combinatorics

Pair-Tournament design algorithm

最后都变了- 提交于 2021-01-28 17:15:27
问题 I'm trying to build a Javascript function that takes as an input: array of players e.g. ["player1","player2","player3","player4"] (probably only equal number of players) and dynamically creates an array for a tournament design based on the following rules: each player partners no more than once with the same player every player has an equal amount of total matches the outputs would be an array containing arrays of matches with four entries each e.g. [player1, player2, player3, player4] stands

Pair-Tournament design algorithm

强颜欢笑 提交于 2021-01-28 17:09:48
问题 I'm trying to build a Javascript function that takes as an input: array of players e.g. ["player1","player2","player3","player4"] (probably only equal number of players) and dynamically creates an array for a tournament design based on the following rules: each player partners no more than once with the same player every player has an equal amount of total matches the outputs would be an array containing arrays of matches with four entries each e.g. [player1, player2, player3, player4] stands

Pair-Tournament design algorithm

安稳与你 提交于 2021-01-28 17:09:39
问题 I'm trying to build a Javascript function that takes as an input: array of players e.g. ["player1","player2","player3","player4"] (probably only equal number of players) and dynamically creates an array for a tournament design based on the following rules: each player partners no more than once with the same player every player has an equal amount of total matches the outputs would be an array containing arrays of matches with four entries each e.g. [player1, player2, player3, player4] stands

Pair-Tournament design algorithm

老子叫甜甜 提交于 2021-01-28 17:08:33
问题 I'm trying to build a Javascript function that takes as an input: array of players e.g. ["player1","player2","player3","player4"] (probably only equal number of players) and dynamically creates an array for a tournament design based on the following rules: each player partners no more than once with the same player every player has an equal amount of total matches the outputs would be an array containing arrays of matches with four entries each e.g. [player1, player2, player3, player4] stands

Python “Stars and Bars”

瘦欲@ 提交于 2021-01-28 03:28:59
问题 I am trying to get all possible ways to distribute n candies among k children. For instance, according to stars-and-bars formula, number of ways to distribute 96 candies among 5 children is 100! / (96!*4!) = 3 921 225 tuples of all possible permutations of size 5. list2 = [item for item in it.product(range(97), repeat = 5) if sum(item) == 96] My PC seems to overwhelmed by complexity. Each tuple consumes 24*5 = 120 bytes of memory. This results in 921 225 * 120 = 470547000 bytes or 450 mb.

All possible combinations with data from JSON file

半城伤御伤魂 提交于 2021-01-27 20:03:14
问题 My goal is to create a part of code that would generate all possible combinations without duplicates (combinations with same elements, no matter what their sequence is) with data from a JSON file. My JSON file looks like this: [ { "COLLECTION": "Assault", "WEAPON": "SG 553", "SKIN": "Tornado", "GRADE": "Consumer Grade" }, { "COLLECTION": "Assault", "WEAPON": "UMP-45", "SKIN": "Caramel", "GRADE": "Consumer Grade" }, { "COLLECTION": "Vertigo", "WEAPON": "Five-SeveN", "SKIN": "Candy Apple ",

Methods to exhaustively partition a vector into pairs in R

大憨熊 提交于 2021-01-27 06:23:53
问题 (This is inspired by another question marked as a duplicate. I think it is an interesting problem though, although perhaps there is an easy solution from combinatorics, about which I am very ignorant.) Problem For a vector of length n , where n mod 2 is zero, find all possible ways to partition all elements of the vector into pairs, without replacement, where order does not matter. For example, for a vector c(1,2,3,4) : list(c(1,2), c(3,4)) list(c(1,3), c(2,4)) list(c(1,4), c(2,3)) My

Methods to exhaustively partition a vector into pairs in R

泄露秘密 提交于 2021-01-27 06:23:08
问题 (This is inspired by another question marked as a duplicate. I think it is an interesting problem though, although perhaps there is an easy solution from combinatorics, about which I am very ignorant.) Problem For a vector of length n , where n mod 2 is zero, find all possible ways to partition all elements of the vector into pairs, without replacement, where order does not matter. For example, for a vector c(1,2,3,4) : list(c(1,2), c(3,4)) list(c(1,3), c(2,4)) list(c(1,4), c(2,3)) My

Finding all combinations of a list in Python with repetition

人走茶凉 提交于 2021-01-07 07:06:28
问题 I am looking to find and print all possible combinations of the set (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12) of length 5. There should be 13 choose 5 combinations (6188) because order does NOT matter, and repetition is allowed. I found this code and was using it: from itertools import product for item in product([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], repeat=5): print(item) However, this is not printing all 6188 combinations. Trying to figure out how to tweak the code so it spits out

Finding all combinations of a list in Python with repetition

非 Y 不嫁゛ 提交于 2021-01-07 07:04:27
问题 I am looking to find and print all possible combinations of the set (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12) of length 5. There should be 13 choose 5 combinations (6188) because order does NOT matter, and repetition is allowed. I found this code and was using it: from itertools import product for item in product([0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], repeat=5): print(item) However, this is not printing all 6188 combinations. Trying to figure out how to tweak the code so it spits out