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问题 Howard Chu writes: In the latest C spec it is impossible to write a "legal" implementation of malloc or memcpy. Is this right? My impression is that in the past, the intent (at least) of the standard was that something like this would work: void * memcpy(void * restrict destination, const void * restrict source, size_t nbytes) { size_t i; unsigned char *dst = (unsigned char *) destination; const unsigned char *src = (const unsigned char *) source; for (i = 0; i < nbytes; i++) dst[i] = src[i];

问题 I came across a part of question in which, I am getting an output, but I need a explanation why it is true and does work? char arr[4]; strcpy(arr,"This is a link"); printf("%s",arr); When I compile and execute, I get the following output. Output: This is a link 回答1: The short answer why it worked (that time) is -- you got lucky. Writing beyond the end of an array is undefined behavior . Where undefined behavior is just that, undefined , it could just a easily cause a segmentation fault as it

问题 My code is this: string dex = "ABCD1234"; string ch = "C"; string ch1, ch2; if (dex.Contains(ch)) { string n = Convert.ToChar(dex); MessageBox.Show(ch + " is on " + n + " place and is between " + ch1 + " and " + ch2); } I wanted to convert the string into array but i can't do it and i can't retrieve the position of the 'ch' string and what's between it. The output should be: MessageBox.Show("C is on 3rd place and is between B and D"); 回答1: string aS = "ABCDEFGHI"; char ch = 'C'; int idx = aS

问题 My code is this: string dex = "ABCD1234"; string ch = "C"; string ch1, ch2; if (dex.Contains(ch)) { string n = Convert.ToChar(dex); MessageBox.Show(ch + " is on " + n + " place and is between " + ch1 + " and " + ch2); } I wanted to convert the string into array but i can't do it and i can't retrieve the position of the 'ch' string and what's between it. The output should be: MessageBox.Show("C is on 3rd place and is between B and D"); 回答1: string aS = "ABCDEFGHI"; char ch = 'C'; int idx = aS

问题 I'm declaring character array as char* string. And then I declare other pointer which again refer to original string, then when I'm going to change any thing on that string, at runtime program throws segmentation fault. #include <string.h> #include <ctype.h> int main(void) { char* s = "random"; char* t = s; *t = 'R'; // ----> Segmentation fault t[0] = toupper(t[0]); // ----> Segmentation fault *s = 'R'; // ----> Segmentation fault s[0] = 'R'; // ----> Segmentation fault printf("s is : %s ,

问题 I'm declaring character array as char* string. And then I declare other pointer which again refer to original string, then when I'm going to change any thing on that string, at runtime program throws segmentation fault. #include <string.h> #include <ctype.h> int main(void) { char* s = "random"; char* t = s; *t = 'R'; // ----> Segmentation fault t[0] = toupper(t[0]); // ----> Segmentation fault *s = 'R'; // ----> Segmentation fault s[0] = 'R'; // ----> Segmentation fault printf("s is : %s ,

问题 This question already has answers here : uint8_t can't be printed with cout (8 answers) Closed 5 years ago . I am trying to create an array of 1 byte values, using unsigned chars to hold the values. my code looks like this: unsigned char state[4][4] = { {0xd4, 0xe0, 0xb8, 0x1e}, {0xbf, 0xb4, 0x41, 0x27}, {0x5d, 0x52, 0x11, 0x98}, {0x30, 0xae, 0xf1, 0xe5}}; Where each value is 2 hex digits which makes a byte. However, when I attempt to print the array out using cout << "\nInitial State \n-----

问题 This question already has answers here : uint8_t can't be printed with cout (8 answers) Closed 5 years ago . I am trying to create an array of 1 byte values, using unsigned chars to hold the values. my code looks like this: unsigned char state[4][4] = { {0xd4, 0xe0, 0xb8, 0x1e}, {0xbf, 0xb4, 0x41, 0x27}, {0x5d, 0x52, 0x11, 0x98}, {0x30, 0xae, 0xf1, 0xe5}}; Where each value is 2 hex digits which makes a byte. However, when I attempt to print the array out using cout << "\nInitial State \n-----

问题 I want to compare a character in a string with the letter "R". So I want to check if the character on the position i in the string is a "R", a "L" or a "F". This is my code, but it doesn't word... I'm a Java beginner and really happy about every idea to improve my code and makes it work. for (int i = s.length()-2; i >= 0; i--){ if (s.charAt(i) == "R"){ s = s + "L";} else if (s.charAt(i) == L){ s = s + "R";} else {s = s + "F";} // s = s + s.charAt(i); }//for By the way, the complete exercise

问题 I want to compare a character in a string with the letter "R". So I want to check if the character on the position i in the string is a "R", a "L" or a "F". This is my code, but it doesn't word... I'm a Java beginner and really happy about every idea to improve my code and makes it work. for (int i = s.length()-2; i >= 0; i--){ if (s.charAt(i) == "R"){ s = s + "L";} else if (s.charAt(i) == L){ s = s + "R";} else {s = s + "F";} // s = s + s.charAt(i); }//for By the way, the complete exercise