clause

JOIN 子句 MySQL 对 SELECT 语句和多表 DELETE 和 UPDATE 语句 table_references 部分支持以下 JOIN 语法： 1. table_references: 2. escaped_table_reference [, escaped_table_reference] ... 3. 4. escaped_table_reference: { 5. table_reference 6. | { OJ table_reference } 7. } 8. 9. table_reference: { 10. table_factor 11. | joined_table 12. } 13. 14. table_factor: { 15. tbl_name [PARTITION (partition_names)] 16. [[AS] alias] [index_hint_list] 17. | [LATERAL] table_subquery [AS] alias [(col_list)] 18. | ( table_references ) 19. } 20. 21. joined_table: { 22. table_reference {[INNER | CROSS] JOIN | STRAIGHT_JOIN} table_factor

今天在Ubuntu下的部署项目，发现一些好好的列表页面发生 1055 :Expression # 11 of SELECT list is not in GROUP BY clause and contains nonaggregated column ' ppm_c.ppm_flow_starting_dealing.status ' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode = only_full_group_by 查了下问题出现的原因： MySQL 5.7.5 及以上功能依赖检测功能。 如果启用了ONLY_FULL_GROUP_BY SQL模式（默认情况下），MySQL将拒绝选择列表，HAVING条件或ORDER BY列表的查询引用在GROUP BY子句中既未命名的非集合列，也不在功能上依赖于它们。 （5.7.5之前，MySQL没有检测到功能依赖关系，默认情况下不启用ONLY_FULL_GROUP_BY。有关5.7.5之前的行为的说明，请参见“MySQL 5.6参考手册”。） 解决方法： 1.临时修改 查询 select @@global .sql_mode 重新设置值 set @@global .sql_mode

安装了mysql5.7，用group by 查询时抛出如下异常 SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'kanxf.o.down_uid' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by 解决办法 第一步 mysql > set global sql_mode='STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION'; 第二步 mysql > set session sql_mode='STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE

IDENTITY Columns is a new feature introduced in Oracle Release 12c to support the American National Standards Institute (ANSI) SQL keyword IDENTITY. Identity Columns are automatically incrementing columns. They simplify application development and migration from other RDBMS to Oracle. This feature make use of a default sequence generator and hence the columns will be assigned an increasing or decreasing integer value from this sequence generator. 1 这种情况，insert不能给id1字段赋值，会自动赋值，例如values (1，'name1')会失败 SQL> create table tab_sql_idnty4 ( id1 number generated by default as identity , name varchar2

Topic SQL Description https://leetcode.com/problems/delete-duplicate-emails/ Write a SQL query to delete all duplicate email entries in a table named Person , keeping only unique emails based on its smallest Id . +----+------------------+ | Id | Email | +----+------------------+ | 1 | john@example.com | | 2 | bob@example.com | | 3 | john@example.com | +----+------------------+ Id is the primary key column for this table. For example, after running your query, the above Person table should have the following rows: +----+------------------+ | Id | Email | +----+------------------+ | 1 | john

mysql的版本 mysql> select version(); +-----------+ | version() | +-----------+ | 8.0.12 | +-----------+ 在执行group by时遇到报错，具体如下 mysql> select * from api_properties GROUP BY file_id order by file_id; 1055 - Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'bim.api_properties.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by 记得上次在5.7下也遇到了同样的问题 5.7的 win下修改my.ini，添加 sql_mode=STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO, NO_AUTO_CREATE_USER,NO_ENGINE

场景： 使用gurobi求解优化问题时，遇到quicksum()函数用法如下： quicksum(mu[i] for i in range(n)) 读着很流畅而且好像并没什么问题欸，但 mu[i] for i in range(n) 返回的又是什么？ 看了下quicksum()函数的介绍： def quicksum(p_list): # real signature unknown; restored from __doc__ """ ROUTINE: quicksum(list) PURPOSE: A quicker version of the Python built-in 'sum' function for building Gurobi expressions. ARGUMENTS: list: A list of terms. RETURN VALUE: An expression that represents the sum of the input arguments. EXAMPLE: expr = quicksum([x, y, z]) expr = quicksum([1.0, 2*y, 3*z*z]) """ pass 所以，上述代码返回的是个list？ python console中试了下： x = [1,2,3 ] print (x[i] for i

1.MySQL管理 1.1启动和关闭服务 # Linux service mysqld start # 启动 service mysqld stop # 关闭 service mysql restart # 重启 # Windows net start mysql # 启动 net stop mysql # 关闭 1.2常用命令 登录 mysql -u root -p[密码] [-P端口] [-h地址] USE 数据库名 列出 MySQL 数据库管理系统的数据库列表 mysql> USE sql_test; Database changed SHOW DATABASES: 列出 MySQL 数据库管理系统的数据库列表 mysql> SHOW DATABASES; +--------------------+ | Database | +--------------------+ | information_schema | | mysql | | performance_schema | | sys | +--------------------+ 4 rows in set (0.00 sec) SHOW TABLES: 显示指定数据库的所有表，使用该命令前需要使用 use 命令来选择要操作的数据库 mysql> SHOW TABLES; +-------------------

解决[Err] 1055 - Expression #1 of ORDER BY clause is not in GROUP BY clause 的问题 MySQL 参考文章： （1）解决[Err] 1055 - Expression #1 of ORDER BY clause is not in GROUP BY clause 的问题 MySQL （2）https://www.cnblogs.com/xpx951201/p/11208978.html 备忘一下。 来源： oschina 链接： https://my.oschina.net/u/4428122/blog/4750180

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