one=c(1,2,3,4), two=c(7,8,9,10), three=c(1,2,3,4), four=c(1,2,3,4) ) Is there something that would return all the columns that are identical to data$one? Something like allcolumnsidentity(data$one, data) # compares all columns with respect to data$one Should return (TRUE, FALSE, TRUE, TRUE) since data$three and data$four are identical to data$one. I saw the identical() and comapre()