cidr

Given a CIDR address, e.g. 192.168.10.0/24 How to determine mask length? ( 24 ) How to determine mask address? ( 255.255.255.0 ) How to determine network address? ( 192.168.10.0 ) Yuriy It is covered by apache utils. See this URL: http://commons.apache.org/proper/commons-net/apidocs/org/apache/commons/net/util/SubnetUtils.html String subnet = "192.168.0.3/31"; SubnetUtils utils = new SubnetUtils(subnet); utils.getInfo().isInRange(address) Note: For use w/ /32 CIDR subnets, for exemple, one needs to add the following declaration : utils.setInclusiveHostCount(true); This is how you would do it

I'm looking for quick/simple method for matching a given IP4 dotted quad IP to a CIDR notation mask. I have a bunch of IPs I need to see if they match a range of IPs. example: $ips = array('10.2.1.100', '10.2.1.101', '10.5.1.100', '1.2.3.4'); foreach ($ips as $IP) { if (cidr_match($IP, '10.2.0.0/16') == true) { print "you're in the 10.2 subnet\n"; } } What would cidr_match() look like? It doesn't really have to be simple, but fast would be good. Anything that uses only built-in/common functions is a bonus (as I'm likely to get one person to show me something in pear that does this, but I can't

Given an ip address (say 192.168.0.1), how do I check if it's in a network (say 192.168.0.0/24) in Python? Are there general tools in Python for ip address manipulation? Stuff like host lookups, ip adddress to int, network address with netmask to int and so on? Hopefully in the standard Python library for 2.5. This article shows you can do it with socket and struct modules without too much extra effort. I added a little to the article as follows: import socket,struct def makeMask(n): "return a mask of n bits as a long integer" return (2L<<n-1) - 1 def dottedQuadToNum(ip): "convert decimal