char

How do I add String to a char array?

给你一囗甜甜゛ 提交于 2021-01-07 00:55:06
问题 public static void main (String[] args) { char[][] c = {{'a', 'b', 'c'}, {'d', 'e', 'f'}}; show(c); } public static void show (char[][] c) { for (int i = 0; i < c.length; i++) { System.out.println(c[i]); I want a space between each letter. I tried to write + " " after c[i] but then I get this warning: "Must explicitly convert the char[] to a String". How I am supposed to add a string to my array? Thanks in advance! 回答1: Right now what you are doing wrong is, you are printing each sub-array. I

how to replace character in string

可紊 提交于 2021-01-04 06:37:50
问题 int main(){ char* str = "bake", *temp = str; char alpha [] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'}; for (int i = 0 ; temp[i] != '\0'; i++) { for (int j = 0; alpha[j] != '\0'; j++) { temp[i] = alpha[j]; printf("%s\n",temp); } temp = str; } return 0; } Why am I trying to replace a character in a particular location it falls to me? i want it print me like that i = 0 (index 0 he change only the first char). aake bake cake dake ..

How do I check if a string contains a certain character?

拥有回忆 提交于 2020-12-26 08:16:47
问题 I'm fairly new to C programming, how would I be able to check that a string contains a certain character for instance, if we had: void main(int argc, char* argv[]){ char checkThisLineForExclamation[20] = "Hi, I'm odd!" int exclamationCheck; } So with this, how would I set exclamationCheck with a 1 if "!" is present and 0 if it's not? Many thanks for any assistance given. 回答1: By using strchr(), like this for example: #include <stdio.h> #include <string.h> int main(void) { char str[] = "Hi, I

Converting chars (Casting vs. .getNumericValue)

寵の児 提交于 2020-12-25 05:25:20
问题 Why is it that casting (int) can convert chars of a symbol to int properly, but "Character.getNumericValue('someSymbolCharValue');" can't? E.g. "Character.getNumericValue('?');" will return -1 even though the char can be presented as int with " (int) '?' " where it will return 63 回答1: A character's "numeric value" is not its ASCII/Unicode index value. The Character.getNumericValue method will attempt to convert the char to an int by applying the character's numeric meaning: Returns the int

Converting chars (Casting vs. .getNumericValue)

对着背影说爱祢 提交于 2020-12-25 05:21:38
问题 Why is it that casting (int) can convert chars of a symbol to int properly, but "Character.getNumericValue('someSymbolCharValue');" can't? E.g. "Character.getNumericValue('?');" will return -1 even though the char can be presented as int with " (int) '?' " where it will return 63 回答1: A character's "numeric value" is not its ASCII/Unicode index value. The Character.getNumericValue method will attempt to convert the char to an int by applying the character's numeric meaning: Returns the int

How to prevent Safari from implicitly converting character in XHR request?

时光毁灭记忆、已成空白 提交于 2020-12-15 05:25:31
问题 I picked this character 〉 as a separator for my combo-key-field for my DynamoDb database. That character surfaces in the browser as part of a next-page-query token. (in an endless scroll list view) Chrome properly sends that character to the backend (as part of the next-page-query token). However, Safari, sends that character as this character: 〉 , which is different, and as a result, my backend is unable to recognise it. Why is the browser changing the character? Is this behaviour expected?

printing a char pointer … what happens?

别来无恙 提交于 2020-12-05 10:56:31
问题 i'm new to C and i've got a question about char pointers and what it will print . take a look : int main() { char *p1="ABCD"; p1="EFG"; printf ("%s",p1); return 0; } it will print EFG and now : int main() { char *p1="ABCD"; //p1="EFG"; printf ("%s",p1); return 0; } and it will give you ABCD The point that I don't get is what exactly *p1 is ? Is it a number of an address that contains a char value ? Is it a char ? what is in *p1 right now ? Why is it const ? 回答1: From the C Standard: http:/

How can i convert a uint32_t to a char* type

偶尔善良 提交于 2020-12-05 07:25:46
问题 Hello i am using an Arduino UNO with an adafruit shield to display score values but the function used to display scores only accepts char* values and the score itself can occupy up to 6 digits(000,000 to 999,999). i have tried using sprint() but i have had no luck since the screen will flicker like crazy. i believe the problem to be that chars only hold a certain number of bytes that could not fit a 32 bit int but i would think their is a way around this. draw text is the function used by the

How can i convert a uint32_t to a char* type

扶醉桌前 提交于 2020-12-05 07:24:38
问题 Hello i am using an Arduino UNO with an adafruit shield to display score values but the function used to display scores only accepts char* values and the score itself can occupy up to 6 digits(000,000 to 999,999). i have tried using sprint() but i have had no luck since the screen will flicker like crazy. i believe the problem to be that chars only hold a certain number of bytes that could not fit a 32 bit int but i would think their is a way around this. draw text is the function used by the

How can i convert a uint32_t to a char* type

拥有回忆 提交于 2020-12-05 07:24:32
问题 Hello i am using an Arduino UNO with an adafruit shield to display score values but the function used to display scores only accepts char* values and the score itself can occupy up to 6 digits(000,000 to 999,999). i have tried using sprint() but i have had no luck since the screen will flicker like crazy. i believe the problem to be that chars only hold a certain number of bytes that could not fit a 32 bit int but i would think their is a way around this. draw text is the function used by the