cartesian

问题 I can do this on paper easily enough but have a bit of a mental block in getting this into a language (I'd take any answer but Java probably easiest). I have two sets of points Point A (xA, yA) and Point B (xB, yB). Knowing this, and assuming that these two create a straight line graph I need to be able write a function that will give me xC given that I would know yC (and, obviously that the new point is on the same line). All help appreciated :) Kind Regards 回答1: (yB-yA)/(xB-xA) = (yC - yA)

问题 Decomposing rotation matrix (x,y',z'') - Cartesian angles Im currently working with rotation matrices and I have the following problem: Given three coordinate systems ( O0,x0,y0,z0; O1,x1,y1,z1; O2,x2,y2,z2 ) which coincide. We rotate first the frame #1 with the respect to frame #0, then the frame #2 with respect to frame #1. The order of the rotations: R = Rx_alpha * Ry_beta * Rz_gamma , so first about x , then y' , then z'' , which are also known as the Cartesian angles . If R1 stands for

问题 in Product SKUs, we can get Cartesian Product in the way of LINQ: string[] arr1 = new[] {"red", "blue", "orange"}; string[] arr2 = new[] {"5 inche", "8 inch"}; var result = from a in arr1 from b in arr2 select a + " " + b; foreach (var item in result){ Console.WriteLine(item); } We know the exact number of arrays. My question is: If the number of arrays is dynamic, how do we get Cartesian Product? Thanks. 回答1: I'd put them in a list of string arrays. Then I'd use ForEach : IEnumerable<string>

问题 in Product SKUs, we can get Cartesian Product in the way of LINQ: string[] arr1 = new[] {"red", "blue", "orange"}; string[] arr2 = new[] {"5 inche", "8 inch"}; var result = from a in arr1 from b in arr2 select a + " " + b; foreach (var item in result){ Console.WriteLine(item); } We know the exact number of arrays. My question is: If the number of arrays is dynamic, how do we get Cartesian Product? Thanks. 回答1: I'd put them in a list of string arrays. Then I'd use ForEach : IEnumerable<string>

问题 in Product SKUs, we can get Cartesian Product in the way of LINQ: string[] arr1 = new[] {"red", "blue", "orange"}; string[] arr2 = new[] {"5 inche", "8 inch"}; var result = from a in arr1 from b in arr2 select a + " " + b; foreach (var item in result){ Console.WriteLine(item); } We know the exact number of arrays. My question is: If the number of arrays is dynamic, how do we get Cartesian Product? Thanks. 回答1: I'd put them in a list of string arrays. Then I'd use ForEach : IEnumerable<string>

问题 This question already has answers here : Get the cartesian product of a series of lists? (13 answers) Closed 6 years ago . Suppose we have a list L . The cartesian product L x L could be computed like this: product = [(a,b) for a in L for b in L] How can the cartesian power L x L x L x ... x L (n times, for a given n) be computed, in a short and efficient way? 回答1: Using itertools.product(): product = itertools.product(L, repeat=n) where product is now a iterable; call list(product) if you

问题 I need to define the location of an html element based on the location of a Cesium entity. I've used the mouse position ( Cesium.Cartesian3.clone(movement.endPosition) ), which is in window coordinates, as a test and it works. So I need to get the entity position, transform it to the WGS84 coordinates, transform those to the window coordinates and use them for element.style.left = window_coord.x and element.style.top = window_coord.y . So I get the entity.position and the x, y and z values

问题 I would like to fit a 2D array by an elliptic function: (x / a)² + (y / b)² = 1 ----> (and so get the a and b) And then, be able to replot it on my graph. I found many examples on internet, but no one with this simple Cartesian equation. I probably have searched badly ! I think a basic solution for this problem could help many people. Here is an example of the data: Sadly, I can not put the values... So let's assume that I have an X,Y arrays defining the coordinates of each of those points .

问题 Is there a way to flip the SVG coordinate system so that [0,0] is in the lower left instead of the upper left? 回答1: I have done a lot of experimentation, and the only logical method is as follows: <g transform="translate(0,400)"> <g transform="scale(1,-1)"> Where 400 is the height of the image. What this does it move everything down so that the top of the image is now and the bottom of the image, then the scale operation flips the Y coordinates, so that the bit that is now off the page/image

问题 I'd like to expand my rows by their cross product across multiple lists. The current logic I use is: list = [['Yes', 'No', 'Maybe'], ['Yes', 'No', 'Maybe']] index = pd.MultiIndex.from_product(list, names = ["column1", "column2"]) pd.DataFrame(index = index).reset_index() which unfortunately will not work for more than one list. How would I be able to run the cartesian product of something that looks like this: [[['Yes', 'No', 'Maybe'], ['Yes', 'No', 'Maybe']],[['Yes', 'No', 'Maybe'], ['Yes',