cdr

How can write a program in scheme to find factors of a list of numbers

由 匆匆过客 提交于 2021-02-05 12:25:33
问题 This is the code for a single integer, how can it extends to list of function? (define (factors n) (define (*factors d) (cond ((> d n) (list)) ((= (modulo n d) 0) (cons d (*factors (+ d 1)))) (else (*factors (+ d 1))))) (*factors 1)) (display (factors 1111111)) (newline) 回答1: You can use for-each to iterate over a list. (define (factors n) (define (*factors d) (cond ((> d n) (list)) ((= (modulo n d) 0) (cons d (*factors (+ d 1)))) (else (*factors (+ d 1))))) (*factors 1)) (define arbitarily

How can write a program in scheme to find factors of a list of numbers

由 倖福魔咒の 提交于 2021-02-05 12:22:35
问题 This is the code for a single integer, how can it extends to list of function? (define (factors n) (define (*factors d) (cond ((> d n) (list)) ((= (modulo n d) 0) (cons d (*factors (+ d 1)))) (else (*factors (+ d 1))))) (*factors 1)) (display (factors 1111111)) (newline) 回答1: You can use for-each to iterate over a list. (define (factors n) (define (*factors d) (cond ((> d n) (list)) ((= (modulo n d) 0) (cons d (*factors (+ d 1)))) (else (*factors (+ d 1))))) (*factors 1)) (define arbitarily

Bouncy Castle example for encoding CDR

由 邮差的信 提交于 2019-12-25 05:20:07
问题 I am trying to encode PGWRecord CDR using ASN.1 notation, starting on page 89 in this 3GPP TS Document I've been looking for awhile for examples how I can do this, but to no avail. Are there any examples that can show me how to do this using Bouncy Castle ? Or is there a better alternative than Bouncy Castle to encode this CDR? Step by step instructions on how I can do this would be very nice! Any help would be very appreciated. Thanks all! 回答1: Try to look at BinaryNotes. You have ASN.1

Asterisk 13.4 cdr engine is creating 2 records per call

由 ◇◆丶佛笑我妖孽 提交于 2019-12-23 23:07:04
问题 This is really starting to get annoying. I´m using Asterisk 1.4 since 2007 to operate a flawless PBX, and it creates a SINGLE CDR per call, like any other version of asterisk would. Yesterday I figured an upgrade would be ok and got Asterisk 13.4. This damn thing is creating 2 CDRs per call... one representing the dial attempt .. and another including both the connected call and the initial dial I don't know where to configure the CDR engine to behave normally... that is, to record A SINGLE

CDR中是否有图层，如何调出图层面板？

由 ぐ巨炮叔叔 提交于 2019-12-20 04:11:57
什么是图层？如果有点PS基础的同学，应该会非常清楚这个概念，它是构成图像的重要组成单位，许多效果可以通过对层的直接操作而得到，并在当前图层操作时候不会影响到其他图层，所以在绘图的过程中有着很重要的作用。很多人问 CorelDRAW 中是否有图层？答案是肯定的，那CDR中的图层在哪呢，为什么不把“图层”摆放在明显的位置？CDR的图层功能在整个软件中不重要么？本文针对CDR中的图层问题做详细讲解。 1. 双击运行CorelDRAW X8，Ctrl+O打开任意绘图文档，并勾选“保持图层和页面”选项。 2. 点击菜单栏“窗口>泊坞窗>对象管理器”命令。 3. 然后，在软件界面的右侧即可看到图层面板。默认状态下，新建的文件都是由页面1和主页面构成；“图层1”指的是默认的局部图层。在页面上绘制对象时，对象将添加到该图层上，除非您选择了另一个图层，如下图所示。 4. 可以从能显示页面、图层或文档中选择对象，同时在对象管理器中也会选中该对象；或者当对象被压落或遮挡，也可以利用对象管理器选择页面中的对象，如图所示。 5.此外， 还可以调整图层顺序。想要调整哪一个对象，直接单击对象名称，拖动对象到合适图层就好。 其实，CDR中的图层功能并不是那么的重要，在做排版、广告的时候很少能够用到，多用于需要导入到PS时为了保留图层，还有一些特别复杂的图或者从Excel导入表格，把表格和文字分别放一个图层。

macOS系统升级

由 佐手、 提交于 2019-12-11 12:16:38
资料 Mac安装系统提示macOS Mojave应用程序副本已损坏,不能用来安装macOS date 102723252015.06 date 1025102018.20 2015年10月27日 星期二 23时25分06秒 PDT 2018年10月25日 星期二 10时20分20秒 PDT 自己制作的 macOS Mojave 10.14.6 iso 文件，亲测可用（附 VMware15 安装 macOS Catalina 图文教程与 macO Catalina.iso 镜像下载地址） 版权声明：本文为博主原创文章，遵循 CC 4.0 BY-SA 版权协议，转载请附上原文出处链接和本声明。 本文链接：https://blog.csdn.net/lijianbiao0/article/details/89212984 终端执行命令： hdiutil create - o ~ / Desktop / Mojave . cdr - size 6 g - layout SPUD - fs HFS + J 解释： 创建一个大小为6G的dmg文件，后面的参数为格式参数，不太清楚，最后一个是文件系统格式（可以不用理会） hdiutil attach ~ / Desktop / Mojave . cdr . dmg - noverify - mountpoint / Volumes /

saving data into custom cdr field

由 我怕爱的太早我们不能终老 提交于 2019-12-07 08:22:25
问题 I created custom field "rec_name" id table "cdr", database "asteriskcdrdb". In this field I want to store recording name. I know I should do it by adding this line in one of .conf files, but where? exten => s,1,set(CDR(rec_name)=${CALLFILENAME}) I can do it by sql statement, too, but I don't know where is the file that saves details of call into database. 回答1: For mysql you need add into /etc/asterisk/cdr_mysql.conf [aliases] rec_name=rec_name If you HAVE aliases section, just add to it rec

saving data into custom cdr field

由 自古美人都是妖i 提交于 2019-12-05 16:13:06
I created custom field "rec_name" id table "cdr", database "asteriskcdrdb". In this field I want to store recording name. I know I should do it by adding this line in one of .conf files, but where? exten => s,1,set(CDR(rec_name)=${CALLFILENAME}) I can do it by sql statement, too, but I don't know where is the file that saves details of call into database. For mysql you need add into /etc/asterisk/cdr_mysql.conf [aliases] rec_name=rec_name If you HAVE aliases section, just add to it rec_name=rec_name 来源： https://stackoverflow.com/questions/10499261/saving-data-into-custom-cdr-field

mysql query - peak concurrent calls CDR data

由 余生长醉 提交于 2019-12-04 01:48:34
问题 Hi I need help working out how to calculate how many peak concurrent calls I have in a day from my CDR date stored in MySQL. The data set looks like this: INSERT INTO `cdr` (`calldate`, `clid`, `src`, `dst`, `dcontext`, `channel`, `dstchannel`, `lastapp`, `lastdata`, `duration`, `billsec`, `disposition`, `amaflags`, `accountcode`, `uniqueid`, `userfield`) VALUES I can user the following query to calculate how many entries there are for each unique date. SELECT COUNT(1) AS entries, date
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