circular-list

Why exactly do we need a "Circular Linked List" (singly or doubly) data structure? What problem does it solve that is evident with simple Linked Lists (singly or doubly)? A simple example is keeping track of whose turn it is in a multi-player board game. Put all the players in a circular linked list. After a player takes his turn, advance to the next player in the list. This will cause the program to cycle indefinitely among the players. To traverse a circular linked list, store a pointer to the first element you see. When you see that element again, you have traversed the entire list. void

I have a list of lists which contains the lower and upper limit of sets of angles something like [[1,22],[2,24]...[359,15],[360,21]] 360 elements in total Now I want to check for each angle from 1 to 360 the elements in the list that contains that angle I was thinking about using the lower and upper limits to create all the elements of the list with range or np.arange(lower,upper) and check if the angle is contained, but np.arange generates empty list when lower is higher than upper for i in range(1,361): sel=[] for coe in coef: if i in range(coe[0],coe[1]): sel.append(coe) I tried also with

I need iterate through a List but circular way. I need too add new elements to the list and iterate over all elements (olds and news elements), How I do it? Is there any data structure for them? I think maybe this is what you want; the ability to add new elements to your list even as you are iterating it. The code is ugly but it seems to work. import scala.collection.mutable.Queue class Circular[A](list: Seq[A]) extends Iterator[A]{ val elements = new Queue[A] ++= list var pos = 0 def next = { if (pos == elements.length) pos = 0 val value = elements(pos) pos = pos + 1 value } def hasNext =

This is an assignment. I have to create a circular linked list and remove every third number in the list. When my program reaches the end of the list it should go back to the head and continue the process until only one number remains. I've searched online and some other reference books but couldn't solve my problem. Most of the references that I've found say things such as: Beside the fact that circular lists have no end, they are quite the same as regular lists or (taken from my textbook): A singly-linked list is circularly linked if the successor of the last node is the first But these don

So my program has a need of a type of circular ArrayList. Only circular thing about it has to be the get(int index) method, this is the original: /** * Returns the element at the specified position in this list. * * @param index index of the element to return * @return the element at the specified position in this list * @throws IndexOutOfBoundsException {@inheritDoc} */ public E get(int index) { rangeCheck(index); return elementData(index); } If index is -1 it should get the element with index ArrayList.size()-1 and if index is ArrayList.size(), it should get the element with index 0.

I am working using a visual programming environment for musical composition based on CL . I am trying to create a function that when given say 3 elements (1 2 3) will return 1, 2, 3, 1, 2, 3 etc., one number at the time each time it is evaluated. The book Common Lisp a Gentle Introduction , mentions briefly that it's possible to create circular lists using sharp-equal notation but does not get into details on how to use them. Keep in mind that I can insert actual Lisp code in the program using a object specifically designed for that. CL-USER 3 > (defun circular (items) (setf (cdr (last items))