compare

问题 I'm trying to get the fields which value is not match base on the compared rows. It's hard to explain so I'll put the sample table and its results. Table: orders | seqid | orderId | taskId | field1 | field2 | field3 | field4 | +---------+-----------+----------+----------+----------+----------+----------+ | 1 | 1 | 1 | a | b | c | d | | 2 | 1 | 2 | a | b | c | d | | 3 | 2 | 1 | a | b | c | d | | 4 | 2 | 2 | a | c | c | c | | 5 | 3 | 1 | a | a | a | a | Results: | OrderId | FieldName | Error |

问题 I have 2 extracted data sets from a dataset called babies2009( 3 vectors count, name, gender ) One is girls2009 containing all the girls and the other boys2009. I want to find out what similar names exist between boys and girls. I tried this common.names = (boys2009$name %in% girls2009$name) When I try babies2009[common.names, ] [1:10, ] all I get is the girl names not the common names. I have confirmed that both data sets indeed contain boys and girls respectively by doing taking a 10 sample

问题 I'm trying to compare two dictionaries. My approach is to turn them into two separate lists of tuples and to then use the set module. Here is an illustration: dict = {'red':[1,2,3],'blue':[2,3,4],'green':[3,4,5]} dict1 = {'green':[3,4,5],'yellow':[2,3,4],'red':[5,2,6]} intersection = set(set(dict.items()) & set(dict1.items())) apparently, this is comparing two lists of tuples and python doesn't like that. I get a TypeError: 'list' is unhashable error (or similar wording). I would like

问题 I have a DataFrame with information about employee salary. It's about 900000+ rows. Sample: +----+-------------+---------------+----------+ | | table_num | name | salary | |----+-------------+---------------+----------| | 0 | 001234 | John Johnson | 1200 | | 1 | 001234 | John Johnson | 1000 | | 2 | 001235 | John Johnson | 1000 | | 3 | 001235 | John Johnson | 1200 | | 4 | 001235 | John Johnson | 1000 | | 5 | 001235 | Steve Stevens | 1000 | | 6 | 001236 | Steve Stevens | 1200 | | 7 | 001236 |

问题 I came across a piece of code in a project I'm working on that looks kind of scary. It's supposed to be displaying a +/- delta between two numbers, but it's using a > to compare strings of numbers instead of numbers. I'm assuming that the code is working as expected at the moment, so I'm just trying to understand how Ruby is comparing these strings in this case. Here's an example with the variables replaced: if '55.59(100)' > '56.46(101)' delta = '+' else delta = '-' end 回答1: String includes

问题 I have three directories. I would like to compare directory1 with directory2, then take those changes/new files and copy them over to directory3. Is there an easy way to do this, maybe by using linux diff and cp commands? I'm open to ideas. Thanks! Andrew 回答1: I believe this is what you want from your description. for file in dir2/*; do file_in_dir1=dir1/$(basename ${file}) if [ ! -e ${file_in_dir1} ]; then # If the file in dir2 does not exist in dir1, copy cp ${file} dir3 elif ! diff ${file}

问题 I have gathered a set of transactions in a CSV file of the format: {Pierre, lait, oeuf, beurre, pain} {Paul, mange du pain,jambon, lait} {Jacques, oeuf, va chez la crémière, pain, voiture} I plan to do a simple association rule analysis, but first I want to exclude items from each transactions which do not belong to ReferenceSet = {lait, oeuf, beurre, pain} . Thus my resulting dataset would be, in my example : {Pierre, lait, oeuf, beurre, pain} {Paul,lait} {Jacques, oeuf, pain,} I'm sure this

问题 I still find the ifelse structure in R a bit confusing, I've got the following data frame: df <- structure(list(snp = structure(1:11, .Label = c("AL0009", "AL00014", "AL0021", "AL00046", "AL0047", "AS0005", "AS0014", "AS00021", "AS0047", "AS0071", "DR0001" ), class = "factor"), CHROMOSOME = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), COUNT_ALLELE = structure(c(1L, 1L, 1L, 3L, 1L, 1L, 1L, 2L, 3L, 3L, 1L), .Label = c("A", "C", "G"), class = "factor"), OTHER_ALLELE = structure(c(3L, 3L, 2L,

问题 I have an application that will hold a set of images in a SQLDatabase and then the user will take a photo and I want to be able to match it with an image in the database. I have no idea where to start, can anyone help? point me in the right direction? Thanks 回答1: Start by checking out OpenCV. The problem you are trying to solve is not exactly trivial though. It is an area of ongoing research and none of the algorithms are perfect (in fact they're all far from perfect, IMO). Good luck! 回答2:

问题 Is there a fast way of doing something like this Compare two arrays with the same value but with a different order in PHP? I have arrays with potentially same data but in different order and I just need to see whether they are identical. OK, turns out I get back an object and not an array, I guess... object(Doctrine\ORM\PersistentCollection)#560 (9) etc. hmm... Would the easiest way perhaps to iterate over the contents of the collection in order to create my own array and then compare like